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    (Original post by Grindle97)
    What was the question to which people got the answers 25 and 0? What did it ask you to do?
    It was the weird sum of question. Question 2 I think.

    It gave you a list of functions to do to get to r n+1. It then gave you a=5 for part i) and a=6 for part ii)

    You then had to find the sum of the sequence between 2nd and 4th terms

    I think anyway...
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    (Original post by Dowel)
    you times indices across brackets giving you 3m
    But it wasn't brackets. It was the log function.

    If it was (a^m)^3 then you could. But this was log(a^m)^3. The brackets is part of the log so you can't times the indices like you would normally.
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    Everyone's saying that it was a hard paper. Everyone's complaining about the f(h+5) question. But if you actually revised properly and actually put in the effort, you could have answered these "impossible questions". You'll get the grade you deserve.
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    When solving the trig question, did everyone put 360 as well as one of the solutions was 0 so wouldn't you add 360 on to that? I know there where more solutions too...Just wondering about the one what =0...
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    (Original post by AdamWallisjr)
    When solving the trig question, did everyone put 360 as well as one of the solutions was 0 so wouldn't you add 360 on to that? I know there where more solutions too...Just wondering about the one what =0...
    Got 0, 180, 14.5, 165.5
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    (Original post by AdamWallisjr)
    When solving the trig question, did everyone put 360 as well as one of the solutions was 0 so wouldn't you add 360 on to that? I know there where more solutions too...Just wondering about the one what =0...
    the value came out at 14. something. You then take that away from 360 to find the other value.
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    (Original post by Crozzer24)
    The log graph was awful, felt impossible to draw a best line of fit, ended up with y intercept of 0.6 and gradient 0.2 which seems way off
    I got the same but 0.65 instead, no biggie. It's probably right
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    log_a(a) = 1 is correct.
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    (Original post by Lucuniexet)
    the value came out at 14. something. You then take that away from 360 to find the other value.
    You take it away from 180
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    (Original post by Mr Moon Man)
    You're supposed to end up with 5 values
    which were what?!
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    (Original post by Lucuniexet)
    which were what?!
    0,180,360, 14 something, and 180- 14 something
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    (Original post by Mr Moon Man)
    0,180,360, 14 something, and 180- 14 something
    0, 180, 14.5, 165.5

    Sine is only positive in two quadrants so the max results you could get is 4
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    (Original post by Akhawais)
    0, 180, 14.5, 165.5

    Sine is only positive in two quadrants so the max results you could get is 4
    swear its only 2 values? because if i did it right i got 4sinx - 1 = 0

    so isn't it just sin^-1 25

    or is there another step i missed? x
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    (Original post by Akhawais)
    0, 180, 14.5, 165.5

    Sine is only positive in two quadrants so the max results you could get is 4
    Depends what the limits were. Was the upper limit <360 or was it <=360?
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    (Original post by ScalyJake)
    Depends what the limits were. Was the upper limit <360 or was it <=360?
    450
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    (Original post by ScalyJake)
    Depends what the limits were. Was the upper limit <360 or was it <=360?
    It was <=360
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    Unofficial mark scheme anyone?
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    (Original post by ScalyJake)
    Depends what the limits were. Was the upper limit <360 or was it <=360?
    Honestly can't remember. If it was <= 360 then there would be 5 values, but I'm pretty sure it was < 360
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    (Original post by Akhawais)
    0, 180, 14.5, 165.5

    Sine is only positive in two quadrants so the max results you could get is 4
    You do 180-0. And also, 360+0.
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    (Original post by mrashid98)
    Unofficial mark scheme anyone?
    There's one a few pages back
 
 
 
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