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    (Original post by Dieselblue)
    Hmm I think i did something stupid in the exam saying that -4x^2+20 = -4(x^2+5) which is wrong. Would I get the final mark for writing the -4x^2+20/(x^2+5)^2 ? Because I definitely wrote that.
    I think you would lose an accuracy mark.
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    for the modulus graph i left it as 1/2ln(25/4) for x-cordinate. will i lose marks for not simplifying further?
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    For 8c I only got 2 positive values?
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    can someone show their working for 9c? please reply to this/tag me so I know if you've done it !
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    What was q 8?
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    (Original post by veldt127)
    I'm not 100% sure on all of these, but I think most are correct.

    1.
    A -5, 6
    B 6

    2.
    A (20-4x^2)/(x^2+5)^2 Might not be simplest form
    B >sqrt(5), <-sqrt(5)

    3.
    A R= sqrt(5)
    a= 26.57°
    B 33.0°, 273.9°
    C 86.1°

    4.
    Ai 21
    ii ln(2.5)
    iii 25
    B Show that question
    C 1.4368, 1.4373
    D Show the root was in [1.4365, 1.4375]

    5.
    i 0.9463
    ii 0.5cosec(4Y)

    6.
    A A=3, B=4
    B Normal eqn. -0.5x + 17.5

    7.
    A graph of arcsin, sort of a rotated S shape. Went through (0,0), (-1,-pi/2), (1,pi/2)
    B -1-0.5sqrt(3)

    8.
    A Trig proof
    B -2.848, -1.277, 0.294, 1.865

    9.
    A 6.740 - dose after 4 hours
    B show that dose equalled a value after 7 hours
    C 5ln(2 + 2e^-1)
    A = 5, B = 2

    Sorry about the formatting, I'll try to improve it once I'm home.
    Got the exact same!
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    If I put -root5 < x < root 5

    Do I get any marks at all??

    Im a ****ing spac I dont know why I did that
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    (Original post by Mattematics)
    4e^2x - 25 = 0
    e^2x = 25/4
    e^x = 5/2
    x = ln(5/2)
    I left it as 0.5ln(25/4). Did they want a simplified form?

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    (Original post by eyeman567)
    What were the equations for F and G
    7x-1= f(x)
    g(x)= 4/(x-2)
    I think
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    (Original post by theereflex)
    For 3(c), I don't understand why the lowest value of theta wasn't just 33 from part b?

    anyone help?
    Same here
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    (Original post by veldt127)
    I'm not 100% sure on all of these, but I think most are correct.


    9.
    A 6.740 - dose after 4 hours
    B show that dose equalled a value after 7 hours
    C 5ln(2 + 2e^-1)
    A = 5, B = 2
    for q9 a i got something like 5.1...... and got the 6.7.... for part b. But i managed to prove part b, as the timings were different so different values or nah?.
    Did anyone else get 5.1... or so for a??

    And I swear this question has appeared before in another C3 paper....
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    (Original post by eyeman567)
    If I put -root5 < x < root 5

    Do I get any marks at all??

    Im a ****ing spac I dont know why I did that
    That's what I got


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    (Original post by Further)
    7x-1= f(x)g(x)= 4/(x-2)
    I think
    Yeah I think it was that, I don't get how you solve it though

    I subbed G into F

    Got 28 / (x-2) = x + 1

    Then ended up with X^2 - x - 30 = 0

    which Im pretty sure is wrong and unsolvable
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    (Original post by unimaginable118)
    Does anyone remember how many marks the last question was? I was SO STUPID. I left it out (( looks like someones not going to uni...
    I did the same, i think it was 8 marks, thought i had done well on time as i finished question 8 as the exam finished and theres normally 8 questions but yeah 😒
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    I though I got 72/75 in this paper, but when I found out that I did a silly mistake in question 3, I don't know if will get an A*.

    I said a=tan^-1(2)=63.43...

    And I used this value for the rest of question 3. Can I still get can A*?
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    (Original post by AvocadosConstant)
    Same here
    3b) denominator was 2cos(theta) - sin(theta) -1,
    3c) 2cos(theta)+sin(theta)-1

    You need to switch sign for cos(theta+Value)=59....

    to cos(theta-Value)=59....
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    Yeah it was definitely 4x^2+20, it looked like you could factorise and cancel out an x^2+5 but you couldn't because of the negative sign in front of the x^2 at the top
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    How many marks was question 6b out of?
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    (Original post by Dieselblue)
    For 5i what did people do with the sin and cos?

    Also part 2a is wrong, -4x^2-20=-4(x^2+5) so -4/x^2+5
    I am sorry but you might have got the answer wrong
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    (Original post by ravichauhan11)
    nope it was 20-4x^2. not -20-4x^2. there was no further cancellation
    Agreed.
 
 
 
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