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Edexcel FP3 - 27th June, 2016 watch

  • View Poll Results: How did you find the Edexcel FP3 exam?
    Very hard
    41
    8.40%
    Hard
    69
    14.14%
    Normal
    156
    31.97%
    Easy
    165
    33.81%
    Very easy
    57
    11.68%

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    (Original post by blahblah21)
    ahh i got a different answer for 2. I got 19/12ln(6) i might be wrong
    I am sorry; I believe mine is correct as I checked the integral on my calculator and matched mine.
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    (Original post by oShahpo)
    How many marks would I lose for not putting u=e^x? I.e. not resubbing the e^x. I am not even sure I didn't do it, but I think so.
    Id say 1 at most 2 but I highly doubt they'd deduct 2 for that
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    (Original post by oShahpo)
    I envy your memory my friend. All's correct, high five.
    Haha, that should be you envy my large display on the casio-fx-9750GII where one can record all of their answers
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    in the reduction question i wrote the integral of cosx as -sin x so my b was -6 and c was 6, how many marks do i lose?
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    (Original post by Ewanclementson)
    I believe I recorded mine wrong as I remember also getting -13/40. I shall correct that and repost the answers.
    thank God, thanks for this man, btw may i ask how you did q2, as i got every other answer you got but couldnt do 2, as i find (dy/dx)^2 subbed into the formula, played about with it couldnt get anywhere, i panicked so made a substitution loool and got nowhere so i skipped. How did you do it and how many marks out of 7 do u think i could get for finding (dy/dx)^2 and subbing into the formula?
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    (Original post by Anon-)
    i did the dot product of the two normal vectors, which is 0 (cos90)
    I did the dot products and then concluded that the two perpendiculars are perpendicular, therefore the two planes are perpendicular. This is a valid conclusion isn't it?
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    (Original post by Ewanclementson)
    I am sorry; I believe mine is correct as I checked the integral on my calculator and matched mine.
    ahh damn it okay hopefully i dont lose too many marks
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    also how do you prove the reduction 3 marker??
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    (Original post by rm761)
    also how do you prove the reduction 3 marker??
    https://72cc677472290a33479706e39d1d...P3%20Notes.pdf bottom of page 17
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    Rather annoyed as that could have been as easy 75 but I completely froze on the 5 mark integration somehow! Used the completely wrong method so won't get any marks but should get 70/75. Hoping I got got 100UMS in M3 and FP2 if the unofficial mark schemes are right...
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    Should be full raw for full UMS for both IAL and UK papers this year.
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    (Original post by rm761)
    also how do you prove the reduction 3 marker??
    SinA - SinB = 2Cos(A+B/2)Sin(A-B/2)
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    anyone remember the marks for each q? and the sub qs?
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    Anyone help me vectors ?
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    (Original post by MarocMan)
    thank God, thanks for this man, btw may i ask how you did q2, as i got every other answer you got but couldnt do 2, as i find (dy/dx)^2 subbed into the formula, played about with it couldnt get anywhere, i panicked so made a substitution loool and got nowhere so i skipped. How did you do it and how many marks out of 7 do u think i could get for finding (dy/dx)^2 and subbing into the formula?
    No problem, inside the square root, there was 1+(x/4-1/x)^2 which expands and factorises to (x/4+1/x)^2 then the squared cancels the root and out pops a nice integral
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    (Original post by rm761)
    also how do you prove the reduction 3 marker??
    using the factor formula shown on c3 formula book and you will find it cancels nicely to the one shown
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    (Original post by Zacken)
    Should be full raw for full UMS for both IAL and UK papers this year.
    Hey Zacken, if N1 is the perpendicular vector to plane Pi1, N2 is that to plane P2, and if N1.N2 = 0, hence N1 is perpendicular to N2. It then follows that P1 is perpendicular to Pi2, correct?
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    in the reduction question i wrote the integral of cosx as -sin x so my b was -6 and c was 6, how many marks do i lose?

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    (Original post by Major-fury)
    Anyone help me vectors ?
    Which bit do you want? The last bit you had to solve the two cartesian equations by subbing any value into x, y or z. Then solving for the rest and that gives you a.
    B was basically the cross product of the two perpendicular vectors.
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    (Original post by Ewanclementson)
    No problem, inside the square root, there was 1+(x/4-1/x)^2 which expands and factorises to (x/4+1/x)^2 then the squared cancels the root and out pops a nice integral
    omg i expanded and then didnt realise itll factorise that nicley, nice spot tbh, how many marks you think i'd lose?
 
 
 
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