You are Here: Home >< Physics

# OCR Physics A G484: 20th June 2016 Watch

1. (Original post by cookie_raider01)

wasn't the graph like this???
Yes but, you didn't have to draw the total energy right!!??
2. (Original post by cookie_raider01)

wasn't the graph like this???
Agreed but it didn't ask for total energy right?b
3. If possible blurt out as many numbers and answers as we can remember for all the questions and we can roughly see how we all did
4. (Original post by cookie_raider01)

wasn't the graph like this???
Though in the exam the PE curve didn't go down to zero, it was above the x axis
5. Guys, go to this thread, more people there, and answers already there:
http://www.thestudentroom.co.uk/show...670959&page=10
6. (Original post by cookie_raider01)

wasn't the graph like this???
I did my max kinetic energy lower at 50 mJ, as there was still 30mJ of EPE even at its minimum. There was never any 0 epe.
7. (Original post by cookie_raider01)

wasn't the graph like this???
That's what I done but realised after leaving the exam that there are springs both side so the minimum Elastic potential energy is only half the max value, and my minimum kinetic energy wasnt at zero which is obviously wrong

Posted from TSR Mobile
8. This is what I got:
9. what i can remember:

1) a) i put gradients were the same as it was when they were falling under gravity
b) i think i put collision was inelastic and energy was lost so i didnt return to the height it was dropped at to make a triangle of the same area
c) think i got around 3 ish ? it was sqrt(gh)
d) i think i got around 5ms
e) around 0.6?

2) was CA* 25* 1*10^3 to get 8.25 ?
b) i got an answer of 1070 newtons ?

a) A
b) phase difference was 7(pi)/4 ?

4)
a) people got different to me but i got 130 by (50*0.025*9.8*1.2)/(0.025)*(4.5)?
b) i said heat lost to surroundings and not all KE transferd to heat energy
c) i said the temperature rise would be the same as its independent of mass

5)
a) all i can remember writing is that as its an ideal gas internal energy is directley proportional to temperature (i didnt write in kelvin but that could be mark)

6)
a) i got -G(M1)*(M2)/(R1+R2)^2 ?
b) i got something like 4(pi^2)M1R1/T^2
c) (was a proof i cant remember)
d) was R1=1.2*10^11 and R2= 1.2*10^11
e) umm around 60000 ? cant remember
f) i got something like 10^33 but other people got around 10^40 by looking at forces forces

7)
a) umm not sure, was 20'000 moles ? and maybe 600m^2 ?
b) was around 11000 moles released ?
10. (Original post by AlexeiLipov)
How did people do the KE graph? Was your max KE at 50? And start from 0?
Yup, that's what I got.

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: June 20, 2016
Today on TSR

### 'Entry requirements are a form of elitism'

What do you think?

### Roommate kissed my boyfriend

Discussions on TSR

• Latest
• ## See more of what you like on The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

• Poll
Useful resources

## Make your revision easier

Can you help? Study help unanswered threadsStudy Help rules and posting guidelinesLaTex guide for writing equations on TSR

## Groups associated with this forum:

View associated groups
Discussions on TSR

• Latest
• ## See more of what you like on The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

• The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE