# Edexcel GCSE Maths Paper 1 Help ThreadWatch

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#61
If anyone has more questions I won't be able to reply from now as I won't be online. Best of luck in the exam to everyone! 😊
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2 years ago
#62
(Original post by Habiba12)
go on https://www.youtube.com/watch?v=-z4SUypJZxo its a bit annoying but trust me itll stay in your head i heard this once in yr 7 and i still remember it helps with circles and pi
LOOL its funny! & Ty
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2 years ago
#63
(Original post by TJ2001)
Proof is hard to explain over typing, this short video may help.. http://m.youtube.com/watch?v=DxODoNGetVY
With vectors the basic rule to remember is if the are multiples they're parallel, and if they're multiples and share a common point it's a straight line. Sometimes it can be very hit or miss with the complicated problems but providing you remember those rules you can give it a good go.
Surds again can be very hit or miss, but this short video should outline the basic principle - http://m.youtube.com/watch?v=Aq8FavvjSII - and a video is probably easier to understand that if I was to try and type out an explanation.
Congruent triangles, make sure you remeber the four rules of what needs to be equal to be congruent.
SSS (three side)
AAS (two angles and corresponding side)
SAS (two sides and included angle)
RHS (right angle, hypotenuse, side)
For similar shapes know these rules and you'll be fine...
(K being the scale factor)
Length - times by K
Surface area - times by K^2
Volume - time by K^3

Hope this has helped. Good Luck in the exam 😊
Thanks
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2 years ago
#64
I have a test tomorrow I'm in college doing level 2 do you think these questions will be on the test
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2 years ago
#65
Anyone can help?
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2 years ago
#66
Anyone can help?

Here. Sorry can't explain it - don't have time, going to bed now.
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2 years ago
#67
Anyone can help?
The size of each angle in an n-sided regular polygon is You can use this to find the size of each angle in the octagon.

Use to find the sum of angles in the hexagon.

And the size of the unknown angles in the hexagon will be equal, so you can work that out by dividing (the sum of angles in a hexagon - 280) by 4.
1
2 years ago
#68
Anyone can help?
In regular Octagon
Ex.Angle = 360/8 = 45 degrees
Int.Angle- 180-45 = 135 degrees

JK is line of symmetry so draw line of symmetr to divide hexagon into two trapeziums. Now the angle 140 degrees has been split into two so now angle JKF and angle KJF are each equal to 70 degrees.

In a trapezium, there a two paralell lines therefore interior angles can add up to 180 degrees. 180-70= 110 degrees

Now take angle inside trapezium away from interior angle of octagon:
135- 110 = 25 degrees
2
2 years ago
#69
how do you work out the surface area of a solid hemisphere?
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2 years ago
#70
(Original post by Yasminxb)
how do you work out the surface area of a solid hemisphere?
Half of the surface area of a sphere + area of a circle

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2 years ago
#71
(Original post by Yasminxb)
how do you work out the surface area of a solid hemisphere?
Surface area of a whole sphere is . So half of that outer surface would be but you have to remember because you 'cut' the sphere in half there is a circle face at the bottom of the hemisphere so we have to add on .
So as the other user said the total surface area of a hemisphere is .
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2 years ago
#72
(Original post by TheOtherSide.)
Half of the surface area of a sphere + area of a circle

(Original post by B_9710)
Surface area of a whole sphere is . So half of that outer surface would be but you have to remember because you 'cut' the sphere in half there is a circle face at the bottom of the hemisphere so we have to add on .
So as the other user said the total surface area of a hemisphere is .
thank youu
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2 years ago
#73
Right its hard to explain but you need to find the midpoint of the current line first. Then this will give you an x and y co-ordinate which you use later on. You then have to find the gradient from the current line, it will either be in an equation you are given or you will have to work it out from the diagram given (height÷length). This gradient will probably be in a fraction form, you flip this fraction to find the gradient of the perpendicular line. Then tou have to substitute everything you have found out into the equation y=mx+c...so... you would take the x and y from the midpoint and the gradient (m). Then you just need to make c the subject of your equation.then finally substitue the gradient and c into your equation y=mx+c to get your new equation for the perpendicular line.... sooo recap.
-find the midpoint xy
-find the gradient of current line (ab)
-find the gradient of new line (ab flipped)
-substitue the gradient and x and y into y=mx+c
-then find c and substitue one last time to get you answer

I hope this made some sense... good luck!

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2 years ago
#74
(Original post by Jaff_)
Yo! Can someone explain the alternate segment therom and proof about consecutive numbers. Thanks, much appreciated!
Always use n and n+1 to show consecutive numbers, there was one a few years back about the difference of two squares of consecutive numbers and it was a case of multiplying n squared and n+1 squared and collecting like terms, sorry if it's vague
Good luck!
L
0
2 years ago
#75
Yo guys I did my IGCSE Maths a year early in 2015 June, got 97% lol. Anyways, reply to this or PM me if u got any questions, free and happy to help (if I can) lol!
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