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    (Original post by Anon-)

    What would be most efficient/intuitive way to integrate this? It came up in an Edexcel paper and they didn't give any information on which method to use, and in the mark scheme they didn't even show the steps for intergrating it.
    Recongnition


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    u=sinx
    du/dx=cosx
    dx=du/cosx
    so the integral turns to 2u^2 as the cosx cancels out.
    No limits to change
    So the integral is 2/3 u^3
    which is 2/3 sin^3x

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    (Original post by lam12)
    Recognition, any tips then what to look out for in order to do it?


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    Look at the differntial of each funcion. Consider the power to a higher power. Then divide by this new power and add a minus sign if needed


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    If you've got two lines, one with the gradient 1 and the other with the gradient 1/3, how is this the gradient between them?
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    Picture didn't work
    Name:  question 3.PNG
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    Name:  image.jpg
Views: 177
Size:  78.9 KB Hi can anyone help me with part a? I'm a bit confused on what the the question is asking you to do?
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    Helloooo!
    Do you needs to know the proofs for:
    a.b = b.a
    and
    a.(b + c) = a.b + a.c

    It's in my text book but I don't know if we have to be able to fully recall it?
    Thanks!
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    (Original post by LMottram)
    Helloooo!
    Do you needs to know the proofs for:
    a.b = b.a
    and
    a.(b + c) = a.b + a.c

    It's in my text book but I don't know if we have to be able to fully recall it?
    Thanks!
    I'm pretty sure you don't need to know it


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    (Original post by Elliemay97)
    Name:  image.jpg
Views: 177
Size:  78.9 KB Hi can anyone help me with part a? I'm a bit confused on what the the question is asking you to do?
    Its just asking how you'd set up the integral. So to find the area of R you'd need to use ∫y.dx/dt. Which will then get you to the answer it wants you to show.






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    (Original post by ooftar)
    Its just asking how you'd set up the integral. So to find the area of R you'd need to use ∫y.dx/dt. Which will then get you to the answer it wants you to show.






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    First mark is for saying r= integral of y dx
    Then differentiate x and find what dt is. Put it in and simplify.

    Change the bounds too


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    cant do b
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    (Original post by Yua)


    cant do b
    When x=0 g(x)=3 look at the graph 3>g(x)>0
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    (Original post by Medicjug)
    When x=0 g(x)=3 look at the graph 3>g(x)>0
    But g(x) can never go below 1/2 as x tends to infinity so it'd be 3 >= g(x) > 1/2

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    (Original post by skyakdu)
    But g(x) can never go below 1/2 as x tends to infinity so it'd be 3 >= g(x) > 1/2

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    Wrong thread


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    Let The Games Commence

    Alright Guys Lets Quit The Small Talk Now. I am asking for one thing, and one thing only!:
    5 TOP tips on how to ace this exam
    When i say ace, I don't mean a measly 65/75, I don't even mean a sky-high 70 (giving a god damn a*), I am talking 73/75. You heard right people 73 the stuff of dreams.
    Best answer will gain my full approval, I shall also owe that sir/Madame my life
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    (Original post by Wahid1)
    Wrong thread


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    How exactly?

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    (Original post by skyakdu)
    How exactly?

    Posted from TSR Mobile
    That **** is c3


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    (Original post by NightAl96)
    Let The Games Commence

    Alright Guys Lets Quit The Small Talk Now. I am asking for one thing, and one thing only!:
    5 TOP tips on how to ace this exam
    When i say ace, I don't mean a measly 65/75, I don't even mean a sky-high 70 (giving a god damn a*), I am talking 73/75. You heard right people 73 the stuff of dreams.
    Best answer will gain my full approval, I shall also owe that sir/Madame my life
    come on guys I haven't got all day!
    well I do but no more than 1 day cos the exams tomorrow
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    (Original post by NightAl96)
    come on guys I haven't got all day!
    well I do but no more than 1 day cos the exams tomorrow
    No it's not its on Tuesday


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    (Original post by Wahid1)
    No it's not its on Tuesday


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    C3s tomorrow
 
 
 
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