# 2016 May 25th Edexcel Core 2 Questions and answers. [Unofficial mark scheme] 2016Watch

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#61
(Original post by jenna191)
wait wait when u integrate for area do uhave to have a +C ?
yes, there are no limits.
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2 years ago
#62
According to this 67+/- 3 marks and that was being harsh on the markings

I would be surprised on the grade boundaries were higher than average as it was pretty average/easy
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2 years ago
#63
(Original post by jenna191)
wait wait when u integrate for area do uhave to have a +C ?
Doubt it, as it disappears when you do the bounds
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2 years ago
#64
I calculated my predicted UMS score and I got 234-235 ( from the 2015 grade boundaries), is that still a B.
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2 years ago
#65
(Original post by jenna191)
wait wait when u integrate for area do uhave to have a +C ?
When you integrate you get = x+c
However when you are trying to find an area for values between a and b
b+c -(a+c) the constants don't change no matter what x is so it's safe to cancel them out instantly.
b-a+c-c = b-a
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#66
(Original post by Dieselblue)
When you integrate you get = x+c
However when you are trying to find an area for values between a and b
b+c -(a+c) the constants don't change no matter what x is so it's safe to cancel them out instantly.
b-a+c-c = b-a

The question didn't have limits at that point, part (a) was simply
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2 years ago
#67
Im pretty sure 8i was write B in terms of A?
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2 years ago
#68
I did that too omg thought I was the only one! So the negative value is right

QUOTE=Qweudhs56;65157369]1.b. Is wrong. The answer is -1.602. It has to be negative because in geometric sequence, the biggest term is subtract by the smallest.

Therefore 64(3/4)^9 - 64(3/4)^8 = -1.602 (to three decimal places).

P.S. I don't know if the markscheme would say 'ignore' signs.[/QUOTE]
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2 years ago
#69
(Original post by LuckyMN)
I calculated my predicted UMS score and I got 234-235 ( from the 2015 grade boundaries), is that still a B.
Its 240 for an A so not too far off, if you're lucky you might get an A
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2 years ago
#70
(Original post by X_IDE_sidf)
PDF COPY: http://www.thestudentroom.co.uk/atta...7&d=1464189347

1 Geometric series question, prove given and then workout sum to infinity. Then find the difference between the 9th and 10th term

2 Trapezium rule. in the interval with 4 trapeziums

3 Circle centred at . Find the equation of it and of a tangent at point

4 where find the remainder when divided by then factorise it fully given is a factor.

5 Expansion of . The using that expand in the form given the coefficient of

6 solve for and

7 This was and then find the limits (where it crossed the axis.

8 , write b in terms of a then find given .

9 Find optimum perimeter of a funny shape which comprised a rectangle, sector and a equilateral triangle, need diagram.
Image by Cake_Chan
Equations given, that needed proving are,
and

1 a) (2 marks) proof
b) (2 marks)
c) (2 marks)

2 a) (1 mark)
b) (3 marks)
c) (2 marks)

3 a) (2 marks)
b) (3 marks)
c) (4 marks)

4 a) (2 marks)
b) (2 marks)
c) (4 marks)

5 a) (4 marks)
b) (1 mark)
c) (2 marks)
d) (2 marks)

6 i) (3 marks) or
ii) (6 marks) or

7 a) (3 marks)
b) (3 marks)

8 i) (3 marks)
ii) (4 marks)

9 a) (2 marks)
b) (3 marks) proof
c) (3 marks) proof
d) (5 marks)
e) (2 marks) is a minimum at

This is useful and was spread out over another thread so I thought I would post it here. The missed answers were all either proofs or not suited to a single number response.

Thank you new arsey
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2 years ago
#71
feeling so much better after seening even if i did good or bad lol
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2 years ago
#72
(Original post by Randall13)
for the first part of the logs

I said 1/3 = 3b+1/a-2

then 1/3a -2/3= 3b+1

1/3a-5/3=3b

1/3a-5/3 all divided by 3 = b

Is this correct and how many marks would i lose if incorrect?
Nope, there's a mistake here.
1/3 = (3b+1)/(a-2) is right, but you mutliplied out 'a' wrong
It should be
3b+1 = a/3 - 2/3
3b = a/3 - 5/3
3b = (a-5)/3
b = (a-5)/9
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2 years ago
#73
I did that too! The difference was negative thiugh so I hope it's right

QUOTE=Fatmanlolololol6;65158247]I am quite pissed. I got full marks in this paper, but for question 1.b. I wrote -1.602. Would that be penalised? And does that mean I can still get full UMS?[/QUOTE]
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2 years ago
#74
(Original post by Failedexamms)
I did that too! The difference was negative thiugh so I hope it's right

QUOTE=Fatmanlolololol6;65158247]I am quite pissed. I got full marks in this paper, but for question 1.b. I wrote -1.602. Would that be penalised? And does that mean I can still get full UMS?
[/QUOTE]

The difference was positive, difference means that |u9-u10| = |u10-u9|, so the answer had to be positive, you'd get away with 1 mark though
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2 years ago
#75
For question 8i would this be a valid way to get to the answer?
I did it this way during the exam but everyone I've spoken to seems to have done it a different way.

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2 years ago
#76
(Original post by UKoE Luna)
For question 8i would this be a valid way to get to the answer?
I did it this way during the exam but everyone I've spoken to seems to have done it a different way.

That method looks perfectly fine, i would worry about it aha
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2 years ago
#77
(Original post by SLamb)
That method looks perfectly fine, i would worry about it aha
Awesome Thanks for clearing that up I wasn't quite sure if I was just allowed to remove the logs like that.
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2 years ago
#78
any idea what the grade bondaries might be
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#79
(Original post by Failedexamms)
I did that too! The difference was negative thiugh so I hope it's right
(Original post by Fatmanlolololol6)
I am quite pissed. I got full marks in this paper, but for question 1.b. I wrote -1.602. Would that be penalised? And does that mean I can still get full UMS?
(Original post by Failedexamms)
I did that too omg thought I was the only one! So the negative value is right
(Original post by Qweudhs56)
1.b. Is wrong. The answer is -1.602. It has to be negative because in geometric sequence, the biggest term is subtract by the smallest.Therefore 64(3/4)^9 - 64(3/4)^8 = -1.602 (to three decimal places).P.S. I don't know if the markscheme would say 'ignore' signs.
I have no idea what is meant by ' It has to be negative because in geometric sequence, the biggest term is subtract by the smallest.'. The question just asked for the difference. This would imply that the answer should be positive. However, I feel that it should be positive but they will not penalise you in the mark scheme.To put this to rest finally, I found this in jan 2006: which prooves my point
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2 years ago
#80
Hi guys

if i put 5y + 3x - 95 = 0, will i still get the mark even though it said put it as 'ax + by + c = 0'?
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