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# AQA Physics PHYA5 - 28th June 2016 [Exam Discussion Thread] watch

1. (Original post by ahlam H)
Did anyone get 2100J and 2500J for the last 2 questions on nuclear physics
What were those questions?

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2. (Original post by ahlam H)
Did anyone get 2100J and 2500J for the last 2 questions on nuclear physics
Yes that's right

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3. (Original post by nnblccz)
Swear I got 1.8x10^11, which is basically the specific charge of an electron

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Same, I got 1.81x10^11. You just re-arrange r=mv/Be solve for e/m
4. (Original post by the_chosen_one97)
Same, I got 1.81x10^11. You just re-arrange r=mv/Be solve for e/m
Or you can use the 2V/B^2r^2 because they gave all data and answer was 1.9*10^11

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Yes that's right

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i think i got them the other way round? wasnt specific heat capacity 2120? and the energy was 2490?
6. (Original post by the_chosen_one97)
Same, I got 1.81x10^11. You just re-arrange r=mv/Be solve for e/m
Erm you didn't have v - the velocity - you had the potential through which they are accelerated

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Or you can use the 2V/B^2r^2 because they gave all data and answer was 1.9*10^11
Yep , I got this

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Yep I got this
8. (Original post by Ac19951)
1.22x10^8 AU for the last question in Astrophysics anyone? I think i forgot to square root my answer.

Also what did you guys write for the first part of the CCD question? Regarding structure.
it was 2.4x10^14 AU
9. Surprisingly not too bad. Think I've made a few mistakes but that was a nice paper regardless
10. 128MeV???????
11. (Original post by aelahi23)
Found the exam to easy quite. I did turning points for optional module

although one question threw me off, the 4 mark question in turning points that asked to find specific charge I got 2.1 * 10^8 what did other people get?

since F=Bev and F= Mv^2/r
I did equated them to each other then rearranged to get
e/m = v/Br

"v" mean velocity
"V" means PD

To find v (velocity) I did v=V/Br

so subbed in the v=V/Br into e/m = v/Br to get rid of velocity from the equation to get e/m= V/Br/Br
which simplified to e/m= V/ B^2 * r^2
Is that correct?

Section A was very easy so I don't have any queries about that
I used the equation eV = 1/2 mv^2
Gave me a velocity of something like 23989839. I then used this in the equation e/m = v/Br and it gave the right answer which is 1.8x10^11.
I think I did it the way you did to begin with but thought it obviously can't be that so changed it.. you should get a mark for the Unit provided you got that right ! Which to be fair is given on the formula sheet lmao
12. (Original post by Sid1234)
it was 2.4x10^14 AU
Me too!! Thank god
13. (Original post by Mango Milkshake)
128MeV???????
YES !
14. I wrote about Rutherford alpha scattering, wbu?
15. (Original post by Mango Milkshake)
128MeV???????
127.24 i got o.O
16. (Original post by cowie)
What were those questions?

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It was about the specfic capacity and latent for ice and water where the ice was raised from -25 to 0 degrees celcius
17. (Original post by txnilxnur)
I used the equation eV = 1/2 mv^2
Gave me a velocity of something like 23989839. I then used this in the equation e/m = v/Br and it gave the right answer which is 1.8x10^11.
I think I did it the way you did to begin with but thought it obviously can't be that so changed it.. you should get a mark for the Unit provided you got that right ! Which to be fair is given on the formula sheet lmao
Both methods will get the marks chill

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18. (Original post by Sid1234)
it was 2.4x10^14 AU
i got this as well
19. anyone can post the solution for turning point ?
20. (Original post by txnilxnur)
I used the equation eV = 1/2 mv^2
Gave me a velocity of something like 23989839. I then used this in the equation e/m = v/Br and it gave the right answer which is 1.8x10^11.
I think I did it the way you did to begin with but thought it obviously can't be that so changed it.. you should get a mark for the Unit provided you got that right ! Which to be fair is given on the formula sheet lmao
No you can't do it that way - you're using the electron charge and mass from the formula booklet which they wouldn't have had at the time! The question made it clear: use THIS data

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