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    (Original post by _MAT_)
    I put green
    I also put green and I believe 4 proton environments
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    Did you get this for the 3d shape of the 1-2,methylpiperazine?

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    (Original post by Edsi)
    Did you get this for the 3d shape of the 1-2,methylpiperazine?

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    Yeah I put that, just horizontally
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    (Original post by Edsi)
    Did you get this for the 3d shape of the 1-2,methylpiperazine?

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    If it went out the page on one side and into the page on the other wouldn't that make it planar?
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    (Original post by geor_thor)
    How many hydrogen environments did people get for the question labelling the H environments.

    Also what colour did you put the iron as for the reflects be spectrum. I put yellow?
    I got 3 environments. Yellow was corrsct

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    (Original post by geor_thor)
    How many hydrogen environments did people get for the question labelling the H environments.

    Also what colour did you put the iron as for the reflects be spectrum. I put yellow?
    I got 5 environments and the color is brown orange but i guess orange yellow would do ( https://www.google.co.uk/#hl=it&q=ocher+pigment )
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    (Original post by LewisEdwards1234)
    Didn't think that paper was too bad, a lot of stuff had came up in a lot of past papers before, calculations were a bit poor though. Believe I got -120 for the enthalpy diagram. 1 for the question with H20, 2 for the value of Y but the others were pretty hard.
    I got 4 for y
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    (Original post by marcus_tj)
    If it went out the page on one side and into the page on the other wouldn't that make it planar?
    Yeah
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    (Original post by marcus_tj)
    If it went out the page on one side and into the page on the other wouldn't that make it planar?
    Not really the electron pair makes it tetrahedral, therefore it can ideally form E/Z isomers as the groups can go both into/out of the page or can be alternated
    At least this is what i think
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    The benzene question I got 3 different environments (numbers 1,2,3) I drew environment 3 only once as that was an NH bond and I drew the number 1 and 2 around each respective ring. Hope this makes sense

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    (Original post by Edsi)
    Not really the electron pair makes it tetrahedral, therefore it can ideally form E/Z isomers as the groups can go both into/out of the page or can be alternated
    At least this is what i think
    Can't be tetrahedral as lone pairs contribute to the bond angle but not the shape. Shape would be pyramidal but it didn't ask

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    Name:  Cycic.png
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    I put this because it's not planar and I assumed that the nitrogen would form a trigonal pyramidal shape since it has three bonding pairs and one lone pair Attachment 554876554880 so it'd look a bit like this?
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    (Original post by iJAKE)
    I got 6
    same i got 6 but i dont think its right

    idk
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    (Original post by B50les)
    I got 4 for y
    So did I
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    (Original post by Fishhy34)
    same i got 6 but i dont think its right

    idk
    I too got 6
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    (Original post by Zuzuvela)
    I got 3 environments. Yellow was corrsct

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    Green should be accepted aswell
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    (Original post by _MAT_)
    Name:  Cycic.png
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    I put this because it's not planar and I assumed that the nitrogen would form a trigonal pyramidal shape since it has three bonding pairs and one lone pair Attachment 554876554880 so it'd look a bit like this?
    I have just found the molecule (except CH3 is replaced with NH2 but it doesn't change the ring shape)
    open the url and click 3d shape
    https://pubchem.ncbi.nlm.nih.gov/com...n=3D-Conformer
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    can anyone remember the structure we needed to label the h environments of?
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    (Original post by TaeNy)
    Am I the only one who put hydrogen for the first one😂
    I put hydrogen too lol thought you needed to break the c=c to make the alkane 😂
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    (Original post by Zuzuvela)
    The benzene question I got 3 different environments (numbers 1,2,3) I drew environment 3 only once as that was an NH bond and I drew the number 1 and 2 around each respective ring. Hope this makes sense

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    Exactly what I got
 
 
 
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