JMorgan2
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#61
Report Thread starter 12 years ago
#61
Is the reaction between A and B = (3/2)(W)(Cosec(theta)) ???
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JMorgan2
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#62
Report Thread starter 12 years ago
#62
Looking back, there is one thing i don't understand.

I had stated R = (3/2)Wcosec(theta) where R = force A acts on B

You asked what component of the above acts vertically on A. I had stated 3W/2 but isn't this the component that acts vertically on B(rather that A) since R is the force A acts on B???
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generalebriety
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#63
Report 12 years ago
#63
(Original post by JMorgan2)
Looking back, there is one thing i don't understand.

I had stated R = (3/2)Wcosec(theta) where R = force A acts on B

You asked what component of the above acts vertically on A. I had stated 3W/2 but isn't this the component that acts vertically on B(rather that A) since R is the force A acts on B???
Newton's third law: every action has an equal and opposite reaction.

(Original post by JMorgan2)
Is the reaction between A and B = (3/2)(W)(Cosec(theta)) ???
Don't have a clue. Really too tired right now. Might look again tomorrow.
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holst123
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#64
Report 12 years ago
#64
2 things....

1)I just want to confirm that:
a) reaction between A and B = (3/2)WCosec(theta)
b) Reaction between B and E = W/root3

2) For the horizontal reaction between B and C, I get the two terms, 3Wcot(theta)/2 and W/2root3. But why is the horizontal reaction the difference between the two? A diagram would be really really helpful
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holst123
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#65
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#65
Also what does happen if cot(theta) < 1/(3root3)?
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holst123
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#66
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#66
????
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holst123
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#67
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#67
Anybody???
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holst123
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#68
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#68
???
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