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    I-got-9
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    QUESTION=X^4+81
    Simplify=(x^2+9)(x^2-9)
    Simplify-further-blah
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    Thanks
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    (Original post by vishantu_success)
    QUESTION=X^4+81
    Simplify=(x^2+9)(x^2-9)
    Simplify-further-blah
    oh i put ((x-3)^2(x+3)^2)
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    (Original post by vishantu_success)
    QUESTION=X^4+81
    Simplify=(x^2+9)(x^2-9)
    Simplify-further-blah
    That's one mark, second mark for (x + 3)(x - 3)(x^2 + 9)

    (x^2 + 9) can't be simplified further.
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    For the last question did you have to use the cosine rule....

    This is what I did...

    w^2 = 3n^2 + 2n^2 - 2n*3n*1/3
    w^2 = 9n + 4n - 6n^2*1/3
    w^2 = 9n +4n - 2n^2
    w = 3n + 2n - 2n
    w = 3n --which is the same as the other line meaning it is an isoscelese triangle
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    hey guys, making an unofficial mark scheme lol
    any help with remembering the questions would be appreciated

    http://www.thestudentroom.co.uk/show....php?t=4176536
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    The hardest one was working out k. Does anyone have the workings to see how many marks I would get? The original equation was y=1/3x^3-x^2-5x-k
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    (Original post by Mattyates2000)
    For the last question did you have to use the cosine rule....

    This is what I did...

    w^2 = 3n^2 + 2n^2 - 2n*3n*1/3
    w^2 = 9n + 4n - 6n^2*1/3
    w^2 = 9n +4n - 2n^2
    w = 3n + 2n - 2n
    w = 3n --which is the same as the other line meaning it is an isoscelese triangle
    Yeah, exactly that. Good question, with nice numbers.
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    (Original post by Ishan_2000)
    That's one mark, second mark for (x + 3)(x - 3)(x^2 + 9)

    (x^2 + 9) can't be simplified further.
    Thats what i got!!!
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    (Original post by daisie)
    The hardest one was working out k. Does anyone have the workings to see how many marks I would get? The original equation was y=1/3x^3-x^2-5x-k
    Differentiate first to get: x^2 - 2x - 3 (it was 3x not 5x, I think)

    Then, make this equal to 0, as it was a minimum point, so has a gradient of 0, so:
    x^2 - 2x - 3 = 0
    Factorise: (x - 3)(x + 1) = 0
    Solve: x = 3, -1.

    Sub in x = 3 into the equation, as that was where y was, and you should end up with k - 9 = 0 (y = 0, when x = 3, as the x-axis was a tangent to the minimum point.)


    k = 9 (4 marks)
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    (Original post by daisie)
    The hardest one was working out k. Does anyone have the workings to see how many marks I would get? The original equation was y=1/3x^3-x^2-5x-k
    I think the answer was 9... you had to do dy/dx = 0 to find x and then you knew that why was 0 so you sub y = 0 and x = (can't remember) into
    y=1/3x^3-x^2-5x-k and then you get +9 I think
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    Name:  image.jpg
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    These are some random answers for random questions that me and a few others got, they're not all right but if you got anything similar or recall writing something similar then woo
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    (Original post by ihatehannah)
    -80
    Fs i got -80/sqrt of 1 which is -80. I got confused what sqrt of 1 was
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    (Original post by Ishan_2000)
    Differentiate first to get: x^2 - 2x - 3 (it was 3x not 5x, I think)

    Then, make this equal to 0, as it was a minimum point, so has a gradient of 0, so:
    x^2 - 2x - 3 = 0
    Factorise: (x - 3)(x + 1) = 0
    Solve: x = 3, -1.

    Sub in x = 3 into the equation, as that was where y was, and you should end up with k - 9 = 0 (y = 0, when x = 3, as the x-axis was a tangent to the minimum point.)


    k = 9 (4 marks)
    Thank you! Yes sorry thats a typo it should have been 3 not 5
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    For the perimeter of the trapezium question, to clear any confusion:

    BA + BC + CD + AE + DE = Perimeter,
    BA = 3
    BC = 3
    CD = 3 (square has equal sides, all were 3)
    AE = Right angled triangle, angle of 60 degrees was given, side of 3 cm was the opposite. AE was the hypotenuse.
    So, sin(60) = 3 / AE
    AE = 3 / sin(60), so it is 3 / (root3 / 2), which equals 6 / root3

    DE = Right angled triangle, angle of 60 degrees was given, side of 3 cm was the opposite. DE was the adjacent.
    So, tan(60) = 3 / DE
    DE = 3 / tan(60), so it is 3 / root3

    Add them all up, to get 9 + 3 / root3 + 6 / root3
    Common denominator of root3, and rationalise to get 9 + 3 root3, which factorises to 3 ( 3 + root3) cm
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    (Original post by Ishan_2000)
    For the perimeter of the trapezium question, to clear any confusion:

    BA + BC + CD + AE + DE = Perimeter,
    BA = 3
    BC = 3
    CD = 3 (square has equal sides, all were 3)
    AE = Right angled triangle, angle of 60 degrees was given, side of 3 cm was the opposite. AE was the hypotenuse.
    So, sin(60) = 3 / AE
    AE = 3 / sin(60), so it is 3 / (root3 / 2), which equals 6 / root3

    DE = Right angled triangle, angle of 60 degrees was given, side of 3 cm was the opposite. DE was the adjacent.
    So, tan(60) = 3 / DE
    DE = 3 / tan(60), so it is 3 / root3

    Add them all up, to get 9 + 3 / root3 + 6 / root3
    Common denominator of root3, and rationalise to get 9 + 3 root3, which factorises to 3 ( 3 + root3) cm
    Thats what I did but for both AE and DE I rationalised them to make it easier for myself
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    (Original post by Ishan_2000)
    For the perimeter of the trapezium question, to clear any confusion:

    BA + BC + CD + AE + DE = Perimeter,
    BA = 3
    BC = 3
    CD = 3 (square has equal sides, all were 3)
    AE = Right angled triangle, angle of 60 degrees was given, side of 3 cm was the opposite. AE was the hypotenuse.
    So, sin(60) = 3 / AE
    AE = 3 / sin(60), so it is 3 / (root3 / 2), which equals 6 / root3

    DE = Right angled triangle, angle of 60 degrees was given, side of 3 cm was the opposite. DE was the adjacent.
    So, tan(60) = 3 / DE
    DE = 3 / tan(60), so it is 3 / root3

    Add them all up, to get 9 + 3 / root3 + 6 / root3
    Common denominator of root3, and rationalise to get 9 + 3 root3, which factorises to 3 ( 3 + root3) cm
    You seem to have done very well on the exam, well done
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    (Original post by SmithAmelia)
    I completely forgot about the obtuse angle bit
    nothing to do with it being an obtuse angle it just said y <0
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    (Original post by Dorisdolphine)
    What did u get for x/y
    I got -80 for that because it was 16/-0.4 which is the same as 16 x -5 which was -80
 
 
 
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