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    so.... do we need a Hitler video for this one ? :flute:
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    (Original post by GCSEsThen)
    I got the same thing using area of a triangle formula 1/2*b*h

    so 1/2*25*25/8

    Your method would take longer and isnt as efficient but is perfectly valid
    I feel so stupid for not doing that xD But at least I still got it right lol
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    On question 11 simplifying part. Did it ask you to
    simplify (f(x+h) - f(x))/h when f(x) = x^2 - 2x
    and not mention when x = 5?
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    What was the answer to the final question in c2? I rounded up :/??
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    FULL UNOFFICIAL MARK SCHEME
    https://docs.google.com/document/d/1...it?usp=sharing
    This took me so long, hope its helpful
    Tweet me for any errors (@MilindS99)
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    (Original post by MilindS99)
    FULL UNOFFICIAL MARK SCHEME
    https://docs.google.com/document/d/1...it?usp=sharing
    This took me so long, hope its helpful
    Tweet me for any errors (@MilindS99)
    Do you have a question paper so I can see question 11?
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    (Original post by Mr Moon Man)
    Why can't you round up?
    I was debating whether to round up and I did, but do u lose the mark if you rounded up?
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    (Original post by MilindS99)
    FULL UNOFFICIAL MARK SCHEME
    https://docs.google.com/document/d/1...it?usp=sharing
    This took me so long, hope its helpful
    Tweet me for any errors (@MilindS99)
    On question 11 there is an error. It was x=5 and 5.1, not 8. 8 was gradient.
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    (Original post by Shipreck)
    On question 11 there is an error. It was x=5 and 5.1, not 8. 8 was gradient.
    for part (i) the gradient was 8.1 I think
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    I don't understand why you can't round up on the last question? Where does that rule come from?
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    (Original post by ineedA)
    Did anyone get 4. Something for the sum of the sequence when A is 5, I'm sure it's not 25
    For that question I got:

    i) a=5

    Sum = 25

    ii) a=6

    Sum = 0
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    Edit: Sorry the images are quite big for some reason





    Both Wolfram Alpha and Mathway say that it is -m^3 although the question itself was really confusing. OCR are missing out brackets when needed especially on the sine question too.
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    (Original post by Akhawais)




    Both Wolfram Alpha and Mathway say that it is -m^3 although the question itself was really confusing. OCR are missing out brackets when needed especially on the sine question too.
    That isn't what the question was. The question was -loga(a^m)^3 = -loga(a^3m) = -3m.
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    (Original post by JoshP97)
    For that question I got:

    i) a=5

    Sum = 25

    ii) a=6

    Sum = 0
    How did you get that?
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    Also is y = sin x - 3

    y = (sin x) - 3 OR y = sin (x - 3)

    I was told that there was an error and it was supposed to be the 2nd one, but I can't find any where that OCR said this (I was told the exam board tweeted about it??). I really hope that's not true as I did the first one. I think both should be credited as it was very unclear.
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    (Original post by Akhawais)
    Edit: Sorry the images are quite big for some reason





    Both Wolfram Alpha and Mathway say that it is -m^3 although the question itself was really confusing. OCR are missing out brackets when needed especially on the sine question too.
    If you read the actual 'input' in wolfram alpha i think it would have been put like that if the log was cubed, but i agree they needed brackets to make this clear
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    I can't be the only who thought I'd seen the paper before. Section B felt so familiar
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    What are you serious with that log question? I put -3m! Wtf is wrong with OCR why do they hate brackets?!?!?? Screwing us over for no reason we basically have to guess what they mean which doesn't test what we know.
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    (Original post by Mr Moon Man)
    How did you get that?
    i) When a = 5 the sequence oscillates, so the remainder would be 2, x 5 = 10 for the second term, the 3rd term would be 1 since 10/3 has a remainder of one, x 5 = 5 for the third term, this goes back to 10 for the fourth term. 10+5+10 = 25.

    ii) When a = 6 there is no remainder to multiply by 5, so the sequence would be 0,0,0,0. the sum of these would be 0.
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    (Original post by ♥Samantha♥)
    Also is y = sin x - 3

    y = (sin x) - 3 OR y = sin (x - 3)

    I was told that there was an error and it was supposed to be the 2nd one, but I can't find any where that OCR said this (I was told the exam board tweeted about it??). I really hope that's not true as I did the first one. I think both should be credited as it was very unclear.
    Ocr haven't tweeted anything about that so I assume that the first one is correct
 
 
 
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