Edexcel A2 C3 Mathematics 12th June 2015 Watch

This discussion is closed.
samb1234
Badges: 13
Rep:
?
#721
Report 3 years ago
#721
(Original post by pearl_rose)
I don't follow :[
Sin(x+a) is exactly the same as sin(a+b) with x as a and alpha as b. You can therefore use the normal formula to expand it

Posted from TSR Mobile
0
aersh8
Badges: 14
Rep:
?
#722
Report 3 years ago
#722
(Original post by samb1234)
You would risk losing marks. No point in doing that really not like it takes long to write it out (especially if you made a stupid mistake you would get 0)

Posted from TSR Mobile
I've never done it any other way (so don't even know how I should write it out), and I always plug in some numbers to check whether I get the same answer...

Posted from TSR Mobile
0
pearl_rose
Badges: 16
Rep:
?
#723
Report 3 years ago
#723
(Original post by samb1234)
Sin(x+a) is exactly the same as sin(a+b) with x as a and alpha as b. You can therefore use the normal formula to expand it

Posted from TSR Mobile
Ohhh haha thanks
0
aersh8
Badges: 14
Rep:
?
#724
Report 3 years ago
#724
(Original post by samb1234)
You would risk losing marks. No point in doing that really not like it takes long to write it out (especially if you made a stupid mistake you would get 0)

Posted from TSR Mobile
Just checked the 2013 and 2014 mark schemes - the method marks are given for what I do (r^2 = coefficient ^2 + coefficient ^2 and tana = (coefficient/coefficicient) so I guess it's fine
0
samb1234
Badges: 13
Rep:
?
#725
Report 3 years ago
#725
(Original post by aersh8)
Just checked the 2013 and 2014 mark schemes - the method marks are given for what I do (r^2 = coefficient ^2 + coefficient ^2 and tana = (coefficient/coefficicient) so I guess it's fine
Then you'll be fine then. Both methods are correct I just tend to write it out as I have enough time and means I am more careful (I obviously plug numbers in as well just to be safe)

Posted from TSR Mobile
0
pearl_rose
Badges: 16
Rep:
?
#726
Report 3 years ago
#726
(Original post by samb1234)
Rsin(x+a) expand sin(x+a) and do coefficient matching eg if you had 7sinx + 4cosx then when you expand rsin(x+a) you would get Rsinxcosa +rsinacosx. By matching the coefficients of the two, you can say that rcosa =7 and rsina=4. Then you can divide the two to get tan a. R is basically coefficient if sin squared plus coefficient of cos squared all rooted. For us it normally tells you its positive but just be careful as it could be -ve. To get the two identities you just divide by either sin^2 or cos^2

Posted from TSR Mobile
Ok so all in all which identities do you think you need to have memorized and that you can't derive from the formula sheet? Thxx
0
Efemena15
Badges: 4
Rep:
?
#727
Report 3 years ago
#727
I hope we're not asked to draw graphs of cot, sec or cosec
2
randlemcmurphy
Badges: 10
Rep:
?
#728
Report 3 years ago
#728
(Original post by Efemena15)
I hope we're not asked to draw graphs of cot, sec or cosec
I'm more worried about being asked to draw the graphs of arcsin, arccos and arctan and having to remember the domain and range for each graph.
0
Kevin De Bruyne
Badges: 21
Rep:
?
#729
Report 3 years ago
#729
(Original post by randlemcmurphy)
I'm more worried about being asked to draw the graphs of arcsin, arccos and arctan and having to remember the domain and range for each graph.
Remember that for drawing those you can't have the same y value pop up on the graph twice, and that arcsin, arccos and arctan are the inverse functions of sin, cos and tan. So for arcsin and arccos the domain, i.e what you put in, will be between 1 and -1. This makes sense because the range of sin and cos are -1 and 1. The range is the domain of sin and cos, so at -1 it'll be -pi/2 and -pi respectively, and at 1 it will be pi/2 and 0 respectively. I can't remember much about arctan but I vaguely remember the shape of the graph and it shouldn't be too difficult.
0
cerlohee
Badges: 16
Rep:
?
#730
Report 3 years ago
#730
Hi everyone, so I'm having trouble with this question: http://gyazo.com/1f59f436bde2776d6d038bd313fc4e39
For part C, I have worked out that b is 6, how do I then go onto work out A? I got 1/5th... Thanks
0
samb1234
Badges: 13
Rep:
?
#731
Report 3 years ago
#731
(Original post by cerlohee)
Hi everyone, so I'm having trouble with this question: http://i.gyazo.com/90da8d80d402473cdbbd213855aedf55.png
I have worked out that b is 6, how do I then go onto work out A? Thanks

ALSO this question: http://i.gyazo.com/893eaaf9bd27c4b0a02a8512344a0a6c.png
I got a max value of 1.107 by making 100sinsq(theta-1.107)=0??
I'm sorry I need to do some revision for chemistry otherwise I would do it for you. Just some advice, it would help if you posted the full questions as you can only see the specific part of the question, not the rest of it (or is that just me?)

