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    (Original post by 123formyabc)
    Hard paper i reckon below 58 for an a. What lines did everyone get for the last question
    Think I got y = x - 1 for one of them and y = -x for the other
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    Guys what did you get in the matrix questions because I was kind of baffled except the first and the last parts. I think the (ii) I got p'(2,-2), (iii) y=-x, (iv) y =6
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    (Original post by 123formyabc)
    Hard paper i reckon below 58 for an a. What lines did everyone get for the last question
    I think I put y=6 for one answer then something like y=-x for another one, was in the last minute so not exactly reliable lol
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    (Original post by Aaqil)
    Guys what did you get in the matrix questions because I was kind of baffled except the first and the last parts. I think the (ii) I got p'(2,-2), (iii) y=-x, (iv) y =6
    What was the original p coordinate can you remember?
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    (Original post by Jackb1234)
    Think I got y = x - 1 for one of them and y = -x for the other
    For the last one I got y = x, since I kept getting the collumn matrix (y y). I got y = -x for iii) but y =x for vi.

    Ill post the question if any1 wants to check:

    ill do rest in a second yea
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    (Original post by Aaqil)
    Guys what did you get in the matrix questions because I was kind of baffled except the first and the last parts. I think the (ii) I got p'(2,-2), (iii) y=-x, (iv) y =6
    Yeah man thats all correct, checking the paper currently looks good.

    Nah wait, p(-2,2) not what you wrote.
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    Great i put something similar. But.. It sounds like i messed up on he argand diagram i got 3 - j, will he error get carried forward? So ill only lose like a 2 marks for it?
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    (Original post by Law-Hopeful)
    Can anyone remember what they got for question 6?
    The question was x^3-5x^2+3x-6=0 has roots... Find the cubic with roots (a/3)+1, (B/3)+1 and (y/3)+1.

    I got 9w^3-42w^2+60w-29=0?
    Just did it and i got 9w^3 -42w^2 +60w -29 =0 after simplfying. :cool:
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    (Original post by UKBrah)
    Just did it and i got 9w^3 -42w^2 +60w -29 =0 after simplfying. :cool:
    Thats definitely the right answer checked it on the calculator
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    (Original post by abdcefghi)
    Thats definitely the right answer checked it on the calculator
    haha thats what I did, i found alpha of the original equation and did a/3 +1 and it did indeed work.
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    (Original post by UKBrah)
    For the last one I got y = x, since I kept getting the collumn matrix (y y). I got y = -x for iii) but y =x for vi.

    Ill post the question if any1 wants to check:

    ill do rest in a second yea
    omg yeah could you please post a few pictures of the whole paper. Thought it was vile. Didn't manage to prove by induction, fudged it up half way through...If grade boundaries are like a record low I may have got an A
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    (Original post by theCreator)
    omg yeah could you please post a few pictures of the whole paper. Thought it was vile. Didn't manage to prove by induction, fudged it up half way through...If grade boundaries are like a record low I may have got an A
    I got you man, sending from phone
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    Can someone upload pictures of the whole paper please would be much appreciated
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    Far as I was concerned, it seemed a rather middle-of-the-road paper in terms of difficulty, maybe slightly more difficult than average, albeit MUCH nicer than the one this January.


    I struggled to plot the argand diagram. As far as I remember, it asked you to plot z1, z2, z1-z2, and z1+z2.

    \left | {z_{2}}  \right | = 5

    arg(z_{2}) = \frac{\pi}{4}

    Using them both I got:

    z_{2}​ = \frac{5\sqrt{2}}{2}+\frac{5\sqrt  {2}}{2}j



    The roots question seemed a bit out of the way, I remember having an x3 coefficient of 9x^{3} and the others were fairly high.
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    Here lads

    Can someone please find what the equation of the line is in the last part of 9?

    Is it y =x? im dying to know
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    (Original post by UKBrah)
    Here lads

    Can someone please find what the equation of the line is in the last part of 9?

    Is it y =x? im dying to know

    I got y=-x
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    (Original post by Political Cake)
    Far as I was concerned, it seemed a rather middle-of-the-road paper in terms of difficulty, maybe slightly more difficult than average, albeit MUCH nicer than the one this January.


    I struggled to plot the argand diagram. As far as I remember, it asked you to plot z1, z2, z1-z2, and z1+z2.

    \left | {z_{2}}  \right | = 5

    arg(z_{2}) = \frac{\pi}{4}

    Using them both I got:

    z_{2}​ = \frac{5\sqrt{2}}{2}+\frac{5\sqrt  {2}}{2}j



    The roots question seemed a bit out of the way, I remember having an x3 coefficient of 9x^{3} and the others were fairly high.
    Yep I agree with your answer for z2.

    The diagram was really cluttered with tons of surds. I think I had like 3 complex numbers in the positive x quadrant and 1 somewhere else.
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    (Original post by theCreator)
    I got y=-x
    I got that for part iii or whatever it was before, not for the last part!
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    What was the answer to q2 lol i sound like an idiot
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    (Original post by 123formyabc)
    What was the answer to q2 lol i sound like an idiot
    -3+j/-3-j
 
 
 
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