Intermediate 2 Maths 2010 Thread Watch

Rachel_93
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#61
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#61
Oh no, i cant remember what ive wrote for half of it and lookin at these anwsers is making me panic!:eek3:
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minsyb
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#62
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#62
Don't worry Rachel! I'm sure you will have done fine! I would upload Paper 1 but I don't have a scanner! Would appreciate if anyone could and then CJN can use their wonderous mind to tell us the answers!! xx
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CJN
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#63
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#63
(Original post by minsyb)
Don't worry Rachel! I'm sure you will have done fine! I would upload Paper 1 but I don't have a scanner! Would appreciate if anyone could and then CJN can use their wonderous mind to tell us the answers!! xx
I can do this if you want, even a half decent camera would do to take pics of every page.

I don't mind if the paper is written on as long as the question is readable
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xxxlopestar
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#64
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I thought it was hard lollol, paper 2 i screwed up so badly and even paper 1 was quite hard. The prelim was ten times easier and i got 87% so i think i will probably get a B!
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TEX1
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#65
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#65
This Years paper was execeptionally harder than previous years-especially with the heat as an additional burden but it still was doable
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xxxlopestar
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#66
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#66
(Original post by TEX1)
This Years paper was execeptionally harder than previous years-especially with the heat as an additional burden but it still was doable
Agreeeeeeeeeeeeeeeeee! Last years one was sooo much easier
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minsyb
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#67
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#67
I agree, I thought Paper 1 was harder this year!! Would love if anyone could scan a copy to the forum??
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derangedyoshi
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#68
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#68
My answers (most should be reliable - I got full marks in the prelim):

Paper 1
Q1 y = -4/3x + 8
Q2a I don't want to type it out, but it wasn't that hard, was it?
2b 7, 6, 8
2c boxplot at 5, 6, 7, 8 and 11
Q3 113.04 cm3
Q4a (x+3)(x-2)
4b 3x^3 + 17x^2 + 7x -2
Q5 k = -9
Q6 AC = 8 cm
Q7 p^5 - 1
Q8a -11
8b As b^2 - 4ac is negative she can't find its square root so can't find the roots
Q9 a = 45
Q10a a = -5
10b Q(8,0)
10c b = -9

Paper 2
Q1 £155000
Q2 pasta 150 degrees, baked potato 200, salad 10
Q3 £11
Q4a mean = 7, standard deviation = 3.96
4b On average, the team's points per match are higher and more consistent.
Q5 x=7, y=-2
Q6 3s/2
Q7 L = (P - 2B)/2
Q8 4root7
Q9 1342 cm2
Q10a multiply sides and simplify
10b 2 metres
Q11 25.3 cm
Q12 126 m
Q13 3.45 m
Q14a 8.69 m
14b 48.1 degrees
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CJN
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#69
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(Original post by derangedyoshi)
My answers (most should be reliable - I got full marks in the prelim):

Paper 1
Q1 y = -4/3x + 8
Q2a I don't want to type it out, but it wasn't that hard, was it?
2b 7, 6, 8
2c boxplot at 5, 6, 7, 8 and 11
Q3 113.04 cm3
Q4a (x+3)(x-2)
4b 3x^3 + 17x^2 + 7x -2
Q5 k = -9
Q6 AC = 8 cm
Q7 p^5 - 1
Q8a -11
8b As b^2 - 4ac is negative she can't find its square root so can't find the roots
Q9 a = 45
Q10a a = -5
10b Q(8,0)
10c b = -9

Paper 2
Q1 £155000
Q2 pasta 150 degrees, baked potato 200, salad 10
Q3 £11
Q4a mean = 7, standard deviation = 3.96
4b On average, the team's points per match are higher and more consistent.
Q5 x=7, y=-2
Q6 3s/2
Q7 L = (P - 2B)/2
Q8 4root7
Q9 1342 cm2
Q10a multiply sides and simplify
10b 2 metres
Q11 25.3 cm
Q12 126 m
Q13 3.45 m
Q14a 8.69 m
14b 48.1 degrees
I guarentee the answers I posted are correct, if you upload paper 1 I can do those answers and you can check if you want - but mine are definitely right.

You answers for paper 2 look all correct except maybe a small error in Q7?
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derangedyoshi
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#70
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#70
For Q7, they're equivalent:
(P - 2B)/2
=P/2 - 2B/2
=P/2 - B

This works because (x + y)/z = x/z + y/z
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CJN
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#71
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#71
(Original post by derangedyoshi)
For Q7, they're equivalent:
(P - 2B)/2
=P/2 - 2B/2
=P/2 - B

This works because (x + y)/z = x/z + y/z
Sorry I read his answer wrong I read it as P/2 - B/2 my fault :o: yes I know how it works...
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TEX1
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#72
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#72
It was so easy when they put in a F***ing pie chart construct ? the SQA are legendary- what a gift.
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DanielJarvie
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#73
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#73
i'm doing int2 maths unit4 and i have two sets of data which are two classes of exam results. i have used the date to draw pictographs and cumulative frequency graphs. I've made a summary table with both sets with median, mean, siqr and the mode but i don't know what to write for the conclusion. any help would be appreciated!
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TheUnbeliever
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#74
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#74
(Original post by DanielJarvie)
i'm doing int2 maths unit4 and i have two sets of data which are two classes of exam results. i have used the date to draw pictographs and cumulative frequency graphs. I've made a summary table with both sets with median, mean, siqr and the mode but i don't know what to write for the conclusion. any help would be appreciated!
It's kind of tricky without seeing the data, but you really want to comment on the relationship between the two sets of data. For example, (and completely making this up): "Class 2 has a higher mean, but a lower median - there were a couple high performing outliers that weren't representative of the class as a whole. Class 1's marks have a lower mean, but also a lower standard deviation. Most members of class 1 performed better than most of those in class 2."

Mode is likely to be entirely meaningless in this circumstance, and I'm not sure why pictographs would be more useful than a box plot - but it's been a very long time since I did Int 2, so perhaps that's what was asked for.
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