Posted from TSR Mobile
0
MiloHVLeonard
Badges: 1
Rep:
?
#732
Report 3 years ago
#732
Hey guys,
Do we need to know proof by contradiction, exhaustion, and counter example?
One of my friends said he saw it in his CGP book, and I saw proof by counter example in a solomon paper, but it says nothing on the spec
I'm pretty sure that we don't need to know, but I just want to make sure
Does anyone know?
Thanks
0
cerlohee
Badges: 16
Rep:
?
#733
Report 3 years ago
#733
(Original post by samb1234)
I'm sorry I need to do some revision for chemistry otherwise I would do it for you. Just some advice, it would help if you posted the full questions as you can only see the specific part of the question, not the rest of it (or is that just me?)

Posted from TSR Mobile
Ah sorry no wonder I've had no replies!
Have fixed it now if anyone can help out. Have fun with chemistry
0
s.c.a1
Badges: 8
Rep:
?
#734
Report 3 years ago
#734
can someone pls help me with this question. why is part b a quadratic equation?? why cant i just ln the whole thing
0
yelllowribbon
Badges: 12
Rep:
?
#735
Report 3 years ago
#735
(Original post by MiloHVLeonard)
Hey guys,
Do we need to know proof by contradiction, exhaustion, and counter example?
One of my friends said he saw it in his CGP book, and I saw proof by counter example in a solomon paper, but it says nothing on the spec
I'm pretty sure that we don't need to know, but I just want to make sure
Does anyone know?
Thanks
Pretty sure we don't need it...but yeah check with someones else, or on the spec
0
studentwiz
Badges: 3
Rep:
?
#736
Report 3 years ago
#736
(Original post by s.c.a1)
can someone pls help me with this question. why is part b a quadratic equation?? why cant i just ln the whole thing
let e^x = y

y-3/y=4 xboth sides by y

y^2+3=4y rearrange ...y^2-4y+3=0 solve for y then sub into e^x=y to find x values
0
studentwiz
Badges: 3
Rep:
?
#737
Report 3 years ago
#737
(Original post by cerlohee)
Ah sorry no wonder I've had no replies!
Have fixed it now if anyone can help out. Have fun with chemistry
coordinates (6,-1)

a l6-bl -1 = -1
a l6-bl =0
divide by a
6-b=0
b=6
0
mismash
Badges: 2
Rep:
?
#738
Report 3 years ago
#738
hello, i am really sorry to but in.. but im a year 12 student and i am really worried because i dont think i have done v well in my c1 and c2 maths exams.
would u guys recommend retaking those modules in y13 or simply is it going to waste time and increase work load too much...???
0
randlemcmurphy
Badges: 10
Rep:
?
#739
Report 3 years ago
#739
(Original post by cerlohee)
Hi everyone, so I'm having trouble with this question: http://gyazo.com/1f59f436bde2776d6d038bd313fc4e39
For part C, I have worked out that b is 6, how do I then go onto work out A? I got 1/5th... Thanks
We know two points so we can form two equations:

1=a|6-b|-1This means a|6-b|=0 So a could equal zero and b could equal 6

We also have:

11=a|0-b|-1This means ab=12
This means that a cannot equal zero, so b equals 6 and a equals 2 (hope that is the right answer!)
0
lam12
Badges: 2
Rep:
?
#740
Report 3 years ago
#740
(Original post by cerlohee)
Ah sorry no wonder I've had no replies!
Have fixed it now if anyone can help out. Have fun with chemistry
The range changes because it's 3theta. You use 2pi... I don't exactly know what you're exactly asking tbh haha

For the first bit because it's a ^2 it can't be a negative and therefore the sin bit = 0

For the second part it would be 3 theta - 1.107 = 2pi as the range increases as its 3theta and now we can go up to 3pi but it's not = to 3pi and therefore we use just 2pi

I don't think I explained this well but I tried, I may be wrong but it's how it was explained to me :-)

Attachment 412775




Posted from TSR Mobile
0
X
new posts
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

University open days

  • Cranfield University
    Cranfield Forensic MSc Programme Open Day Postgraduate
    Thu, 25 Apr '19
  • University of the Arts London
    Open day: MA Footwear and MA Fashion Artefact Postgraduate
    Thu, 25 Apr '19
  • Cardiff Metropolitan University
    Undergraduate Open Day - Llandaff Campus Undergraduate
    Sat, 27 Apr '19

Have you registered to vote?

Yes! (26)
50%
No - but I will (1)
1.92%
No - I don't want to (1)
1.92%
No - I can't vote (<18, not in UK, etc) (24)
46.15%

Watched Threads

View All
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise