Maths year 11

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    That's wrong. If you want to convert it into cm, then rather than multiplying it by 100, you must multiply it by (100)3 because it's in 3 dimensions, therefore 100 per side.

    You can check this by turning each side into cm FIRST before multiplying them all together. It would be the equivalent of
    V=(2x100)x(2x100)x(2x100) where the 2's multiply by eachother 3 times as well as the 100s -> V=1003 x 23
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    (Original post by z_o_e)
    Yepp changed them to CM

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    You can't convert volumes like that. All because there are 100cm in a meter does not mean that there are 100cm^3 in 1m^3.
    Convert the side lengths of the container and work out the volume in cm^3 that way.
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    (Original post by RDKGames)
    That's wrong. If you want to convert it into cm, then rather than multiplying it by 100, you must multiply it by (100)3 because it's in 3 dimensions, therefore 100 per side.

    You can check this by turning each side into cm FIRST before multiplying them all together.


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    Correct.
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    (Original post by RDKGames)
    Correct.


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    Since the whole thing is a quarter of a circle with radius 4.8cm, you can work out that area to 3 s.f. Furthermore, you can work out the area of the triangle and take one away from the other to find the area of the segment.
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    (Original post by RDKGames)
    Since the whole thing is a quarter of a circle with radius 4.8cm, you can work out that area to 3 s.f. Furthermore, you can work out the area of the triangle and take one away from the other to find the area of the segment.
    How do I find the area of the triangle? :/

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    (Original post by z_o_e)
    How do I find the area of the triangle? :/

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    Well the whole thing is a quarter of a circle; the key here is to realise that it means triangle's sides are both the radius of the circle.
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    Pi * 4.8 squared /2
    ?

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    (Original post by RDKGames)
    Well the whole thing is a quarter of a circle; the key here is to realise that it means triangle's sides are both the radius of the circle.
    So I could do pi *4.8 squared /2?


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    (Original post by z_o_e)
    So I could do pi *4.8 squared /2?


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    Not quite; what would that give you?
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    (Original post by RDKGames)
    Not quite; what would that give you?
    Area of the... semi circle?

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    (Original post by z_o_e)
    So I could do pi *4.8 squared /2?


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    That would be the area of half of the circle you need  4.8\pi /4 = 1.2\pi . But you need to subtract the area of the triangle to get the shaded area of the minor segment.
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    (Original post by z_o_e)
    Area of the... semi circle?

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    Yes that would give you the semi-circle area, but you want a quarter of it.
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    (Original post by B_9710)
    That would be the area of half of the circle you need  4.8\pi /4 = 1.2\pi . But you need to subtract the area of the triangle to get the shaded area of the minor segment.
    That's not quite right...
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    (Original post by RDKGames)
    Yes that would give you the semi-circle area, but you want a quarter of it.
    I could divide that area in 2 to find a quarter.

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    (Original post by z_o_e)
    I could divide that area in 2 to find a quarter.

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    Yep. Though you could've skipped this part by simply dividing the circle's area by 4 directly.
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    (Original post by RDKGames)
    Yep. Though you could've skipped this part by simply dividing the circle's area by 4 directly.


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    That's right. Now you can find the segment's area by taking away the triangle's area.
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    (Original post by RDKGames)
    That's right. Now you can find the segment's area by taking away the triangle's area.
    I didn't get this.

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