Hey there! Sign in to join this conversationNew here? Join for free
x Turn on thread page Beta

Edexcel FP3 - 27th June, 2016 watch

  • View Poll Results: How did you find the Edexcel FP3 exam?
    Very hard
    41
    8.40%
    Hard
    69
    14.14%
    Normal
    156
    31.97%
    Easy
    165
    33.81%
    Very easy
    57
    11.68%

    Offline

    20
    ReputationRep:
    (Original post by Major-fury)
    The only question I'm not sure on is the last one I think I did everything right but can't seem to remember my answer. The position vector was (0,-0.2, and something else )
    you used x = 0 then, well you can test the position vector by subbing into the cartesian equations, you will find one of them posted above.
    Offline

    20
    ReputationRep:
    (Original post by MarocMan)
    my honest opinion is that itll be 72 100UMS 65 A* 58 A 51 B and who cares about the rest tbh... and i somehow couldnt get question 2, but i done everything else... btw what did you lot get for that completing the square integral that had a negative 1 as the coefficient of x^2 in the root
    2/3 arctan(x/2) or x/4, can't remember exactly
    Maybe it was 4/3 arctan(x/4), one of the two.
    Offline

    2
    ReputationRep:
    (Original post by oShahpo)
    Did you get it in the form required? I remember it was something like pi + 6root3 - 6 or pi - 6root + 6.
    it was pi +6root3 -6 inside the bracket yh, i know thats right cus i then tested it on my calculator and it was same answer
    Offline

    20
    ReputationRep:
    (Original post by MarocMan)
    my honest opinion is that itll be 72 100UMS 65 A* 58 A 51 B and who cares about the rest tbh... and i somehow couldnt get question 2, but i done everything else... btw what did you lot get for that completing the square integral that had a negative 1 as the coefficient of x^2 in the root
    72 for an A* is too high, people generally make mistakes, specially in FP3 so I think it will be 71/70.
    Offline

    2
    ReputationRep:
    (Original post by oShahpo)
    2/3 arctan(x/2) or x/4, can't remember exactly
    Maybe it was 4/3 arctan(x/4), one of the two.
    there were limits so what was your answer in terms of pi?
    Offline

    2
    ReputationRep:
    Guys what would 60-64/75 be? thanks (:
    Offline

    20
    ReputationRep:
    (Original post by MarocMan)
    there were limits so what was your answer in terms of pi?
    Oh that's b then right? I can't remember but I think k was = 2.
    Offline

    2
    ReputationRep:
    (Original post by oShahpo)
    72 for an A* is too high, people generally make mistakes, specially in FP3 so I think it will be 71/70.
    nah i said 72 for 100 UMS loool 65 for A*, this paper was milessss harder that june 2012 which had 70 for A* and 66 for A
    Offline

    2
    ReputationRep:
    (Original post by oShahpo)
    72 for an A* is too high, people generally make mistakes, specially in FP3 so I think it will be 71/70.
    he said 72 for 100UMS
    Offline

    20
    ReputationRep:
    (Original post by blahblah21)
    Guys what would 60-64/75 be? thanks (:
    A if you're lucky, but possibly a high B.
    Offline

    6
    ReputationRep:
    (Original post by oShahpo)
    2/3 arctan(x/2) or x/4, can't remember exactly
    Maybe it was 4/3 arctan(x/4), one of the two.
    Wasn't the answer for th pi / 3
    Offline

    2
    ReputationRep:
    (Original post by oShahpo)
    Oh that's b then right? I can't remember but I think k was = 2.
    youre talking about the y=arcothx question loool but yesss i got k=2 ... i thought i got it wrong THANK GOD
    Offline

    2
    ReputationRep:
    (Original post by MarocMan)
    there were limits so what was your answer in terms of pi?
    arcsin1-arcsin0.5 = pi/3 is what i got.
    Offline

    20
    ReputationRep:
    (Original post by Anon-)
    he said 72 for 100UMS
    Oh, that's impossible then. It will be 75 for an A* definitely! Unless the candidate pool this year is worse than the previous years..
    Offline

    6
    ReputationRep:
    Solutions - Let me know if any need changing.
    1)3 and -2
    2)5/8+ln(3/2)
    3)k=2
    4)pi/3 2/3arctan(e^x/3)
    5)25/3-32/15root2
    6)9 then p=7 and q=5, the eigenvector is (2,1,-2) and then there will be varying orders of the eigenvectors for P.
    7)1/12(pi+6root3-6)
    8)7x+5y-9z=8 and my a was (11/8,-13/8,0) and b was (11/8,-1/8,1) although others may differ.
    Offline

    2
    ReputationRep:
    (Original post by Major-fury)
    Wasn't the answer for th pi / 3
    yessss thats what i got, i then tested the integral on my calculator and the calculator gave me a maths error looool so i assumed the question was a mistake tbh, but i did whatever to get pi/3
    Offline

    2
    ReputationRep:
    (Original post by oShahpo)
    A if you're lucky, but possibly a high B.
    ahh cheers man, i need like 73 ums in this for an A
    Offline

    20
    ReputationRep:
    (Original post by Anon-)
    arcsin1-arcsin0.5 = pi/3 is what i got.
    I can't remember, I think I might have not substituted in the limits. Do you remember which question this was? Was it two parts or just one part?
    Offline

    6
    ReputationRep:
    Am I the only one who liked the integrating questions ? You can literally check ur answers to see if they are correct
    Offline

    20
    ReputationRep:
    (Original post by Ewanclementson)
    Solutions - Let me know if any need changing.
    1)3 and -2
    2)5/8+ln(3/2)
    3)k=2
    4)pi/3 2/3arctan(e^x/3)
    5)25/3-32/15root2
    6)9 then p=7 and q=5, the eigenvector is (2,1,-2) and then there will be varying orders of the eigenvectors for P.
    7)1/12(pi+6root3-6)
    8)7x+5y-9z=8 and my a was (11/8,-13/8,0) and b was (11/8,-1/8,1) although others may differ.
    I agree with all but I don't remember this pi/3 at all. Do you remember the question?
    AHHH **** I forgot to sub the e^x in U.. ****.!
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: August 20, 2016
Poll
Do you agree with the proposed ban on plastic straws and cotton buds?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.