Turn on thread page Beta
    Offline

    2
    ReputationRep:
    (Original post by randlemcmurphy)
    We know two points so we can form two equations:

    1=a|6-b|-1This means a|6-b|=0 So a could equal zero and b could equal 6

    We also have:

    11=a|0-b|-1This means ab=1
    This means that a cannot equal zero, so b equals 6 and a equals 1/6 (hope that is the right answer!)
    A = 2 and i didn't get how you did it :/


    Posted from TSR Mobile
    Offline

    10
    ReputationRep:
    (Original post by lam12)
    A = 2 and i didn't get how you did it :/


    Posted from TSR Mobile
    I realised I wrote 1 instead of 11, post edited.
    Offline

    14
    ReputationRep:
    (Original post by mismash)
    hello, i am really sorry to but in.. but im a year 12 student and i am really worried because i dont think i have done v well in my c1 and c2 maths exams.
    would u guys recommend retaking those modules in y13 or simply is it going to waste time and increase work load too much...???
    It really won't increase your workload too much since you need to know C1 and C2 to be able to do C3 and C4 anyway - 90% of my class are resitting them since they seem so much easier now so think they might as well improve their grade.

    Posted from TSR Mobile
    Offline

    16
    ReputationRep:
    (Original post by randlemcmurphy)
    We know two points so we can form two equations:

    1=a|6-b|-1This means a|6-b|=0 So a could equal zero and b could equal 6

    We also have:

    11=a|0-b|-1This means ab=12
    This means that a cannot equal zero, so b equals 6 and a equals 1/6 (hope that is the right answer!)
    If ab=12, that'd make b 2 which is the right answer! I didn't think of solving it this way (used that it had moved 6 units to the right) but might use in future! My problem was that I stupidly used (11,0) instead of (0,11)... :/ Thanks

    (Original post by lam12)
    The range changes because it's 3theta. You use 2pi... I don't exactly know what you're exactly asking tbh haha

    For the first bit because it's a ^2 it can't be a negative and therefore the sin bit = 0

    For the second part it would be 3 theta - 1.107 = 2pi as the range increases as its 3theta and now we can go up to 3pi but it's not = to 3pi and therefore we use just 2pi

    I don't think I explained this well but I tried, I may be wrong but it's how it was explained to me :-)

    Attachment 412775




    Posted from TSR Mobile
    Ahh thankyou! My problem was that I didn't see the 3theta, assuming it was theta so ended up witht eh wrong answer! Thanks for drawing it out and everything though ))

    (Original post by studentwiz)
    coordinates (6,-1)

    a l6-bl -1 = -1
    a l6-bl =0
    divide by a
    6-b=0
    b=6
    Hey, I had found b but couldn't find a, this is another way to approach it that I didn't think of though so thanks
    Offline

    19
    ReputationRep:
    useful material for the upcoming exams

    http://www.thestudentroom.co.uk/show....php?t=3353445

    http://www.thestudentroom.co.uk/show....php?t=3361867

    http://www.thestudentroom.co.uk/show....php?t=3361905
    Offline

    3
    ReputationRep:
    d and c thanks in advance nvm !

    figured it out :/
    Attached Images
     
    Offline

    3
    ReputationRep:
    someone explain how you would go about getting the range?
    Attached Images
     
    Offline

    5
    ReputationRep:
    (Original post by studentwiz)
    someone explain how you would go about getting the range?
    consider range of y=e^x then consider what will happen to this range when the graph is shifted upward by k^2 units
    Offline

    2
    ReputationRep:
    Hey guys,

    I've done all the real papers from 2005-2014 and also finished up the the Solomon papers. I'm hoping to finish all the Elmwood by tomorrow any suggestions for more papers that are more challenging but still relevant.


