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# Current Year 13 thread Mark I (2014-2015) watch

1. (Original post by strawberrysnow)
Thank you so much! I feel like an idiot... I'm just so bad at integrating!

But how did you know to differentiate it to the power of 3/2? I realised it was similar to the last question, but I just didn't know what to put instead of the 1/2, if you know what I mean?

By chain rule you take one from the power so you do the opposite
(Original post by The Clockwork Apple)
Integration by substitution
u = x^3
That way you can get rid of the x^2 when you do du/dx
Good luck and tell me when you solve it
Could do this as well
2. (Original post by The Clockwork Apple)
Integration by substitution
u = x^3
That way you can get rid of the x^2 when you do du/dx
Good luck and tell me when you solve it
Thank you - I kind of understand what you're talking about I'm still confused though - I'm just awful at integrating! Can you please explain further? I'm really sorry...
3. (Original post by strawberrysnow)
Thank you - I kind of understand what you're talking about I'm still confused though - I'm just awful at integrating! Can you please explain further? I'm really sorry...
Just do it my way
4. (Original post by L'Evil Fish)
Just do it my way
Haha, yes thank you!!
5. (Original post by strawberrysnow)
Thank you - I kind of understand what you're talking about I'm still confused though - I'm just awful at integrating! Can you please explain further? I'm really sorry...
Sure! I'm in a car journey rn (I'll be home in like 3 hours), so I can send you a complete solution when I get home.
6. (Original post by strawberrysnow)
Haha, yes thank you!!
In any case, if you subs u = x^3, you'll get an overall equation:
(u-2)^7 which should be very easy to integrate!
If you don't know how to get to (u-2)^7 tell me where you get lost and I'll get into more detail
7. (Original post by The Clockwork Apple)
In any case, if you subs u = x^3, you'll get an overall equation:
(u-2)^7 which should be very easy to integrate!
If you don't know how to get to (u-2)^7 tell me where you get lost and I'll get into more detail
Thank you so much for your kindness

I've got (u-2)^8 / 8 now, but I'm still not sure what to do from there... ><

I'm really sorry for making you explain to me.. I'm really bad at integrating
8. (Original post by strawberrysnow)
Sorry to bother everyone but I'm stuck again... Please help? I've tried it by parts again but it's looking quite messy... I really can't integrate!!

Attachment 370913

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I think you might be doing exactly the same exercise as me xD is it exc 10.9 page 246/247?

Posted from TSR Mobile
9. (Original post by rachelc142)
i think you might be doing exactly the same exercise as me xd is it exc 10.9 page 246/247?

posted from tsr mobile
YES ohmygosh can we do these exercises together??
10. (Original post by strawberrysnow)
YES ohmygosh can we do these exercises together??
11. (Original post by rachelc142)
12. Math mock was a joke today
13. (Original post by strawberrysnow)
Thank you so much for your kindness

I've got (u-2)^8 / 8 now, but I'm still not sure what to do from there... ><

I'm really sorry for making you explain to me.. I'm really bad at integrating
You substitute back and you've finished
What's the answer at the end of the book?
So overall ⅛ * (x^3-2) ^ 8
14. (Original post by The Clockwork Apple)
You substitute back and you've finished
What's the answer at the end of the book?
So overall ⅛ * (x^3-2) ^ 8
Omg that's the answer at the back!! Thank you so much!!
15. I wish I started learning the guitar earlier
16. (Original post by strawberrysnow)
Omg that's the answer at the back!! Thank you so much!!
That's OK. Make sure you HMU with more qs
17. (Original post by strawberrysnow)
So for question seven, I considered the differential of sin (2x^3) and compared it to what I was trying to get
Question 10 is an integral given in the formula booklet
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18. (Original post by rachelc142)
So for question seven, I considered the differential of sin (2x^3) and compared it to what I was trying to get
Question 10 is an integral given in the formula booklet
Posted from TSR Mobile
You guys have it easy, formula booklets don't exist at Advanced Higher

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19. (Original post by Princepieman)
You guys have it easy, formula booklets don't exist at Advanced Higher

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I find the formula booklet that CIE gives useless tbh
20. (Original post by binarythoughts)
I find the formula booklet that CIE gives useless tbh
You still get one though.

One 3 hour exam, without any formula books at all. Not cool.

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