Edexcel FP3 June 2015 - Official Thread Watch

RDPClem
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#781
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#781
I got 2 as a repeated root for all of the eigenvalues... Did anybody else get that? xD
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nanairo
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#782
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#782
Hope the grade boundary low!!!
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physicsmaths
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#783
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#783
What did people do for area?


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TeeEm
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#784
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#784
any more? Need a decent polling sample (min 100)
http://www.thestudentroom.co.uk/show....php?t=3417321
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Gome44
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#785
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#785
(Original post by physicsmaths)
What did people do for area?


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0.5?
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Emmi12345
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#786
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#786
That went terribly for me... Also made stupid mistakes on the 'easy' questions, so things are definitely not looking up for me.
Never had an exam that's gone worse than that in my life.
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fatart123
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#787
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#787
Spet 1hr thinking 3 was wrong lol. Pissed up a few parts of later questions because of that. Thank **** I didn't need that for an a*
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nanairo
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#788
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#788
(Original post by pengomar)
I did. It wasn't that hard, just a bit long.
Sp you think the IAL paper is a bit easier?
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pengomar
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#789
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#789
(Original post by nanairo)
Sp you think the IAL paper is a bit easier?
I think so
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raff97
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#790
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#790
(Original post by Gome44)
0.5?
fml I think I forgot to sub in the bottom limits. I had e and stuff over e. All over the place
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physicsmaths
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#791
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#791
**** i think i forgot to times by 1/2


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raff97
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#792
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#792
(Original post by physicsmaths)
**** i think i forgot to times by 1/2


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I got 1 for area of the triangle too. i had (1/2)sqrt2.e^t*sqrt2.e^-t=1
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Chazatthekeys
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#793
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#793
(Original post by physicsmaths)
**** i think i forgot to times by 1/2


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On what question?!
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Chazatthekeys
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#794
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#794
(Original post by raff97)
I got 1 for area of the triangle too. i had (1/2)sqrt2.e^t*sqrt2.e^-t=1
Yup I had area of OQR = 1 also, same as you're lengths also
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Gome44
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#795
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#795
Attached files
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Gome44
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#796
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#796
(Original post by physicsmaths)
**** i think i forgot to times by 1/2


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Most people are saying 1 so I'm probably wrong :/
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soundhippo
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#797
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#797
(Original post by raff97)
i got 1 for area of the triangle too. I had (1/2)sqrt2.e^t*sqrt2.e^-t=1
me toooo
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physicsmaths
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#798
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#798
(Original post by Gome44)
Most people are saying 1 so I'm probably wrong :/
I got 1.


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trooken
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#799
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#799
Normalised eigenvectors if anyone's curious

For 2-√2, it was (0.5, -1/√2, 0.5)
For 2, it was (1/√2, 0, -1/√2)
For 2+√2, it was (0.5, 1/√2, 0.5)

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Jay-dawg
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#800
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#800
(Original post by trooken)
For the last question, I substituted y=mx+c into the equation of the ellipse, obtained values for x from a quadratic, worked out the corresponding values for y, then found the midpoints of X and Y in terms of c, then equated the two 'c's together to get a locus. The answer I got is not the same as what others before me posted, so is this method invalid, or did I most likely make a mistake with the algebra?

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I did this as well, I got y=-4mx , what did you get?


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