    Posted from TSR Mobile
    Offline

    3
    ReputationRep:
    (Original post by Gilo98)
    consider range of y=e^x then consider what will happen to this range when the graph is shifted upward by k^2 units
    1+k^2?
    Offline

    2
    ReputationRep:
    Name:  untitled.JPG
Views: 379
Size:  104.4 KB

    Can anyone help me with ii) ?? I'm confused..
    Offline

    19
    ReputationRep:
    (Original post by ridirahman)
    Name:  untitled.JPG
Views: 379
Size:  104.4 KB

    Can anyone help me with ii) ?? I'm confused..
    Let the length of a side be denoted r. Express V in terms of r.
    You want dr/dt; you can find this using dV/dt and dV/dr. For the specific value you'll need to find r from the given volume.
    Offline

    17
    ReputationRep:
    (Original post by ridirahman)
    Name:  untitled.JPG
Views: 379
Size:  104.4 KB

    Can anyone help me with ii) ?? I'm confused..
    If the side length of the cube is x, then its volume will be x^3. We know dV/dt = 2, we can find dV/dx, and we can find dx/dt from there.
    Offline

    2
    ReputationRep:
    (Original post by Krollo)
    If the side length of the cube is x, then its volume will be x^3. We know dV/dt = 2, we can find dV/dx, and we can find dx/dt from there.
    Ohh okay thanks I got it now
    and I have another question if you don't mind..

    Name:  untitled.JPG
Views: 195
Size:  107.4 KB

    I've done part a) and got root over 109 cos(deta + 16.70)

    How would you do part b) ?
    Offline

    1
    ReputationRep:
    (Original post by ridirahman)
    Ohh okay thanks I got it now
    and I have another question if you don't mind..

    Name:  untitled.JPG
Views: 195
Size:  107.4 KB

    I've done part a) and got root over 109 cos(deta + 16.70)

    How would you do part b) ?
    if you sub root over 109 cos(30t + 16.7) in place of 10cos(30t) + 3sin(30t),
    it becomes
    H = 12 - root 109 cos (30t+16.7)
    which is a transformation of the cos curve. Knowing the maximum in a normal cos curve is 1, you can work backwards to get the maximum in this one.

    for part b, use your maxima and solve for t
    Offline

    2
    ReputationRep:
    Name:  ImageUploadedByStudent Room1433116019.285238.jpg
Views: 205
Size:  160.7 KB

    Someone please help this is from the IYGB papers. I'm confused on part b what order do you do the transformations and why??


    Posted from TSR Mobile
    Offline

    19
    ReputationRep:
    (Original post by Medicjug)
    Name:  ImageUploadedByStudent Room1433116019.285238.jpg
Views: 205
Size:  160.7 KB

    Someone please help this is from the IYGB papers. I'm confused on part b what order do you do the transformations and why??


    Posted from TSR Mobile
    either order so long as it is correct
    (this particular transformation will not appear in an actual EDEXCEL exam after 2005)
    Offline

    19
    ReputationRep:
    useful material for the upcoming exams

    http://www.thestudentroom.co.uk/show....php?t=3353445

    http://www.thestudentroom.co.uk/show....php?t=3361867

    http://www.thestudentroom.co.uk/show....php?t=3361905
    Offline

    2
    ReputationRep:
    (Original post by TeeEm)
    either order so long as it is correct
    (this particular transformation will not appear in an actual EDEXCEL exam after 2005)
    If I decide to stretch it first by scale factor 1/2 do I move it by 1 unit instead of 2?


    Posted from TSR Mobile
    Offline

    19
    ReputationRep:
    (Original post by Medicjug)
    If I decide to stretch it first by scale factor 1/2 do I move it by 1 unit instead of 2?


    Posted from TSR Mobile
    yes
 
 
 
Turn on thread page Beta
Updated: June 21, 2016

University open days

  • Southampton Solent University
    All faculties Undergraduate
    Sun, 18 Nov '18
  • University of Bradford
    All faculties Undergraduate
    Wed, 21 Nov '18
  • Buckinghamshire New University
    All Faculties Postgraduate
    Wed, 21 Nov '18
Poll
Black Friday: Yay or Nay?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.