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    It was mostly the small things that tripped me up, like 6(e), I didn't expressly state R=R^-1.
    Question 7 was ****ed, if you couldn't get a... quite harsh from the exam board no? I'm sure there'd be carry through marks.
    7(e) wasn't nice,
    8(i) took me a while to spot and my proof looks pretty shoddy, dunno how convincing to the examiner...
    9(c)
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    Hi, for 7(e) I was wondering if this answer is accepted?

    Line QR is the image of line OP under an enlargement of scale factor 2 with centre (0,0) followed by translation (-3,-4)
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    For part (a) of the summation series question, (the 1 marker) I put
    ... 3n/6(3n+1)(6n+1) would that get me the mark? Thanks
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    (Original post by TrueDAN)
    Everyone commenting top 60s and 70s and I think I've came in with a low blow in the 50s Really disheartened by it, I guess we all have a bad test though. I predict I will have a D/C which sucks, really thought I had this module down. Damn, I guess we all have a bad test though, will definitely resit it, congrats to all you geniuses getting these insane marks!
    People who didn't get a high mark are less likely to post what they got. Don't worry about it.
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    (Original post by CostaMiyagi)
    Thank you Arsey! 61/75 not too bad
    we got the same marks i think, hoping that this is an A!
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    I did Worse than I thought, 67/75.
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    (Original post by CostaMiyagi)
    Thank you Arsey! 61/75 not too bad

    we got the same marks i think, hoping that this is an A!
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    (Original post by iMacJack)
    Daddy Donny will be proud enough - at least we did a harder paper than Ivan and did better
    what was the best uni he got an offer from surry? Because at least we know we can get there
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    (Original post by NoahMal)
    what was the best uni he got an offer from surry? Because at least we know we can get there
    Lol yeah with a bit of luck maybe
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    (Original post by hogree)
    Midpoint is always (a+b)/2 not (a-b)/2

    Posted from TSR Mobile
    Hmm I see what I was trying to do. I found the distance of x and y from A but forgot to add it to the coordinates of A..... Excuse me while I go shoot my foot
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    (Original post by ilovetacobell)
    we got the same marks i think, hoping that this is an A!
    Should be if everyone is finding it hard
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    (Original post by Arsey)
    Here are my solutions to the FP1 paper.

    Reasonable paper I thought, a few tricky bits
    May I ask question, I did qp=-1 then q=-1/p so the gradient of q become -p. The gradient of p is 1/p. And I state because they are inverse function so they are perpendicular(can't remember what I exactly said) can I still get the mark?
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    Quick poll on
    http://www.thestudentroom.co.uk/show....php?t=4101989
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    max lost 10 marks , is that an A?
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    (Original post by kewjing)
    May I ask question, I did qp=-1 then q=-1/p so the gradient of q become -p. The gradient of p is 1/p. And I state because they are inverse function so they are perpendicular(can't remember what I exactly said) can I still get the mark?
    Well here's what I did;

    pq = -1 from the previous part

    1/p = grad of tangent at p
    therefore grad of tangent at q = 1/q

    So for them to be perpendicular the product of the gradients = -1

    1/p * 1/q = 1/pq = -1 as pq = -1 from the previous part
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    (Original post by Pyslocke)
    Why is the midpoint of AP (5p - 5/p + 5p) / 2?

    Why isn't it [5p - (-5/p +5p)] / 2 = 5/2p.

    Am I going mad again?


    EDIT: I know that using this method I get p = 0 so x would be undefined as shown. But I was still lost
    midpoint is (x1+x2)/2 (y1+y2)/2
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    (Original post by kelvin1338)
    Hello Arsey,

    For the sequence induction question, do I have to prove it's true for n=2 as well? Would I have lost a mark in not doing so?
    Could you please tag me when he answers? Thanks
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    (Original post by iMacJack)
    Well here's what I did;

    pq = -1 from the previous part

    1/p = grad of tangent at p
    therefore grad of tangent at q = 1/q

    So for them to be perpendicular the product of the gradients = -1

    1/p * 1/q = 1/pq = -1 as pq = -1 from the previous part
    Can I still get the mark if I just compare two gradient as m1=-q and m2=1/q
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    (Original post by kewjing)
    Can I still get the mark if I just compare two gradient as m1=-q and m2=1/q
    How did you get to that point?
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    Anybody have any ideas of grade boundaries, I think I might of just scraped an A which is good for me coming from a mid C from last years paper.
 
 
 
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