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    I think I lost 10 marks +/-1 mark will this be an A? PLEASE PUT ME OUT OF MY MISERY! (roughly around 86%)
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    (Original post by chuckynoriss)
    Using the grade boundaries for June 2012 (which was also a relatively easy paper) 57 maybe for an A. (it's usually in the 50's to get an A)
    Is that not really low??? The grade boundaries for easy papers have been up to 65 aka Jan 09?
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    (Original post by CDL)
    Dont mean to be disrespectful to anyone's previous posts but I think a lot of people are mistaken on the grade boundaries for this paper. I am myself quite an able mathematician, scoring 96UMS on Core 1, and i did struggle with some aspects of the paper, especially 8ii. bearing in mind that most of the people who post on here are ALSO very able, i think we're forgetting that this was actually quite a difficult paper and will undoubtedly catch out the 'less able' candidates that took it, so my money is on 55-57 for an A grade
    Thanks for pointing this out. I'm not particularly gifted with maths, and my teacher got really ill so we've basically taught ourselves most of the c2 & s1 stuff. I didn't find the paper that easy, I think I got around 45-52 marks (I can't remember some of the answers I put). So just wanted to say thanks for putting it out there that not everyone found it easy!
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    Hate to point this out, but I think the table of grade boundaries that [email protected] posted is for another specification
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    Does anyone know where we can find a table for previous grade boundaries for ease of use?
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    (Original post by tgtips372)
    Does anyone know where we can find a table for previous grade boundaries for ease of use?
    Can't find a table with them all in a list but here's the past 3.
    Jan 2013
    June 2012
    Jan 2012
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    (Original post by tgtips372)
    Hate to point this out, but I think the table of grade boundaries that [email protected] posted is for another specification
    You're right, sorry.

    ------------A--B--C--D--E
    Jan 13 - 54 47 40 34 28
    Jun 13 - 57 51 45 39 33
    Jan 12 - 60 53 46 40 34
    Jun 11 - 59 52 46 40 34
    Jan 11 - 60 53 46 39 33
    Jun 10 - 57 51 45 40 35
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    (Original post by RooRoo1)
    Thanks for pointing this out. I'm not particularly gifted with maths, and my teacher got really ill so we've basically taught ourselves most of the c2 & s1 stuff. I didn't find the paper that easy, I think I got around 45-52 marks (I can't remember some of the answers I put). So just wanted to say thanks for putting it out there that not everyone found it easy!
    If it's 57 I'll sob with happiness (I have all my fingers and my toes and my arms and my legs crossed)
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    For the sake of completion:
    7)i) Show that worked solution.
    I = \displaystyle\int^4_1 x^{\frac{3}{2}} - 1 \ dx = \left[\dfrac{2}{5}x^{\frac{5}{2}} - x \right]^4_1

\Rightarrow I = \left(\dfrac{2}{5}(4^{\frac{5}{2  }}) - 4\right) - \left(\dfrac{2}{5}(1^{\frac{5}{2  }}) - 1\right)

\Rightarrow I = \dfrac{64}{5}-4+\dfrac{3}{5} = \dfrac{67-20}{5} = \dfrac{47}{5} = 9\frac{2}{5}
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    (Original post by [email protected])
    1. 6.39 [4]
    2i) 106, 254 [3]
    2ii) 71.6, 252 [3]
    3i) 64+960x+6000x^2 [4]
    3ii) c=-11 [3]
    4a) (5/4)x^4-3x^2+x+c [3]
    4bi) -12x^-2+c [2]
    4bii) a=+2 [3]
    5i) 62.2 [4]
    5ii) 34 [4]
    6i) 963 [3]
    6ii) 17 [6]
    7i) show that [4]
    7ii) 37/30 [5]
    8ia) (0,1) [1]
    8ib) (0,4) [1]
    8ic) a>1 0<b<1 [2]
    8ii) show that [5]
    9i) 15 [2]
    9ii) (2x+1)(2x-3)(x+1) [6]
    9iii) 2/3pi, pi, 4/3pi [4]

    Attachment 216632
    Attachment 216633
    Attachment 216634
    Attachment 216635
    Attachment 216636
    Attachment 216637
    THANKS AND how on earth did u manage to get the paper?!:O
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    Can someone please explain how they did 7 (ii)
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    Okay for 9ii) I got wrote (2x-3)(x+1) without the previous answer but then I wrote so x= -1/2 +2/3 or -1 will I lose a mark for having not written (2x+1)(2X-3)(X+1) ???
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    (Original post by HayyanN)
    Can someone please explain how they did 7 (ii)
    The method I used was one that I learnt for C1. I differentiated the curve and made the value for x equal to 4 to find the gradient at the point (4,7). Then I used y-y1=m(x-x1) to find out the equation of the tangent. After doing this I made y=0 to find where the tangent crossed the x axis. Then I integrated the tangent finding the area between x=4 and x=5/3. I then subtracted the value for the area under the tangent from the value for the area under the curve to get 37/30.
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    (Original post by HayyanN)
    Can someone please explain how they did 7 (ii)
    Integral - triangle of tangent with x-axis.
    Find tangent's equation:
    Spoiler:
    Show
    \dfrac{dy}{dx} =\frac{3}{2}x^{\frac{1}{2}}

\mathrm{When} \ x = 4 \Rightarrow \dfrac{dy}{dx} = 3

\Rightarrow y - 7 = 3(x-4) \Rightarrow y = 3x - 5

y = 0 \Rightarrow x = \dfrac{5}{3}


    Area:
    Spoiler:
    Show
    A = 9\frac{2}{5} - \frac{1}{2}\times (4 - \frac{5}{3}) \times 7 

\Rightarrow A = \dfrac{47}{5} - \dfrac{49}{6} = \dfrac{37}{30}
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    i got about 48 marks which is about a C....
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    (Original post by RooRoo1)
    Thanks for pointing this out. I'm not particularly gifted with maths, and my teacher got really ill so we've basically taught ourselves most of the c2 & s1 stuff. I didn't find the paper that easy, I think I got around 45-52 marks (I can't remember some of the answers I put). So just wanted to say thanks for putting it out there that not everyone found it easy!
    got about the same marks as you. what grade do you think that'll be?
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    I got 59-63 marks is that an A? (((((((((((
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    For 9ii I put (x+0.5)(2x+2)(2x-3) , which multiplies out the same- does anybody know if i will still get the marks- thanks
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    (Original post by owl 1996)
    For 9ii I put (x+0.5)(2x+2)(2x-3) , which multiplies out the same- does anybody know if i will still get the marks- thanks
    MrM is an OCR examiner - he'll be able to tell you if you post your question here.
    If it multiplies out the same, your working is correct, and the final answer is the same you will obtain full credit.
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    (Original post by geekD96)
    THANKS AND how on earth did u manage to get the paper?!:O
    Pick it up, walk out with it
 
 
 
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