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    (Original post by Mr M (jr))
    No, it was ln(u) + (1/u) + c
    Hello Mr M junior, how many marks do you think I would lose in the early question with the stationary points, I got two of them correctly but forgot the third when cosx=0. Thanks alot
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    (Original post by The Coxmobil)
    I don't suppose anyone got a Ln of a Ln at any point?
    I think I remember getting that and being like wtf. Ahh I can't remember which question it was...

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    Mr M - would greatly appreciate your help. At the very beginning of Q8 part I - I subbed in the value of t instead of r into 1.08=k/sqrtR - everything else in my working was correct - how many do you think I would lose for doing something so silly? Also, my y co ordinates for Q4 were wrong for the final 2 x-co ordinates. All my x values were correct. Greatly appreciate what you do here -
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    Forgot what angle I was getting in the vectors question, so I did 180-x to get 8.68. Drop 1 there.

    Not really a marking point, but for the second binomial expansion when it says write in powers of 1/x, would they mean the answer given in the unofficial mark scheme or to write it as -(1/x)^2 + 3(1/x)^3 + 6(1/x)^4, or whatever it was. Either way I wrote both.

    Didn't get an exact value of 28/3 for the pyramid, but I gave 9.33 to 3 sf, that should hopefully be enough. Quite a tough paper, but not unfair.


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    (Original post by The Coxmobil)
    I don't suppose anyone got a Ln of a Ln at any point?
    I did can't remember when but I did.
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    Ok, I've put a mark scheme here: http://www.thestudentroom.co.uk/show...5#post43220805
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    (Original post by Mr M)
    I've looked now. Are there any questions that people are unsure about and would like a second opinion on?
    For 5 ii):

    I got completely the wrong integral, but still put limits in and presented my answer in the form AlnB

    How many marks would I lose? (/5)
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    (Original post by Snakefingers13)
    Forgot what angle I was getting in the vectors question, so I did 180-x to get 8.68. Drop 1 there.

    Not really a marking point, but for the second binomial expansion when it says write in powers of 1/x, would they mean the answer given in the unofficial mark scheme or to write it as -(1/x)^2 + 3(1/x)^3 + 6(1/x)^4, or whatever it was. Either way I wrote both.

    Didn't get an exact value of 28/3 for the pyramid, but I gave 9.33 to 3 sf, that should hopefully be enough. Quite a tough paper, but not unfair.


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    you wouldn't lose one for that 8.68, it didn't specify which angle surely?
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    (Original post by DoeADeer)
    I think I remember getting that and being like wtf. Ahh I can't remember which question it was...

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    ahhh thanks, hate that feeling in an exam where you're sure that in no way can your answer be right haha
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    (Original post by DoeADeer)
    I think I remember getting that and being like wtf. Ahh I can't remember which question it was...

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    I did for the substitution one when I put x back in.. Ln ( 1 + lnx ) + ... Something like that
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    (Original post by QuestionsQ)
    Mr M - would greatly appreciate your help. At the very beginning of Q8 part I - I subbed in the value of t instead of r into 1.08=k/sqrtR - everything else in my working was correct - how many do you think I would lose for doing something so silly? Also, my y co ordinates for Q4 were wrong for the final 2 x-co ordinates. All my x values were correct. Greatly appreciate what you do here -
    Q8: lose 2 or 3 probably.

    Q4: probably only lose 1. Max 2.
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    (Original post by TheSneakyBadger)
    you wouldn't lose one for that 8.68, it didn't specify which angle surely?
    It did; it asked for angle BAC. Only 171 (or possibly 360-171) would be acceptable.
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    (Original post by Mr M (jr))
    It did; it asked for angle BAC. Only 171 (or possibly 360-171) would be acceptable.
    How would it specify if it had wanted 8.68?
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    Reckon 64/72 is going to be 90%?
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    (Original post by Mr M)
    I've looked now. Are there any questions that people are unsure about and would like a second opinion on?
    To integrate tan2x ive done 1/2lnsecx instead of 1/2lnsec2x. How many marks will i lose out of 5?
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    (Original post by SJ12345)
    To integrate tan2x ive done 1/2lnsecx instead of 1/2lnsec2x. How many marks will i lose out of 5?
    drop 1
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    To integrate tan 2x, I used a simple substitution of u =2x, to tanu/2 then changed my limits etc. and got to the correct answer. That would be fine wouldn't it? They didn't specify a particular method of doing it did they?
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    (Original post by Mr M)
    drop 1
    Mr M, could you please tell me if you think I'd get ANY marks at all on number 8, because I put

    dr = -k rootx.
    dt

    Which I know is horrifically wrong, I just forgot what inversely proportional meant. Would I get any marks at all for the whole question?
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    (Original post by Mr M)
    I've looked now. Are there any questions that people are unsure about and would like a second opinion on?
    Is the angle 8.7 or 171.3?
    Thank you Mr M!
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    (Original post by Mr M)
    I've looked now. Are there any questions that people are unsure about and would like a second opinion on?
    Hi, I wonder if you could guess at how many marks overall I would have lost from these mistakes:

    1) Putting 1/72 rather than 1/81 because I'm such an idiot
    5ii) Integrating tan2x correctly but then putting the limits in as if it were 0.5lnsecx rather than sec2x..........
    7iii) Doing all the right method but multiplying by 1/2 instead of 1/3 because I apparently can't read.
    8) leaving the equation of r as 2/3(r)^3/2 rather than rearranging to get r on its own

    I also said that the stationary point (0,3) was a maximum not a minimum, is this right? and if not, how many marks

    Thanks!
 
 
 
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