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    For the sum I got -1/k for the product 1 and the the second part 1/k^2

    And for the difference method question I got the sum to infinity as 1/3 but others got 1/6 how about u?
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    I thought that was alright, at least compared to M2...
    I got:
    1)
    1/2 * n(n-1)(2n+3)
    2)
    i) sqrt(3)-3i
    ii) -1/49 + 4sqrt(3)/49 i
    3)
    i) alpha + beta = -1/k
    alpha * beta = 1
    ii) (alpha + 1/alpha) * (beta + 1/beta) 1/k^2
    4)
    i) (5a-3b 10 0)
    ii) (6b-5)
    iii) (6a 12 18)
    (4a 8 12)
    (-a -2 -3)
    5) [inductive proof]
    6)
    i) |z-3-3i| = sqrt(5)
    ii) [argand diagram]
    iii) 2 + 5i, 4 + i
    7)
    i) Shear, x axis invariant, (0,1) mapped to (3,1)
    ii) (0 -1)
    (-1 0)
    Reflection in y=-x
    8)
    i) [Show that]
    ii) n / 3(2n+3)
    iii) 1/ 2(2n+1)
    9)
    i) [Show that]
    ii) The equations were consistent
    10)
    i) +/- (5 + 4i)
    ii) [Show that]
    iii) +/- (5/41 +/- 4/41 i)
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    I think I got everything bar the argand diagram question (how many marks was that?) Strange times when C1 is harder than FP1
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    (Original post by farryharnworth)
    I thought that was alright, at least compared to M2...
    I got:
    1)
    1/2 * n(n-1)(2n+3)
    2)
    i) sqrt(3)-3i
    ii) -1/49 + 4sqrt(3)/49 i
    3)
    i) alpha + beta = -1/k
    alpha * beta = 1
    ii) (alpha + 1/alpha) * (beta + 1/beta) 1/k^2
    4)
    i) (5a-3b 10 0)
    ii) (6b-5)
    iii) (6a 12 18)
    (4a 8 12)
    (-a -2 -3)
    5) [inductive proof]
    6)
    i) |z-3-3i| = sqrt(5)
    ii) [argand diagram]
    iii) 2 + 5i, 4 + i
    7)
    i) Shear, x axis invariant, (0,1) mapped to (3,1)
    ii) (0 -1)
    (-1 0)
    Reflection in y=-x
    8)
    i) [Show that]
    ii) n / 3(2n+3)
    iii) 1/ 2(2n+1)
    9)
    i) [Show that]
    ii) The equations were consistent
    10)
    i) +/- (5 + 4i)
    ii) [Show that]
    iii) +/- (5/41 +/- 4/41 i)
    I think I got the same answers for the questions I remember so that's pretty good but am gutted I couldn't do the last question
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    (Original post by Bobby21231)
    For the sum I got -1/k for the product 1 and the the second part 1/k^2

    And for the difference method question I got the sum to infinity as 1/3 but others got 1/6 how about u?
    I got the same as you for both of those.
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    I have a feeling it was 2/3 for the argand diagram and 3 for the pints of intersection but I could be wrong
    (Original post by SGHD26716)
    I think I got everything bar the argand diagram question (how many marks was that?) Strange times when C1 is harder than FP1
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    (Original post by farryharnworth)
    I thought that was alright, at least compared to M2...
    I got:
    1)
    1/2 * n(n-1)(2n+3)
    2)
    i) sqrt(3)-3i
    ii) -1/49 + 4sqrt(3)/49 i
    3)
    i) alpha + beta = -1/k
    alpha * beta = 1
    ii) (alpha + 1/alpha) * (beta + 1/beta) 1/k^2
    4)
    i) (5a-3b 10 0)
    ii) (6b-5)
    iii) (6a 12 18)
    (4a 8 12)
    (-a -2 -3)
    5) [inductive proof]
    6)
    i) |z-3-3i| = sqrt(5)
    ii) [argand diagram]
    iii) 2 + 5i, 4 + i
    7)
    i) Shear, x axis invariant, (0,1) mapped to (3,1)
    ii) (0 -1)
    (-1 0)
    Reflection in y=-x
    8)
    i) [Show that]
    ii) n / 3(2n+3)
    iii) 1/ 2(2n+1)
    9)
    i) [Show that]
    ii) The equations were consistent
    10)
    i) +/- (5 + 4i)
    ii) [Show that]
    iii) +/- (5/41 +/- 4/41 i)
    I agree with all of these except 8iii, which IIRC was a sum to infinity, so shouldn't have an n anywhere in it. <- THIS IS WRONG I CAN'T ****ING READ
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    (Original post by sdhand)
    I agree with all of these except 8iii, which IIRC was a sum to infinity, so shouldn't have an n anywhere in it.
    I'm fairly sure it was a sum from n to infinity
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    (Original post by sdhand)
    I agree with all of these except 8iii, which IIRC was a sum to infinity, so shouldn't have an n anywhere in it.
    Between n and infinity so the sum from 1 to n-1 needs to be defined in terms of n


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    (Original post by farryharnworth)
    I'm fairly sure it was a sum from n to infinity
    ****, if that's true I didn't read the question correctly. There goes some marks.
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    Was also 1/blah instead of 2/blah as shown in part i


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    (Original post by farryharnworth)
    I'm fairly sure it was a sum from n to infinity
    I think there was just a sum
    To infinity as well as this
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    (Original post by sdhand)
    I agree with all of these except 8iii, which IIRC was a sum to infinity, so shouldn't have an n anywhere in it.
    Actually the lower limit was n, so you had to subtract the equation with n-1 substituted for n. Their answer is right.
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    (Original post by drandy76)
    Was also 1/blah instead of 2/blah as shown in part i


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    Yeah I'd don't read the 2 as well
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    (Original post by Bobby21231)
    Yeah I'd don't read the 2 as well
    Same lol. Think I'll have got 0 for that one.
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    Was a pretty good paper, only thing i fear now is very high boundaries :s
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    (Original post by sdhand)
    Same lol. Think I'll have got 0 for that one.
    At least it weren't just me Do u know how many marks it was?
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    (Original post by Bobby21231)
    At least it weren't just me Do u know how many marks it was?
    Think between 3 and 5, don't know for sure though.
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    (Original post by sdhand)
    Think between 3 and 5, don't know for sure though.
    Okay thanks I'm hoping I will have only dropped 10 marks at most as I know I lost 4 on the last question and then some on here
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    (Original post by Bobby21231)
    Okay thanks I'm hoping I will have only dropped 10 marks at most as I know I lost 4 on the last question and then some on here
    I think I dropped about 10 as well. Should be a low to middling A if the previous years grade boundaries are anything to go by.
 
 
 
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