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OCR Salters Chemistry B F332 Advance Notice Jan 2011 Understanding Our Changing Atmos

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Original post by russdood93
What did you put for:

a source of propene?

reagents and conditions for converting propene to propan-2-ol?

reagents and conditions for converting propane to 2-chloropropane?


I put:

1) Crude oil

2) Phosphoric acid catalyst 60atm 300 oC temp

3) Dilute HCL (shake at) room temp and pressure.....?
Reply 61
Original post by tkoki1993
For 1. I would've said crude oil


that's what i said. It was only a one mark question
Original post by tkoki1993
what did people get for the question about equilibria?


I got a little confused :frown: But I wrote that increase temp would decrease yield as it would favour the endothermic reaction (:s:) and increase pressure would increase yield as it would favour the forwards reaction (more moles)

I have no idea :/
What did you guys put for how did they find out how ozone depleted
Reply 64
Original post by hidden_desire
I put:

1) Crude oil

2) Phosphoric acid catalyst 60atm 300 oC temp

3) Dilute HCL (shake at) room temp and pressure.....?


Same.

Original post by hidden_desire
I got a little confused :frown: But I wrote that increase temp would decrease yield as it would favour the endothermic reaction (:s:) and increase pressure would increase yield as it would favour the forwards reaction (more moles)

I have no idea :/


I got that the increased temp would decrease yield as higher temperatures favour endothermic side. Higher pressure increases yield as it favours the side with least gas molecules, and so moves to the left...that's if I'm remembering correctly...
(edited 13 years ago)
Reply 65
Original post by Darthdevidem
What did you guys put for how did they find out how ozone depleted


How'd you mean?

I just put about how the British antarctic survey used a converted spy plane and sateliites to gather data on ozone at different points in antarctica. They also performed mass spectrometry (I think!) on samples they collected.
The data was originally overlooked as the data gathered was so low it was filtered out by the computers they used. It took them a while to find it amongst all the other samples. :confused:
Reply 66
Original post by jpurkis1

Original post by jpurkis1
How'd you mean?

I just put about how the British antarctic survey used a converted spy plane and sateliites to gather data on ozone at different points in antarctica. They also performed mass spectrometry (I think!) on samples they collected.
The data was originally overlooked as the data gathered was so low it was filtered out by the computers they used. It took them a while to find it amongst all the other samples. :confused:


Crap I put infrared...
Reply 67
what did everyone get for the titration question and ratio?

for titration q:
acid was 2.5x10^-3moles
2.5x10^-3 moles
concentration was 0.124moldm-3??

ratio i got 1:3??
Reply 68
Original post by gozatron
Crap I put infrared...

didnt they ask something about infrared i said look for a peak at 1720 to 1740??
Reply 69
Original post by coffee345
what did everyone get for the titration question and ratio?

for titration q:
acid was 2.5x10^-3moles
2.5x10^-3 moles
concentration was 0.124moldm-3??

ratio i got 1:3??


You've got a good memory...

I can't remember what I put for the titration, but that sounds about right.
The molar ratio question was annoying, because everyone in my class who retook it got different answers. I got 1 : 0.4 :s-smilie:
Reply 70
Original post by jpurkis1
You've got a good memory...

I can't remember what I put for the titration, but that sounds about right.
The molar ratio question was annoying, because everyone in my class who retook it got different answers. I got 1 : 0.4 :s-smilie:


lol im worried about the exam thats why D:

did you get burette for equipment?

and how did you get 0.4...because i got that but changed it to 3 :frown:
How many marks do you think we'll need for 90 UMS or 100UMS?

For 90 I reckon 82/100 raw marks

For 100 I reckon 90/100 raw marks

Anyone else agree?
Reply 72
Original post by coffee345
lol im worried about the exam thats why D:

did you get burette for equipment?

and how did you get 0.4...because i got that but changed it to 3 :frown:


I sort of guessed; I didn't get it at all...

And yes, burette.
Reply 73
What did everyone put about the equilbrium question?
I put increase yield for Temperatrue
and decrease yeield for pressure?

Am i wrong? :frown:

I also put the ethene was used to make Plastics? Is that right?
(edited 13 years ago)
what did people get for the bond enthalpy question? thought it was a bit cheeky they changed it round from way they've done it in all the past papers. i think i got something like 348kJ :/

and the mole ratio one? how were you supposed to work it out? had no idea what to do, moved on and just bunged down 1:0.5 in a last minute rush
Reply 75
Original post by jpurkis1

I got that the increased temp would decrease yield as higher temperatures favour endothermic side. Higher pressure increases yield as it favours the side with least gas molecules, and so moves to the left...that's if I'm remembering correctly...


That's what I put.
Reply 76
Original post by MyJunkIsYou
what did people get for the bond enthalpy question? thought it was a bit cheeky they changed it round from way they've done it in all the past papers. i think i got something like 348kJ :/

and the mole ratio one? how were you supposed to work it out? had no idea what to do, moved on and just bunged down 1:0.5 in a last minute rush


Where did you get 343kj from? I think i got mine wrong? My answer came to summin like 10^-19
Reply 77
Original post by tom108
Where did you get 343kj from? I think i got mine wrong? My answer came to summin like 10^-19


i got something x10^-19

and for the bond enthalpy one i got something x10^-40 O.O"
Original post by tom108
Where did you get 343kj from? I think i got mine wrong? My answer came to summin like 10^-19


oh yeah well i got something to the 10^-19 for the first part, calculating the energy for a single bond.

And then it wanted the bond enthalpy in kj if i remember. that's what i got 348kj for. but then again i wasn't sure whether to divide or times by the avogadro constant so knowing me i probably did the wrong thing!
Reply 79
Original post by tom108
Where did you get 343kj from? I think i got mine wrong? My answer came to summin like 10^-19


The answer of X * 10^-19 needed to be multiplied by avogadro's constant (6.02 * 10 ^23) to work out the bond enthalpy. They might accept answers in a range of between 320 - 370, from what I've seen and heard from people.

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