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    Is the reaction between A and B = (3/2)(W)(Cosec(theta)) ???
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    Looking back, there is one thing i don't understand.

    I had stated R = (3/2)Wcosec(theta) where R = force A acts on B

    You asked what component of the above acts vertically on A. I had stated 3W/2 but isn't this the component that acts vertically on B(rather that A) since R is the force A acts on B???
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    (Original post by JMorgan2)
    Looking back, there is one thing i don't understand.

    I had stated R = (3/2)Wcosec(theta) where R = force A acts on B

    You asked what component of the above acts vertically on A. I had stated 3W/2 but isn't this the component that acts vertically on B(rather that A) since R is the force A acts on B???
    Newton's third law: every action has an equal and opposite reaction.

    (Original post by JMorgan2)
    Is the reaction between A and B = (3/2)(W)(Cosec(theta)) ???
    Don't have a clue. Really too tired right now. Might look again tomorrow.
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    2 things....

    1)I just want to confirm that:
    a) reaction between A and B = (3/2)WCosec(theta)
    b) Reaction between B and E = W/root3

    2) For the horizontal reaction between B and C, I get the two terms, 3Wcot(theta)/2 and W/2root3. But why is the horizontal reaction the difference between the two? A diagram would be really really helpful
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    Also what does happen if cot(theta) < 1/(3root3)?
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    ????
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    Anybody???
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    ???
 
 
 
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