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    (Original post by SeanFM)
    Think of definitions and what points on box plots represent.
    So Q1 = 30 therefore its 30 for A and for b Q3 = 46 so its 46 for B?
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    (Original post by imran_)
    show ur working please
    so I worked out how many people between 1.5 and 3.5
    so 1.5 + ?/15*3 = 3.5
    rearrange for ? = 10
    but you want above 3.5 so 15-10=5
    Then you will also include the 9 in the next group as they are between the time limit

    Then interpolate again to find those between 6.5 and 7
    so 6.5 + ?/6 *1 =7
    ?=3

    5+9+3=17

    Not sure if you're gonna understand this method but that's how I do it.
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    (Original post by not_lucas1)
    So Q1 = 30 therefore its 30 for A and for b Q3 = 46 so its 46 for B?
    See, you knew how to answer them already :borat:
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    For the equation y = a + bx what does a represent? is it the y intercept ?
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    Which is the hardest S3 paper??
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    for jan 2009 Q4a why don't you use n/2 to calculate the median etc
    The answers were:
    Q2=53
    Q1=35
    Q3=60
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    Do we need to know about explanatory variables????
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    (Original post by not_lucas1)
    For the equation y = a + bx what does a represent? is it the y intercept ?
    of the regression line yes
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    (Original post by ChilliLemon)
    Do we need to know about explanatory variables????
    Yes, they often come up
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    (Original post by tazza ma razza)
    Wicked Mate - see you at Warwick next year
    Hopefully not.
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    (Original post by SANTR)
    Ok, suppose the value was 0.8010 and not on either table, how would you determine the Z value?
    Using the normal table...
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    (Original post by 4nonymous)
    so I worked out how many people between 1.5 and 3.5
    so 1.5 + ?/15*3 = 3.5
    rearrange for ? = 10
    but you want above 3.5 so 15-10=5
    Then you will also include the 9 in the next group as they are between the time limit

    Then interpolate again to find those between 6.5 and 7
    so 6.5 + ?/6 *1 =7
    ?=3

    5+9+3=17

    Not sure if you're gonna understand this method but that's how I do it.
    Yes, a third of the first bit, all the second, then half of the 6.
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    (Original post by Zacken)
    Using the normal table...
    But 0.8010 isn't on the table, there's 0.7950 or 0.8023?
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    (Original post by Mr T Pities You)
    Yes, a third of the first bit, all the second, then half of the 6.
    lol. I managed to get the right answer at least and I've done a similar type question using the same method and it worked
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    (Original post by SANTR)
    But 0.8010 isn't on the table, there's 0.7950 or 0.8023?
    Whichever is closest. However, the exact reason you don't get asked for those values is because they're not on the table.
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    Anyone kind enough to give me the link to S1 IAL jan 15 paper?
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    (Original post by mollie1711)
    I'm having a last minute panic about quartiles, if n/4, n/2 etc is a whole number eg 5 would you use 5.5th number?
    Yep, and if you get a decimal round up and use that value.
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    (Original post by SANTR)
    But 0.8010 isn't on the table, there's 0.7950 or 0.8023?
    round to the nearest one so use the z value for whatever 0.8023 is
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    (Original post by SANTR)
    But 0.8010 isn't on the table, there's 0.7950 or 0.8023?
    Not quite sure if you understand how the tables work, I think you should try figure out a way of using them that works for you, maybe a bit late now
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    (Original post by Mr T Pities You)
    Yep, and if you get a decimal round up and use that value.
    So if the Q is a whole number you add 0.5 and use the mean of the values its between? and if its a rational number you round it and use that specific number?
 
 
 
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