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    (Original post by Puddles the Monkey)
    In order of how many posts each person made :innocent:
    Thought so!
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    (Original post by IrrationalRoot)
    physicsmaths


    Did you end up trying Q4 of STEP I 2015 afterwards?
    Na mate I ain't looked at the paper since i sat it haha!


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    (Original post by Krollo)
    Doing II 2014 today if anyone wants to join me.

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    Good luk lad
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    new thread who dis?
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    (Original post by IrrationalRoot)
    Thought so!
    If you're interested:

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    How did I get into the top ten. *shrugs*
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    (Original post by Zacken)
    If you're interested:

    Yes no. 4! And then there's Zacken...
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    (Original post by EricPiphany)
    How did I get into the top ten. *shrugs*
    Who's in your picture
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    (Original post by physicsmaths)
    Na mate I ain't looked at the paper since i sat it haha!


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    Ah, you should try it though, nice geometry Q that I left out in my mock since for my 6th I decided to do Q3 instead of Q4. It's geometry without vectors, which I always like .
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    (Original post by gasfxekl)
    Who's in your picture
    I don't know, to be honest. Not me.
    For your viewing pleasure:
    Spoiler:
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    (Original post by Puddles the Monkey)
    I TOLD YOU NOT TO CLICK! :shakecane:
    I clicked
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    TSR Community Team
    (Original post by Gregorius)
    I clicked
    May you scroll for eternity with only yourself to blame :shakecane:
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    Am I being really stupid or something? If P divided the line AB in the ratio t:1, I would think that would mean  AP= \dfrac{t}{t+1}, PB = \dfrac{1}{t+1} no?
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    (Original post by Gregorius)
    I clicked
    I think everyone clicked .
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    (Original post by EnglishMuon)
    Am I being really stupid or something? If P divided the line AB in the ratio t:1, I would think that would mean  AP= \dfrac{t}{t+1}, PB = \dfrac{1}{t+1} no?
    Yeo that is right. What question? 2014 I?


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    (Original post by Puddles the Monkey)
    May you scroll for eternity with only yourself to blame :shakecane:
    It wasn't THAT long...


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    (Original post by EnglishMuon)
    Am I being really stupid or something? If P divided the line AB in the ratio t:1, I would think that would mean  AP= \dfrac{t}{t+1}, PB = \dfrac{1}{t+1} no?
    Both shud be multiplied by AB btw


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    (Original post by physicsmaths)
    Yeo that is right. What question? 2014 I?


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    yea.
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    For (ii) I said line AB has equation  r= (1- \lambda)a + \lambda b and  f= \mu g =... By equating a's and b's I get
     \lambda (1+sr+r) = \mu, (1+r+sr)(1- \lambda) = \mu rs subbing into eachother gets  rs(1+sr+r) \lambda = (1+r+sr)(1- \lambda) \Rightarrow (rs+1) \lambda =1 . I cant see an obvious mistake here? (overall I got t=rs instead of 1/rs suggesting my a,b 'coeffs' were the wrong way round).
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    (Original post by EnglishMuon)
    yea.
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    For (ii) I said line AB has equation  r= (1- \lambda)a + \lambda b and  f= \mu g =... By equating a's and b's I get
     \lambda (1+sr+r) = \mu, (1+r+sr)(1- \lambda) = \mu rs subbing into eachother gets  rs(1+sr+r) \lambda = (1+r+sr)(1- \lambda) \Rightarrow (rs+1) \lambda =1 . I cant see an obvious mistake here? (overall I got t=rs instead of 1/rs suggesting my a,b 'coeffs' were the wrong way round).
    I will do the prt again to see where you have gone wrong I did it differently but what I did was I flipped the diagram and used flipped a's b's etc to get the pos vector relative to the the other points(you can choose any) then add the position vector of either point(whichever you choose)


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    Just finished STEP III 2014. In my opinion this was a more difficult paper than 2013, mostly due to the number of geometry based questions. The one with complex numbers wasn't too bad but I dropped four marks on the vectors because I didn't use a proof by contradiction (was this necessary for the marks?). I should have gotten around 108 on that paper I think
 
 
 
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