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# OCR MEI - FP1 - 14th May 2015 watch

1. (Original post by MintyMilk)
Attachment 398155

Our unofficial mark scheme, (2 of us).

Pinch of salt.
1 is the wrong way round I think and 4 is definitely wrong
2. (Original post by Aph)
1 is the wrong way round I think and 4 is definitely wrong
Yeah 1 is the other way around. The diagram on the right for 4 is correct.
3. (Original post by Aph)
1 is the wrong way round I think and 4 is definitely wrong
Nah, look closely at the one labeled most likely this one. It's correct - I too thought they had shaded inside the circle when I looked, but nope so it's correct
4. (Original post by Aph)

Thanks
5. (Original post by Connorbwfc)
Yeah 1 is the other way around. The diagram on the right for 4 is correct.
But shouldn;t the shaded portion be enclosed by 2 lines, instead of 1? arg=0 and arg = pi/4
6. (Original post by Willtyler)
Nah, look closely at the one labeled most likely this one. It's correct - I too thought they had shaded inside the circle when I looked, but nope so it's correct
(Original post by Connorbwfc)
Yeah 1 is the other way around. The diagram on the right for 4 is correct.
no because iit was between 0 and pi/4 so it should've been a triangle with a point at -1-j not what they have drawn
7. (Original post by Buses)
But shouldn;t the shaded portion be enclosed by 2 lines, instead of 1? arg=0 and arg = pi/4
Oops, yeah it's wrong. There should be a horizontal line across at J=-1.
8. (Original post by Buses)
But shouldn;t the shaded portion be enclosed by 2 lines, instead of 1? arg=0 and arg = pi/4
Yeah you're right so question 4 is also wrong - I got that right in the exam thankfully
9. (Original post by Buses)
But shouldn;t the shaded portion be enclosed by 2 lines, instead of 1? arg=0 and arg = pi/4
exactly, and they haven't done that.
10. Did anyobe get something like this for the argand diagram?
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12. (Original post by Darcy1)
Did anyobe get something like this for the argand diagram?

Yes, but rotated the other way and with all the boundaries included.
13. (Original post by Aph)
exactly, and they haven't done that.
cool. what was your transformation matrix that got A''B''C'' to ABC (q9)
14. (Original post by Connorbwfc)
Yes, but rotated the other way and with all the boundaries included.
Yeah came out wrong in the picture LOL
15. (Original post by Buses)
cool. what was your transformation matrix that got A''B''C'' to ABC (q9)
For that i did T-1 times M-1 (the inverses)
16. (Original post by Buses)
cool. what was your transformation matrix that got A''B''C'' to ABC (q9)
I don't really remember
17. Was it something like: 1/48(0,8 top row. -6 4 bottom row) ?
18. How do you guys feel the difficulty of this paper was compared to the previous years ?
How do you guys feel the difficulty of this paper was compared to the previous years ?
slightly easier than last year. And less lengthy. Grade boundaries should remain the same as last year though
20. I think apart from the sigma question which is quite different from what people are used to, this years paper is one of the less difficult ones

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