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    (Original post by physicsmaths)
    Cant the ans be in a better form like 2^n(n!)^2/(2n+1)!
    This was identical to a reduction given in step III 2015 q 1.
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    I think this is right.

    \displaystyle \frac{2^{n+1}n!(n+1)!}{(2n+2)!}=  \frac{2\cdot 2^n n!(n+1)n!}{(2n+2)(2n+1)!}=\frac{  2^n n! n!}{(2n+1)!}=\frac{2^n(n!)^2}{(2  n+1)!}
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    (Original post by TeeEm)
    39 days to A level results

    Question for Sunday 05/07/15
    AS Level Maths upwards
    Here is my solution. Take n=1 and it shud give 2/3 but your formula gives 1/3. All you are missing is that 2^n+1 should be 2^2n+1. And then you answer simplifies to my one!
    Name:  ImageUploadedByStudent Room1436090242.733018.jpg
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    (Original post by rayquaza17)
    I think this is right.

    \displaystyle \frac{2^{n+1}n!(n+1)!}{(2n+2)!}=  \frac{2\cdot 2^n n!(n+1)n!}{(2n+2)(2n+1)!}=\frac{  2^n n! n!}{(2n+1)!}=\frac{2^n(n!)^2}{(2  n+1)!}
    Yh thats it. I just cant do latex as it wouldve been clearer.


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    (Original post by physicsmaths)
    Yh thats it. I just cant do latex as it wouldve been clearer.


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    maybe there is a typo in my answer. This is my answer also
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    (Original post by TeeEm)
    maybe there is a typo in my answer. This is my answer also
    But do you agree now that your answer simplifies to my one roght?


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    (Original post by TeeEm)
    maybe there is a typo in my answer. This is my answer also
    Also you should steal this Name:  ImageUploadedByStudent Room1436091498.982642.jpg
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    IIT JEE question. Very weird and neat answer.


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    (Original post by physicsmaths)
    But do you agree now that your answer simplifies to my one roght?


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    definitely
    I could not understand what you were saying last night without latex.
    (I refuse to use latex too)
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    (Original post by physicsmaths)
    Also you should steal this Name:  ImageUploadedByStudent Room1436091498.982642.jpg
Views: 153
Size:  18.3 KB
    IIT JEE question. Very weird and neat answer.


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    probably I have it somewhere already.
    by the way the recurrence relation is an old question of mine from my proof by induction sheet and not stolen
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    (Original post by TeeEm)
    probably I have it somewhere already.
    by the way the recurrence relation is an old question of mine from my proof by induction sheet and not stolen
    Oh no i wasnt implying you stole that just you always say 'i shall steal this' so thought this question was nice.
    There are so many questions like that or sinilar that onvolve the even and odd terms like that.


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    (Original post by rayquaza17)
    I think this is right.
    \displaystyle \frac{2^{n+1}n!(n+1)!}{(2n+2)!}=  \frac{2\cdot 2^n n!(n+1)n!}{(2n+2)(2n+1)!}=\frac{  2^n n! n!}{(2n+1)!}=\frac{2^n(n!)^2}{(2  n+1)!}
    (Original post by physicsmaths)
    Here is my solution. Take n=1 and it shud give 2/3 but your formula gives 1/3. All you are missing is that 2^n+1 should be 2^2n+1. And then you answer simplifies to my one!
    Name:  ImageUploadedByStudent Room1436090242.733018.jpg
Views: 143
Size:  129.3 KB
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    the answer is all wrong as I copied and pasted and have not changed the answer...
    I rewrote the question today after I did the solution and did it as a show.
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    (Original post by TeeEm)
    the answer is all wrong as I copied and pasted and have not changed the answer...
    I rewrote the question today after I did the solution and did it as a show.
    My fonal answer is wrong?????


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    (Original post by physicsmaths)
    My fonal answer is wrong?????


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    mine was wrong because I have 2 very similar questions to the one I posted.
    I decided to make a new one, copied and pasted, and forgot to change the answer in the box. I just put the solution up to check yours.
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    38 days to A level results

    Question for Monday 06/07/15
    AS Level Maths upwards
    Attached Images
  1. File Type: pdf Q7, Monday 06-07-15.pdf (9.4 KB, 58 views)
  2. File Type: pdf Q7, Monday 06-07-15, solution.pdf (52.8 KB, 48 views)
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    (Original post by TeeEm)
    the answer is all wrong as I copied and pasted and have not changed the answer...
    I rewrote the question today after I did the solution and did it as a show.
    I never worked through the question, I was just checking if your two answers were the same.
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    37 days to A level results

    Question for Tuesday 07/07/15
    A Level Maths upwards
    Attached Images
  3. File Type: pdf Q8, Tuesday 07-07-15.pdf (14.6 KB, 94 views)
  4. File Type: pdf Q8, Tuesday 07-07-15, solution.pdf (91.1 KB, 54 views)
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    (Original post by TeeEm)
    37 days to A level results

    Question for Tuesday 07/07/15
    AS Level Maths upwards
    This mustve been stolen from aea paper 14....


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    (Original post by physicsmaths)
    This mustve been stolen from aea paper 14....


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    Nope,
    stolen may be but these are standard parametric loci of evolutes, involutes, epicycloids etc which I have tons of examples!
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    (Original post by TeeEm)
    Nope,
    stolen may be but these are standard parametric loci of evolutes, involutes, epicycloids etc which I have tons of examples!
    Ah i see. I had only seen it first time in aea you see.


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    (Original post by physicsmaths)
    Ah i see. I had only seen it first time in aea you see.


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    look at IYGB, C4,

    Paper T, Q6
    Paper S, Q9

    very easy to make for a question maker of my calibre ....
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    (Original post by TeeEm)
    look at IYGB, C4,

    Paper T, Q6
    Paper S, Q9

    very easy to make for a question maker of my calibre ....
    Hi TeeEm,

    Have you got any good resources on Laplace transforms and any of these:

    Probability ( rms, density functions and random variables)
    Central limit theorem
    Regression
    Weibull distribution
    Normal distribution
 
 
 
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