Hey there! Sign in to join this conversationNew here? Join for free
    Offline

    6
    ReputationRep:
    (Original post by Jowen12)
    1.8 I believe? Probably wrong though!
    I'm not 100% sure but I think it was 0.8
    Offline

    10
    ReputationRep:
    (Original post by Studious_Student)
    What was the value of theta for the sector question again? I remember somewhat that the radius was 12
    It was 0.8
    Offline

    11
    ReputationRep:
    (Original post by Jowen12)
    1.8 I believe? Probably wrong though!
    It was 0.8
    Offline

    11
    ReputationRep:
    Thank you!
    (Original post by Mr Moon Man)
    Sin(X)=0 for 0,180, and 360
    Offline

    2
    ReputationRep:
    (Original post by ineedA)
    Sup, did exactly the same, you and I both integrated the value before the brackets right? You're not meant to do that, if you carried on and multiplied it by 50 then we'll probably get W for method marks
    Not supposed to integrate 8/51 or whatever it was? How come?
    Offline

    11
    ReputationRep:
    (Original post by WuMyster)
    Not supposed to integrate 8/51 or whatever it was? How come?
    5/81

    When integrating, a constant value which applies to the whole integral can be put outside of the integral before integrating
    Offline

    2
    ReputationRep:
    (Original post by tizzaclaire98)
    5/81

    When integrating, a constant value which applies to the whole integral can be put outside of the integral before integrating
    Oh crap I remember learning that but that didn't come up in any of my textbooks (retaker). Oh well.
    Offline

    2
    ReputationRep:
    With the sin graph translation did you guys move it 3 units down. There were no brackets so I was unsure?
    Offline

    11
    ReputationRep:
    (Original post by WuMyster)
    Oh crap I remember learning that but that didn't come up in any of my textbooks (retaker). Oh well.
    It actually comes up much more in C3 - surprised it was put into C2
    Offline

    11
    ReputationRep:
    (Original post by mp1998)
    With the sin graph translation did you guys move it 3 units down. There were no brackets so I was unsure?
    Yeah it was strange without brackets. I believe it was translating 3 units down though
    Offline

    2
    ReputationRep:
    (Original post by tizzaclaire98)
    It was 0.8
    Ah okay my mistake!
    Offline

    2
    ReputationRep:
    guys for that question with "f(h+5) - f(5)/h" could you assume that h represents the the change in x and so when when x=5 the change in x would be 0 and so u sub that into the simplified "h+8" to geit "0+8" which gives you 8, the answer???? or am i way off
    Offline

    1
    ReputationRep:
    (Original post by Jowen12)
    1.8 I believe? Probably wrong though!
    it was 0.8
    Offline

    9
    ReputationRep:
    So then wouldn't the answer be a = 12.7? Because the unofficial markscheme says a = 8.96

    r^2/2 x Theta = a^2/2 x sin(theta)

    Sub values in:

    144/2 x 0.8 = a^2/2 x Sin (0.8)

    (288/5)/sin (0.8) = a^2/2 ---> 80.2948504 = a^2/2

    160.5897008 = a^2

    a = 12.67 = 12.7 (3 sig figs) ?
    Offline

    0
    ReputationRep:
    (Original post by tizzaclaire98)
    Its a differentiation by first principles question.

    Q:
    y = x^2 - 2x
    find dy/dx on the chord between x=5 and x=5.1.

    A:
    8.1

    Q:
    given that f(x) = x^2 - 2x
    find (f(5+h) - f(5))/h

    A:
    sub 5+h for x:
    (5+h)^2 - 2(5+h) = 25+10h+h^2 -10 -2h = 15 +8h +h^2
    minus f(x) sub 5 for x:
    15+8h+h^2 - (25-10)= 8h+h^2
    Divide by h:
    8 + h

    Q:
    gradient at x=5

    A:
    deltay/deltax = 8 + h
    as h tends to 0, gradient tends to 8, so dy/dx = 8
    I left it as 8h+8h^2
    At first I couldn't see why you did that then I saw it was in the original equation, made so many stupid mistakes like this!
    Will I just lose 1 mark?
    Offline

    11
    ReputationRep:
    (Original post by ant1greeny)
    I left it as 8h+8h^2
    At first I couldn't see why you did that then I saw it was in the original equation, made so many stupid mistakes like this!
    Will I just lose 1 mark?
    I imagine so - no more than 2 I would think
    Offline

    5
    ReputationRep:
    (Original post by tizzaclaire98)
    Attachment 545879

    Can someone explain why I only got two values? thanks
    You're not meant to divide by sinx. You had to bring it all over to one side and then take the brackets so
    Sinx(4sinx-1)=0
    Sinx=0 and Sinx=1/4
    Offline

    2
    ReputationRep:
    (Original post by tizzaclaire98)
    It actually comes up much more in C3 - surprised it was put into C2
    Come to think of it, I think I remember learning that from C3 and not in C2. Weird.
    Offline

    2
    ReputationRep:
    Does anyone have a picture of the paper? Or at least the first few? I wanna see the wording of the sequences question for question 2... Threw me off a bit :curious:
    Offline

    12
    ReputationRep:
    (Original post by Lucuniexet)
    for the simplifying log question i got -3m
    is this familiar to anyone?!
    I got this! Because I had -logaA^3m which simplified to -3mlogaA which gives -3m, right?
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Are unpaid trial work shifts fair?
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.