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    (Original post by ethanol99)
    Difference between U9 & U10 is incorrect.
    Answer is 1.601
    He probably used ar^n
    oh i didn't see him put that. I got the same as you (1.601)
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    (Original post by AstarAstarA)
    It was the difference between ar^9 and ar^10 wasn't it?
    a = 64
    r = 3/4

    Can someone confirm?
    you're wrong here mate. It's ar^n-1, not ar^n
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    (Original post by AstarAstarA)
    It was the difference between ar^9 and ar^10 wasn't it?
    a = 64
    r = 3/4

    Can someone confirm?
    it was the difference between U9 and U10
    which is ar^8 and ar^9
    so the difference was 1.601
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    As the formula is ar^(n-1) it would've been ar^8 and ar^9 as it was the 9th and 10th tern
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    (Original post by TeeEm)
    Is this the new arsey?
    http://www.thestudentroom.co.uk/show...ighlight=arsey

    I can't
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    Such is life
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    I posted a few more here http://www.thestudentroom.co.uk/show...3#post65151283, also included marks
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    (Original post by X_IDE_sidf)
    I posted a few more here http://www.thestudentroom.co.uk/show...3#post65151283, also included marks
    Snake
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    (Original post by AstarAstarA)
    Snake
    hissss. What do you mean by snake
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    (Original post by richpanda)
    you're wrong here mate. It's ar^n-1, not ar^n
    yeah i did that because the geometric series goes like this: a,ar,ar^2,ar^3.
    therefore when n=9 its ar^8 and when n=10 its ar^9.
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    (Original post by eftio.gea)
    Guys wasn't part a of Q9 = 1/3pi(x^2)????

    because the sector area is 1/2r^2(theta)
    which is 1/2(x^2)(2/3pi)

    = 2/6pi(x^2)
    = 1/3pi(x^2)
    ??
    I agree
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    (Original post by Student1408)
    yeah i did that because the geometric series goes like this: a,ar,ar^2,ar^3.
    therefore when n=9 its ar^8 and when n=10 its ar^9.
    i did this and got 1.602.. to 3d.p... anyone else got 1.602 or most got 1.601?
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    (Original post by big willy)
    gr8 100%


    Shut up small willy.
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    Well this resit has knocked my confidence for C3 and C4
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    (Original post by AstarAstarA)
    Geometric:
    b) 256
    c) 1.601

    Binomial:
    A = 16
    k = 7/2
    B = 936

    Integration:
    S = 24.3

    Trapezium:
    a) 7
    b) 20.75
    c) R = 5.75

    Factor theorem:
    a) 5
    c) (x + 2)(3x + 2)(2x - 1)

    Differentiation(Q10):
    a) 1/3PIx^2
    d) Minimum = 120m
    c) x = 16.63... => f''(x) = 0.437 > 0

    Trig identities:
    a) Theta = 8/15Pi , -2/15Pi
    b) x = 194.5, 345.5

    Circle:
    a) root(34)
    c) 3x + 5x - 95 = 0

    Log:
    i) (a - 5)/9
    ii) -2.19
    For the trig I used both a cast diagram and a sin graph to help me answer it, will that be accepted?
    I got the answer right but i didnt make it obvious that i used CAST
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    Wasn't the difference in the geometric sequence supposed to be given to 3.sf, so 1.60?
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    yea i got that
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    am I the only one who found C1 easier than C2 ?
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    (Original post by NotNotBatman)
    Wasn't the difference in the geometric sequence supposed to be given to 3.sf, so 1.60?
    No, i think it said 3 decimal places
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    (Original post by NotNotBatman)
    Wasn't the difference in the geometric sequence supposed to be given to 3.sf, so 1.60?
    3 decimal places anyone?
 
 
 
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