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    (Original post by Noble.)
    Ok, I will tell you the answer - not that it's going to help you.

    For the circle to 'touch' each axis we must have that the centre point of the circle is of the form (a,b) where a=b

    Since we also have that (a,b) lies on the line y=3x-4 we must have b=3a-4 but we also know that a=b, so a = 3a -4 gives the centre of the circle being (2,2) now the radius is also obvious.
    hi nobel, I am having bother understanding the equation of a circle

    x^2 + y^2 + 2gx + 2fy + c = 0

    what are f g and c?
 
 
 
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