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# Edexcel Physics IGCSE 1P Unofficial Mark Scheme 25th May 2016 watch

• View Poll Results: How did you find the exam?
95% - 100%
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1. (Original post by JKram)
81.6%, you might get an A or an A* depending on what the boundary is set at. Over the last few years it's averaged around 82% so you might be lucky!
82%??? crap
2. (Original post by cornflakeexpert)
82%??? crap
no its hasnt it was 76 last year and that paper was so mucheasier than ours . It will be low 70s
3. Man, that exam was a disaster. Whats with the bear thing ffs ??
4. (Original post by conradliebers)
2.h)
Orbital Speed = 17123.28767km/hr (3)
Thank you for putting this mark scheme online. Really appreciate it. One thing though; I am pretty sure that it said that 150,000,000km was the radius, not the circumference.

So wouldn't it be
150,000,000 * 2 * pi = 94247796.1km
365 * 24 = 8760

so divide the first by the second to get 107588.7895km/h
roughly equal to 108000km/h
5. (Original post by akaash13)
Thank you for putting this mark scheme online. Really appreciate it. One thing though; I am pretty sure that it said that 150,000,000km was the radius, not the circumference.

So wouldn't it be
150,000,000 * 2 * pi = 94247796.1km
365 * 24 = 8760

so divide the first by the second to get 107588.7895km/h
roughly equal to 108000km/h
Yes I think that was right yes, I remember it now. It was because a friend told me that and I got confused.
6. (Original post by akaash13)
Thank you for putting this mark scheme online. Really appreciate it. One thing though; I am pretty sure that it said that 150,000,000km was the radius, not the circumference.

So wouldn't it be
150,000,000 * 2 * pi = 94247796.1km
365 * 24 = 8760

so divide the first by the second to get 107588.7895km/h
roughly equal to 108000km/h
I got that as well, can you answer my other question on the other page?
7. (Original post by aaljhfgahsj)
Guys for the question about the speed of the train I got 8.48... So 8.5(3sf) but a lot of people are saying its 12... Which it could be, but correct me if I am wrong but the question wanted the velocity of the train..so v=square root of ke/halfxmass, and I'm pretty sure the ke was given in MJ (so times by 1mil), and when you do that it gives you my answer...so which one is correct, and if it is 12 can someone plz explain?
Hi again,

This is how I got 12.

I believe it was something like 1.8MJ, which you divide by one half (i.e. Multiply by two) to get 3.6MJ because the equation is 1/2 times m times velocity squared. This gives mass times velocity squared. Then divide by mass which was 25000 kg I think to get 144 and square root to get 12. I think that you forgot to multiply by 2 because I di the calculation without multiplying by 2 and I got what you got.
8. (Original post by akaash13)
Hi again,

This is how I got 12.

I believe it was something like 1.8MJ, which you divide by one half (i.e. Multiply by two) to get 3.6MJ because the equation is 1/2 times m times velocity squared. This gives mass times velocity squared. Then divide by mass which was 25000 kg I think to get 144 and square root to get 12. I think that you forgot to multiply by 2 because I di the calculation without multiplying by 2 and I got what you got.
Ok thanks...hopefully grade boundaries will be lower this year haha
9. (Original post by JKram)
81.6%, you might get an A or an A* depending on what the boundary is set at. Over the last few years it's averaged around 82% so you might be lucky!
Sorry to point out but this is a ludicrous statement. Grade boundary has only ever crept to 142/180 once and only ever been over 140 once. For those interested the % of 142/180 is 79%, far too high for the paper. In recent years the grade boundary has hovered around 132-136 for the a*, however in more difficult years it has dropped to mid to high 120's.

Also, I believe 3a) was around 142 or 3 kPa can't remember now, don't think it was in the thousands
10. (Original post by Job738338)
and we have maths tommorow
yup!!!!!
11. Does anyone have a drawing of what the TIR into the jewl is supposed to look like?
12. 2b) thermal not kinetic
13. I hope g boundaries are low but grade boundary has been above 142/180 Olijones100, for jan 2016 it was 145/180
also i'm pretty sure the measurement between 2 dots was 5.4 not 5.3
14. (Original post by willp12345)
2b) thermal not kinetic
its kinetic

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15. (Original post by willp12345)
2b) thermal not kinetic
It is kinetic. I've done enough past papers to know.
16. (Original post by qazwaz)
I hope g boundaries are low but grade boundary has been above 142/180 Olijones100, for jan 2016 it was 145/180
also i'm pretty sure the measurement between 2 dots was 5.4 not 5.3
It's a rough measurement, the mark scheme will give a range. I wrote 6.3 because the image it gave wasn't exactly perpendicular/straight so it looked a bit like some parallax error.
17. (Original post by Olijones100)
Sorry to point out but this is a ludicrous statement. Grade boundary has only ever crept to 142/180 once and only ever been over 140 once. For those interested the % of 142/180 is 79%, far too high for the paper. In recent years the grade boundary has hovered around 132-136 for the a*, however in more difficult years it has dropped to mid to high 120's.

Also, I believe 3a) was around 142 or 3 kPa can't remember now, don't think it was in the thousands
You use the formula P1V1 = P2V2

If the first pressure you use is 101kPa and the volume is 1700 litres, you multiply them to get 171700. Because volume 2 was 12 litres, you simply divid 171700 by 12 in order to get the value which is already in kPa which is 14308.3kPa. Agreed?
18. (Original post by conradliebers)
It is kinetic. I've done enough past papers to know.
both are given a mark

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19. (Original post by conradliebers)
You use the formula P1V1 = P2V2

If the first pressure you use is 101kPa and the volume is 1700 litres, you multiply them to get 171700. Because volume 2 was 12 litres, you simply divid 171700 by 12 in order to get the value which is already in kPa which is 14308.3kPa. Agreed?
Yes youd get all 3 marks for that

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20. (Original post by ursulab)
Does anyone have a drawing of what the TIR into the jewl is supposed to look like?
Diagonally to right, horizontally left, diagonally right

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