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    Is the examiner for ch2 the same as Ch1?
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    Try going through your notes with a whiteboard and just keep scribbling things down again and again, it works for me
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    what specific examples/catalysts/reactions do we need to know... not processes and explanations, for CH1? any help would be vmapreeeeeciated
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    (Original post by VeepFan)
    what specific examples/catalysts/reactions do we need to know... not processes and explanations, for CH1? any help would be vmapreeeeeciated
    I don't think there's any. That's the good thing about ch1.
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    (Original post by goodies)
    I don't think there's any. That's the good thing about ch1.
    /amazing/
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    Name:  ImageUploadedByStudent Room1432242203.848143.jpg
Views: 166
Size:  40.4 KB How is the answer A. Someone explain plz


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    (Original post by dont leave blank)
    Name:  ImageUploadedByStudent Room1432242203.848143.jpg
Views: 166
Size:  40.4 KB How is the answer A. Someone explain plz


    Posted from TSR Mobile
    well find the number of moles in 16 grams of SO2, which is 16/64.1 = 0.2496 moles ------- 64.1 is the Mr of SO2

    you need to multiply 0.2596 by the Ar of Carbon (12) which gives: 0.2596 x 12 = 2.995 grams

    and 2.995 grams rounded up to give 3 grams
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    Can somebody please explain to me how to get the answer to the question right at the bottom of the image in this link: http://gyazo.com/1120ddfcb97f58f8e624e930dba0e257.

    It's the last question june 2010 incase you want to see it all.
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    (Original post by goodies)
    Can somebody please explain to me how to get the answer to the question right at the bottom of the image in this link: http://gyazo.com/1120ddfcb97f58f8e624e930dba0e257.

    It's the last question june 2010 incase you want to see it all.
    I think its the mass of K times 2 OVER total mass times 100

    Should be 56.6
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    (Original post by Faisalshamallakh)
    well find the number of moles in 16 grams of SO2, which is 16/64.1 = 0.2496 moles ------- 64.1 is the Mr of SO2

    you need to multiply 0.2596 by the Ar of Carbon (12) which gives: 0.2596 x 12 = 2.995 grams

    and 2.995 grams rounded up to give 3 grams
    Thanks 😅, i just couldn't think clearly...


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    Holy crap what a brilliant paper. I'm well pleased with that
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    (Original post by Jack1066)
    Holy crap what a brilliant paper. I'm well pleased with that
    What did you get for the last question?
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    Some questions were alright, but the calculations and that catalyst question....what the hell was going on. Might as well ask for my resit form right now.
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    (Original post by Questioner1234)
    What did you get for the last question?
    What was it?
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    (Original post by Jack1066)
    What was it?
    The calculations
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    I think I got the temperature rise wrong (I had 2 degrees but I don't think its right), but I had the concentration the same for both the Hcl and NaOH.

    So my energy released was wrong but I think I'll get error carried forward so I should get some marks
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    That was the most horrible paper ever?!
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    (Original post by Qwertykeyboard15)
    That was the most horrible paper ever?!

    I think it was a lot easier than the past papers I've done, I struggled on those but this I seemed okay...

    Knowing my luck though, its more likely I thought it was easy because I was doing it all wrong
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    (Original post by qwertykeyboard15)
    that was the most horrible paper ever?!
    i'm so glad someone agrees
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    Anyone get -1.3Kj mol-1 for the last calculations question??
 
 
 
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