Hey there! Sign in to join this conversationNew here? Join for free
    Offline

    3
    ReputationRep:
    (Original post by marioman)
    The count rate is going to drop when you move it further away regardless of whether there's beta emission or not.
    Ya so you have to use aluminium sheet to check, or some other thing


    Posted from TSR Mobile
    Offline

    2
    ReputationRep:
    (Original post by marioman)
    The count rate is going to drop when you move it further away regardless of whether there's beta emission or not.
    Wouldnt there be a rapid drop past beta's range?
    Offline

    3
    ReputationRep:
    (Original post by Nikhilm)
    Nah it was 127/128 from the calculation


    Posted from TSR Mobile
    Yeah!
    Offline

    12
    ReputationRep:
    (Original post by CourtlyCanter)
    I was the only one in my school to do it as I learnt it myself because the teacher we had for astrophysics was awful. This year's paper was hard. Do you remember your answers to any of the questions?
    I've made a medical thread
    • Political Ambassador
    • Welcome Squad
    Offline

    2
    ReputationRep:
    Political Ambassador
    Welcome Squad
    (Original post by Mango Milkshake)
    just checked, it's 10,000



    did you round it too early?
    I didn't round anything off until I got to the final answer. Don't know where I went wrong.
    Offline

    0
    ReputationRep:
    (Original post by txnilxnur)
    I thought it was 2000 lmao, swear that's what it says in the textbook
    Isn't it 1 in 2000 for a deflection and 1 in 10000 for angles greater than 90?

    Posted from TSR Mobile
    Offline

    2
    ReputationRep:
    (Original post by CourtlyCanter)
    I was the only one in my school to do it as I learnt it myself because the teacher we had for astrophysics was awful. This year's paper was hard. Do you remember your answers to any of the questions?
    yea this paper was pretty difficult. I didnt get the first calculation to do with the eye. I remember getting 57% for the x ray calculation to do with 12mm. what about you?
    Offline

    2
    ReputationRep:
    (Original post by lc970916)
    probably not .

    " Expressions for the electric and magnetic fields in free space contain the electric permittivity ε0 and magnetic permeability μ0 of free space. As indicated in the section on electric and magnetic constants, these two quantities are not independent but are related to "c", the speed of light and other electromagnetic waves."

    source: http://hyperphysics.phy-astr.gsu.edu...ic/elefie.html
    True they are well defined quantities rather than those who put electric foeld strength and magnetic field strength which are not defined quantities.
    Offline

    1
    ReputationRep:
    3.1*10^-15 for radius of oxygen


    Posted from TSR Mobile
    Offline

    3
    ReputationRep:
    (Original post by particlestudent)
    kingaaran Mango Milkshake

    What did you guys put for the test to see if it emitted beta as well?
    Use a beta absorber, i.e. a few mm of aluminium. Then you can see if this result matches up with the result obtained at 0.9m by using the inverse square law of gamma radiation
    Offline

    12
    ReputationRep:
    (Original post by Nikhilm)
    Ya so you have to use aluminium sheet to check, or some other thing


    Posted from TSR Mobile
    Could I have said:

    "I said plot a graph of count rate against 1/r^2 and it should be a straight line if it is only gamma, but if it is beta it will not be a straight line."
    Offline

    2
    ReputationRep:
    specific charge was 1.8x10^11 Ckg^-1
    Offline

    3
    ReputationRep:
    (Original post by BigDaddy97)
    3.1*10^-15 for radius of oxygen


    Posted from TSR Mobile
    got that
    Offline

    3
    ReputationRep:
    (Original post by FireBLue97)
    specific charge was 1.8x10^11 Ckg^-1
    It wasn't. That is the actual specific charge but the experimental specific charge was 9.1x10^10
    Offline

    12
    ReputationRep:
    (Original post by kingaaran)
    Use a beta absorber, i.e. a few mm of aluminium. Then you can see if this result matches up with the result obtained at 0.9m by using the inverse square law of gamma radiation
    I didn't mention aluminium at all . I said plot count rate against 1/distance squared and if it is a complete straight line then it is only a gamma emitter
    Offline

    2
    ReputationRep:
    Grade boundary predictions?


    Posted from TSR Mobile
    Offline

    2
    ReputationRep:
    (Original post by particlestudent)
    kingaaran Mango Milkshake

    What did you guys put for the test to see if it emitted beta as well?
    I put put an electromagnet between source and detector and drew this Name:  ImageUploadedByStudent Room1467110577.548067.jpg
Views: 233
Size:  44.3 KB


    Posted from TSR Mobile
    Offline

    3
    ReputationRep:
    (Original post by particlestudent)
    I didn't mention aluminium at all . I said plot count rate against 1/distance squared and if it is a complete straight line then it is only a gamma emitter
    I think you'll be fine - it sounds valid
    Offline

    14
    ReputationRep:
    (Original post by particlestudent)
    I said plot a graph of count rate against 1/r^2 and it should be a straight line if it is only gamma, but if it is beta it will not be a straight line.

    This better be accepted
    I saw that in a past paper as an alternative method once. You still get the marks
    Offline

    1
    ReputationRep:
    I also got 1.2x10^8 AU for the penultimate quasar question but starting to think this is wrong after looking on here

    For those who got the other answer (2.4 something) could you tell me how u did this question as i am really confused.
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Has a teacher ever helped you cheat?
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Write a reply...
    Reply
    Hide
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.