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    (Original post by jo7777)
    Guys how do you find the minimum and maximum possible values of the midrange of a histogram?
    Please help!
    Q1: http://www.mei.org.uk/files/papers/2011_June_s1.pdf
    0+3000/2 = 1500
    and 1000+4000/2 = 2500 init
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    Can someone please help me regarding vertical line graphs... I have attached a pic of how I draw mine. Is that okay? Or do I have to make them chunkier to get the marks for mei S1? If that makes sense8) please help Name:  ImageUploadedByStudent Room1369324820.712910.jpg
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    (Original post by jo7777)
    the easiest one is (sum of x^2) - (n x mean^2)
    divided by n-1
    ALL SQUARED
    I used that one on a question I just did, and the mark scheme said it was wrong, I'm so confused!
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    (Original post by tryingtolearn95)
    Can someone please help me regarding vertical line graphs... I have attached a pic of how I draw mine. Is that okay? Or do I have to make them chunkier to get the marks for mei S1? If that makes sense8) please help Name:  ImageUploadedByStudent Room1369324820.712910.jpg
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Size:  152.4 KB


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    That looks fine :yy:

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    (Original post by Mo_maths)
    0+3000/2 = 1500
    and 1000+4000/2 = 2500 init
    Ahh thanks
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    (Original post by zangorou)
    I used that one on a question I just did, and the mark scheme said it was wrong, I'm so confused!
    You maybe put the numbers in wrong
    What's the question and I'll see if I can help
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    (Original post by zangorou)
    I used that one on a question I just did, and the mark scheme said it was wrong, I'm so confused!
    It's not all squared, it's all square rooted! If that wasn't the error then check your values in the calculator again.
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    (Original post by jo7777)
    You maybe put the numbers in wrong
    What's the question and I'll see if I can help
    Q2 part i

    http://integralmaths.org/resources/f...1/2005_Jan.pdf

    Thanks
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    (Original post by zangorou)
    I used that one on a question I just did, and the mark scheme said it was wrong, I'm so confused!
    These are the formulas and when to use which one

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    (Original post by SonamH)
    These are the formulas and when to use which one

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    Thank you!

    The standard deviation is the same though, I don't understand why it's not working
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    If anyone's got any queries or questions that they are stuck on I'm free to help as I've finished my revision now!
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    Can't get on there - don't have an account
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    I just did another question & the median was n/2!! UGH. I always Guess for n+1/2. I figure that in Cumulative Frequency questions its just n/2.
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    (Original post by TypoCool)
    If anyone's got any queries or questions that they are stuck on I'm free to help as I've finished my revision now!
    what is the probability that the exam is difficult given the previous exam was easy? LOL
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    (Original post by jo7777)
    Can't get on there - don't have an account
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    (Original post by Mo_maths)
    what is the probability that the exam is difficult given the previous exam was easy? LOL
    Lol, I'd say that it won't be too difficult! Not much more they can ask, take a look at the 2011 june series which is one of the harder ones, if you master that you' ll get an A for sure!
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    (Original post by DarkWillow)
    I just did another question & the median was n/2!! UGH. I always Guess for n+1/2. I figure that in Cumulative Frequency questions its just n/2.
    It is n+1 with frequency tables
    And it is n with cumulative frequencies only
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    (Original post by TypoCool)
    Lol, I'd say that it won't be too difficult! Not much more they can ask, take a look at the 2011 june series which is one of the harder ones, if you master that you' ll get an A for sure!
    Yeah the old ones don't look that bad but I'm kinda worried that mei may mess up the wording again like in c2 an the other june 2013 papers
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    (Original post by Mo_maths)
    Yeah the old ones don't look that bad but I'm kinda worried that mei may mess up the wording again like in c2 an the other june 2013 papers
    I have noticed that papers are becoming more wordy! But just remember that they want you to do all the things you've done in the mocks just in different situations and circumstances.
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    (Original post by zangorou)
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    So for i)
    mean is 83.95/8 = 10.49
    sum of squares:
    all of the x values squared is 881.2119
    881.2119 - 8 x 10.49^2 = 0.8911
    0.8911/7 = 0.1273
    square root of this is 0.357
    so standard deviation is 0.357

    Is that the correct answer?
 
 
 
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