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    (Original post by mgill17)
    Anyone know where I can get some really hard questions for this unit? I've done as many AQA papers as I can but I fear that that's comfort revising now after Wednesday's ordeal. I want to prepare for the literal worst.

    What are solomon papers like and do they even exist for MPC4, I hear people go on about them all the time?

    I don't understand how the AS core papers were similar to last year's standards then that abomination happened.
    http://www.physicsandmathstutor.com/...rs/C4-solomon/
    these are the edexcel Solomon papers but I find that the majority of the questions are relevant to AQA, also I have found that they have questions applied in different ways so they are pretty good to try and prepare for different styled questions
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    (Original post by Cascadess)
    My prediction for this year is the last question to be a hard vectors question. Anyone else got any other predictions? :P
    When is there not a hard vectors question on core 4?
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    How do you find max rate of growth when you have dy/dx?


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    Guys I'm doing the 2015 paper Question 1 B, I have -1/6ln25 + 3ln5. It should be in the form kln5, how do I this?
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    (Original post by Yo12345)
    How do you find max rate of growth when you have dy/dx?


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    If you imagine you plot dy/dx on a graph, and call that y=f(x) then the maximum point will be where f'(x) = 0, or in other words, where d^2y/dx^2 = 0! (and I guess d^3y/dx^3 < 0...)
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    (Original post by Dinasaurus)
    Guys I'm doing the 2015 paper Question 1 B, I have -1/6ln25 + 3ln5. It should be in the form kln5, how do I this?
    ln25 is ln5^2 = 2ln5

    (-1/6)*2ln5 + 3ln5 = (-1/3)ln5 + 3ln5 = (8/3)ln5
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    PLZ Someone help I think I am getting mental breakdown

    I can't see to get the answer for this convert parametric into cartesian

    x = t / 2t-1
    y = t / t-1
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    (Original post by Examguy123)
    When is there not a hard vectors question on core 4?
    I recon it'll be the last one though, like the pinnacle of difficulty on the paper.
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    (Original post by bartbarrow)
    ln25 is ln5^2 = 2ln5

    (-1/6)*2ln5 + 3ln5 = (-1/3)ln5 + 3ln5 = (8/3)ln5
    How do -1/3 and 3 make 8/3?
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    (Original post by Dinasaurus)
    How do -1/3 and 3 make 8/3?
    (-1/3) + 3 = 8/3? unless I'm going crazy
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    (Original post by koolgurl14)
    PLZ Someone help I think I am getting mental breakdown

    I can't see to get the answer for this convert parametric into cartesian

    x = t / 2t-1
    y = t / t-1
    Tricky - managed to get it down to (y/x) = 2 + (y/t) although not sure that helps...

    When AQA hand out difficult parametric -> cartesians, they usually provide some base format of some kind (e.g. xy + y^2 + x^2 = k, find k) or similar. None of that given?
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    (Original post by bartbarrow)
    (-1/3) + 3 = 8/3? unless I'm going crazy
    Oh wow, I must be going crazy then, so dumb moment.
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    (Original post by Dinasaurus)
    Guys I'm doing the 2015 paper Question 1 B, I have -1/6ln25 + 3ln5. It should be in the form kln5, how do I this?
    with -1/6 ln(25) turn the 25 in to 52 and bring the 2 down
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    (Original post by Mentalmirz)
    http://www.physicsandmathstutor.com/...rs/C4-solomon/
    these are the edexcel Solomon papers but I find that the majority of the questions are relevant to AQA, also I have found that they have questions applied in different ways so they are pretty good to try and prepare for different styled questions
    This might be a good shout then. I think the style of writing was part of the reason I got so phased with some of them I guess. Hoping this one isn't too bad considering I haven't got an A in core 3 now and at best I scrape As in core 4
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    (Original post by koolgurl14)
    PLZ Someone help I think I am getting mental breakdown

    I can't see to get the answer for this convert parametric into cartesian

    x = t / 2t-1
    y = t / t-1
    what's the answer? I think I have one.
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    (Original post by koolgurl14)
    PLZ Someone help I think I am getting mental breakdown

    I can't see to get the answer for this convert parametric into cartesian

    x = t / 2t-1
    y = t / t-1
    Got it I think.. is the answer 1/(x-1)? If so I can post a solution.
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    (Original post by Dinasaurus)
    Guys I'm doing the 2015 paper Question 1 B, I have -1/6ln25 + 3ln5. It should be in the form kln5, how do I this?
    Here u go
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    (Original post by mgill17)
    This might be a good shout then. I think the style of writing was part of the reason I got so phased with some of them I guess. Hoping this one isn't too bad considering I haven't got an A in core 3 now and at best I scrape As in core 4
    same, I'm seriously hoping that this paper is reasonable :/
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    http://www.mrbartonmaths.com/resourc...QAJune08QP.pdf

    For question 7c, why have they chosen y = 0 and not y=-1

    MS http://www.mrbartonmaths.com/resourc...QAJune08MS.pdf
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    (Original post by bartbarrow)
    Got it I think.. is the answer 1/(x-1)? If so I can post a solution.
    (Original post by Shumaya)
    what's the answer? I think I have one.
    (Original post by bartbarrow)
    Tricky - managed to get it down to (y/x) = 2 + (y/t) although not sure that helps...

    When AQA hand out difficult parametric -> cartesians, they usually provide some base format of some kind (e.g. xy + y^2 + x^2 = k, find k) or similar. None of that given?
    The answer is y = x/1-x I wasted this whole day to figure it out ...
 
 
 
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