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    There are some questions I remember but couldn't do
    Any ideas on the answers?

    - The question with the circle with centre (a, 3). Another coordinate on the circle is P(4, -3). Find a

    - The logarithm question to convert log 2 y = 5 - log 2 x (the 2's should be small) into y^2 = k / x
    - How to solve the logarithm equation simultaneously with another equation I can't remember

    - How to find/prove r = 2 for the circle segment

    - The answer in the Sum of n question Where a = 97 and d = -3. I think I got 56
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    (Original post by charlesdarwin)
    What did you get for the trapezium rule?
    I got something like 14.553. I don't think I got the second part right though
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    (Original post by Raynedrops)
    I got something like 14.553. I don't think I got the second part right though
    yeah i got 14.555
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    (Original post by Raynedrops)
    I got something like 14.553. I don't think I got the second part right though
    Was the second part of that question somewhere around 132?
    (not sure if it was this question)
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    (Original post by charlesdarwin)
    What did you get for the trapezium rule?
    i think it was 14.556?
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    what did u get for (A) in centre of circle
    (Original post by Raynedrops)
    There are some questions I remember but couldn't do
    Any ideas on the answers?

    - The question with the circle with centre (a, 3). Another coordinate on the circle is P(4, -3). Find a

    - The logarithm question to convert log 2 y = 5 - log 2 x (the 2's should be small) into y^2 = k / x
    - How to solve the logarithm equation simultaneously with another equation I can't remember

    - How to find/prove r = 2 for the circle segment

    - The answer in the Sum of n question Where a = 97 and d = -3. I think I got 56
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    who else didnt have enough time?
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    (Original post by Arzam45)
    Yea that's what I got.
    a was 23? I think, idont remeber
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    (Original post by Arzam45)
    Was the second part of that question somewhere around 132?
    (not sure if it was this question)
    It was the equation in the integrate brackets but slightly different
    i) original equation / 2
    ii) 2 + original equation

    I think you were suppose to manipulate the answer in the first part
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    (Original post by azizmansoor)
    what did u get for (A) in centre of circle
    Nothing, I have no idea how to work out the answer!
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    What grade boundary for an A do you guys expect?
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    Can somebody please tell me a way to find the paper we did? I think teachers get the papers straight after the exam but I'm a private candidate so that's not going to work for me. Anybody have the paper as such?
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    June 14 was 80 it was easier so less than that I hope

    Posted from TSR Mobile
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    What is the answer of a in the circle question ? did any one get it as 25/8
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    i calculated a and it was 25/8 not sure tho
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    My equation for the circle was (x-a)^2+y^2=a^2. Since the point (4,-3) was a coordinate on the circle, I plugged in the numbers into my equation in order to get a.
    (4-a)^2+9=a^2.
    16-8a+9=0.
    a=25/8
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    Yup , thats exactly what i did
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    (Original post by EUSHA)
    im 100% sure it was 27/64 in the last one.
    it was area under line- area under curve.
    calculation was like this:integ(limit 2 to .5)[-.25x+.5]-integ(limit 2 to .5)[x^3-3x^2+2x]
    yup that was the answer.. I integrated from 1 to 0.5 as those were the points the curve was crossing the x-axis.. then subtracted area of the triangle from the integrated part
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    (Original post by Einsteinj.n.r)
    yup that was the answer.. I integrated from 1 to 0.5 as those were the points the curve was crossing the x-axis.. then subtracted area of the triangle from the integrated part
    Are you sure about this because i got 11/64
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    (Original post by queenoflean)
    My equation for the circle was (x-a)^2+y^2=a^2. Since the point (4,-3) was a coordinate on the circle, I plugged in the numbers into my equation in order to get a.
    (4-a)^2+9=a^2.
    16-8a+9=0.
    a=25/8
    Same

    Posted from TSR Mobile
 
 
 
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