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Edexcel GCSE Maths Paper 2 (9/6/16) Complete Unofficial Mark Scheme Watch

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    (Original post by leopard923)
    I think this answer is wrong also as when you factorise the denominator, you get (3x+4) (x-3) and the numerator was 3-x . 3-x and x-3 are not the same thing. Therefore, you can't cancel out.
    I wasn't sure about this answer, but it's what all of the people I talked to got. I factorised it to (3-X)(-3x-4), which would leave it as 1/-3x-4 but nobody else seems to have done it like that.
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    (Original post by iamamarxist)
    not with you on the last question

    1/2 x a x b x sin(c) = area

    1/2 x 7 x 8 x sin(c) = 18

    it turned out to be like 40.01 I subbed it in and it worked
    I put that too but it wasnt after that angle apparently
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    (Original post by tombart)
    I put that too but it wasnt after that angle apparently
    i feel like a complete idiot
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    (Original post by iamamarxist)
    i feel like a complete idiot
    it was so easy too, just needed to use the cosine and sine rule
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    (Original post by tombart)
    it was so easy too, just needed to use the cosine and sine rule
    ikr, and i feel like i ****ed up the other trig question
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    Think I'm on 167 with realistic marking, so should be ok, what about you?
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    (Original post by Burkay)
    I got 40 for the angle
    I got 40.005 but it had to be to 3sig.figs so i rounded to 40.1
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    (Original post by SweetStarlight14)
    I wasn't sure about this answer, but it's what all of the people I talked to got. I factorised it to (3-X)(-3x-4), which would leave it as 1/-3x-4 but nobody else seems to have done it like that.
    I didn't do that, but I think that it is right.
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    (Original post by iamamarxist)
    not with you on the last question

    1/2 x a x b x sin(c) = area

    1/2 x 7 x 8 x sin(c) = 18

    it turned out to be like 40.01 I subbed it in and it worked


    You are right, this angle was 40.01 but this was not the end of the question. You needed to use this angle with the cosine rule followed by the sine rule to find the angle it was referring to which was 80.4.
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    (Original post by SweetStarlight14)
    I wasn't sure about this answer, but it's what all of the people I talked to got. I factorised it to (3-X)(-3x-4), which would leave it as 1/-3x-4 but nobody else seems to have done it like that.
    Yh i did it exactly like that. So is it the right answer? i put 1/-3x-4
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    isn't q23 actually 13.1?
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    (Original post by SweetStarlight14)
    I wasn't sure about this answer, but it's what all of the people I talked to got. I factorised it to (3-X)(-3x-4), which would leave it as 1/-3x-4 but nobody else seems to have done it like that.
    Maybe there are just different ways of doing it... hopefully lool so we can both get it right
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    Anyone have the foundation mark scheme
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    (Original post by iamamarxist)
    not with you on the last question

    1/2 x a x b x sin(c) = area

    1/2 x 7 x 8 x sin(c) = 18

    it turned out to be like 40.01 I subbed it in and it worked
    You worked out the wrong angle... i almost did but corrected it
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    they can both be divided by -1 so yeah you can cancel
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    What is the date for the November retakes of this exam?
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    (Original post by tombart)
    I put that too but it wasnt after that angle apparently
    That is because the were meant to use that engle to find the other anle.
    After you found 40.... you use cosine and then sine rule
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    (Original post by NikhilStephen123)
    That is because the were meant to use that engle to find the other anle.
    After you found 40.... you use cosine and then sine rule
    If you found the angle ABC which was 40, how many marks out of 6 do you reckon we get?
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    i am literally retard i literally put 20 instead of 20.3 becuase i thought round to 1 decimal point was the same as rounding to the nearest 10....
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    What do you think 157/200 is?


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