# AQA PHYA4 ~ 13th June 2013 ~ A2 PhysicsWatch

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6 years ago
#681
These answers are making me feel rubbish I found the paper really really difficult and looks like I haven't done very well Annoyed cause I actually tried really hard for this exam all year
4
6 years ago
#682
(Original post by Dirtybit)
Probably said the sattelite was near the earths surface
they actually said that? :O

wow, I must've completed missed it

I guess when I saw the word satellite and instinctively thought it was in space, oh ****
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6 years ago
#683
(Original post by fizzbizz)
What did people get for the final transformers multiple choice question? 460 turns and less than 0.26A?
NO WAY is this right? I guessed last minute
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6 years ago
#684
(Original post by MSI_10)
1500?
Yh thats what I got. Then what are people talking about in the first q saying they got 1500 in q1?

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6 years ago
#685
Positive sine curve yeah? Last

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6 years ago
#686
(Original post by Dirtybit)
Probably said the sattelite was near the earths surface
Yeah it said low polar orbit
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6 years ago
#687
(Original post by Jack93o)
oh yeah, for the induced emf graph, everyone started off at zero, right?

but did you draw it sloping up (to the positive part of the y-axis) in the first quarter of a cycle?
I did this but it's wrong, it should've been sloping down to start with (minus sine)
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6 years ago
#688
(Original post by saba146)
section a: kgms-2, t root2 energy one i got 2E? ...

1a)define shm:
acceleration is proportinal to displacement, and acceleration acts toward equilibrium (2)
b)acceleration of pendulum = 0.503 3s.f (3)
c)frequency= 1500 revs per minute (2)
d) time for oscilations to be in phase again = 38 (3)

2) voltage = 30,000 (1)
b) (3)
c) time taken for discharge will increase because time constant increases (2)
d) flash is brighter because more energy stored (2)

3) 6 marker on fields?

4) 2 conditions when no force is exerted on the partcle (2)
field is parallel to velocity
particle is stationary
b)
c)time taken for partile to go through 1 dee
d)show the time taken is independent of radius = 2pim/bq (3)
kinetic energy im MEV = 2.44 (3)

angle for max emf = (2)
gradient of graph = emf (1)

drawing a graph (2)
peak voltage (3)
calculate flux density = 0.26 (2)
what questions has this person missed out?? this doesn't add up to 50 and I can't remember :/
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6 years ago
#689
For satellite P and Q, P had a greater KE but lower PE so answer was C?
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6 years ago
#690
(Original post by cooldudeman)
Yh thats what I got. Then what are people talking about in the first q saying they got 1500 in q1?

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Oh lol someone mixed it up for the list of Qs posted..

The freq for the 3 marker on Q1 was 0.503 guys the acceleration was -0.4 ish!

Not 1500 lol that was for the last q
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6 years ago
#691
(Original post by MSI_10)
For satellite P and Q, P had a greater KE but lower PE so answer was C?
Yup
1
6 years ago
#692
(Original post by fizzbizz)
I did this but it's wrong, it should've been sloping down to start with (minus sine)
you sure? why?
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6 years ago
#693
(Original post by cooldudeman)
Positive sine curve yeah? Last

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Started at 0, EMF was max when linkage was 0, probs wrong though..
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6 years ago
#694
What did everyone get for question 24 on the multi choice about the rod moving in a magnetic field?
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6 years ago
#695
shouldn't it be -sinx?
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6 years ago
#696
(Original post by MSI_10)
Oh lol someone mixed it up for the list of Qs posted..

The freq for the 3 marker on Q1 was 0.503 guys the acceleration was -0.4 ish!

Not 1500 lol that was for the last q
Theres me thinking I lost 6 marks.
I got 0.503 too. Thats 3sf right?

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6 years ago
#697
(Original post by cooldudeman)
Theres me thinking I lost 6 marks.
I got 0.503 too. Thats 3sf right?

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I also put that
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6 years ago
#698
(Original post by Jack93o)
you sure? why?
Because of Lenz's law - induced emf always in the opposite direction

You could also think of it as being the gradient of the flux linkage curve which was -cos:

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6 years ago
#699
(Original post by Serpentine111)
I think it would be brighter because there is more energy stored?
i said that !!!!!!!!1
0
6 years ago
#700
(Original post by The H)
shouldn't it be -sinx?
yes, I'm pretty sure it should be
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