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    (Original post by Mutleybm1996)
    4pi^2 / m


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    Where did you get m from? The formula we're given is T=2pi*root(L/g).

    the gradient of what?
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    (Original post by Mutleybm1996)
    4pi^2 / m


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    https://www.youtube.com/watch?v=8-CUDWndI74 stop at 3:32, it says g=4pi^2m.
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    (Original post by Mutleybm1996)
    You'll be ok! How did you find unit 1?

    Physics teachers are generally pretty rubbish at explaining things, Biology and Chemistry all the way


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    Unit one was shocking! OH DEAR OH DEAR OH DEAR ( pretty sure I am going to have to retake next year Curse Gove and his removal of the january exams) this video did cheer me up about it though
    https://www.youtube.com/watch?v=DIkSSqr1gfc

    I've got to say maths teachers are clearly the best kind of teachers. GO MATHS DEPARTMENT
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    (Original post by LimbuRonit)
    https://www.youtube.com/watch?v=8-CUDWndI74 stop at 3:32, it says g=4pi^2m.
    Pat 1:07 it says g= (L*4pi^2)/T^2 though!!! :/
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    (Original post by Carla Huynh)
    Pat 1:07 it says g= (L*4pi^2)/T^2 though!!! :/
    Ah I see what they've done. They've plotted L against T^2 so the gradient of this is m and therefore g=4pi^2*m
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    (Original post by Carla Huynh)
    Pat 1:07 it says g= (L*4pi^2)/T^2 though!!! :/
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    (Original post by Carla Huynh)
    Ah I see what they've done. They've plotted L against T^2 so the gradient of this is m and therefore g=4pi^2*m
    See above


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    g=4pi^2/m^2

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    (Original post by emfp21)
    g=4pi^2/m^2

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    The gradient squared?! Why?
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    FFs what the hell is going on!!!!!! my head is going to explode !!!!:eek:
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    Ok now I'm confused. That's in the form T^2=
    what would it be in the form g=?
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    (Original post by LimbuRonit)
    FFs what the hell is going on!!!!!! my head is going to explode !!!!:eek:
    Haha yup me too! Thought I understood it until everyone mentioned gradients! :/
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    (Original post by Carla Huynh)
    The gradient squared?! Why?
    Rearrange the equation and that's what you get, the gradient being of the graph T on the y axis, rootL on the x

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    (Original post by Carla Huynh)
    Haha yup me too! Thought I understood it until everyone mentioned gradients! :/
    Can't find a single perfectly explained video!!!! on pendulum
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    (Original post by emfp21)
    Rearrange the equation and that's what you get, the gradient being of the graph T on the y axis, rootL on the x

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    Oh ok I thought it would make more sense to plot T^2 against L so the. It would just be m not m^2...maybe I'm not sure!
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    (Original post by Carla Huynh)
    Oh ok I thought it would make more sense to plot T^2 against L so the. It would just be m not m^2...maybe I'm not sure!
    Depends on what they ask in the exam. Could be either

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    Guys, click on the link below and scroll to the bottom, there are questions and answers for predicted section C questions

    http://matthew-arnold.tmp.synergy-le...view.php?id=62
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    Also guys, just from judging by the G491 paper, I think there is an awfully good chance a question involving the estimation of wavelengths from different parts of the electromagnetic spectrum, so maybe give that a quick look?
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    (Original post by shloke123)
    Also guys, just from judging by the G491 paper, I think there is an awfully good chance a question involving the estimation of wavelengths from different parts of the electromagnetic spectrum, so maybe give that a quick look?
    Would you mind explaining that?? All we got told was radio waves have high wavelengths, then as you go through the spectrum to gamma wavelengths decrease due to higher frequency

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