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# WJEC C3/C4 8th/17th June 2016 Watch

1. (Original post by Ayaz789)
I silll am quite sure im right :/
All you do on that one is e^3
2. (Original post by Salamon16)
No
Idek , anyone got the unofficial ms
3. (Original post by Mango88)
a and b values for transformations?

a=-5
a=3
B=-2/3
4. (Original post by Sznsnsn)
All you do on that one is e^3
Like look in part b , thats exactly what i did tbh
5. (Original post by Sogolhosseini)
a=-5
a=3
B=-2/3
I got a=5 & a=-3
6. (Original post by Ayaz789)
I silll am quite sure im right :/

7. (Original post by Ayaz789)
Like look in part b , thats exactly what i did tbh
That's because that one is just on its own not a power of an exponential
8. (Original post by 98matt)
What about the parametric differentiation q where you had to give the second derivative in terms of y?

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-1/y^3
9. (Original post by Sznsnsn)
That's because that one is just on its own not a power of an exponential
Well i should still get an A* hopefully considering i messed that and 5a up!
10. (Original post by Sogolhosseini)

^^^^^
It's just times by e^3
11. (Original post by FusionNetworks)
-1/y^3
YES ! I had that too I think

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12. (Original post by Ayaz789)
I got a=5 & a=-3
Agree
13. WJEC need to sort out this gardening obsession of theirs

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14. (Original post by Ayaz789)
I got a=5 & a=-3

Yea yea you are right. The I forgot the the shape for a sec
15. what did you get for d2y/d2x in terms of t
16. So for hh(x), was h-1(x) = h(x)?
17. (Original post by FusionNetworks)
So for hh(x), was h-1(x) = h(x)?
Yeah and then 1/9 when subbed the value in?
18. (Original post by FusionNetworks)
So for hh(x), was h-1(x) = h(x)?
Yeah I did that, and for b i got 1/9
19. (Original post by Mango88)
what did you get for d2y/d2x in terms of t
If I remember correctly: -1/8cos^3(3t)
20. What did you guys do for 2 part b?

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