You are Here: Home >< Maths

# AQA maths core 1, 13th May 2015 watch

1. (Original post by Rob194656)
I think most people have said d2y dx2 was -12pi, which is the simplified version of what I wrote.
I used the value 3.14 instead of pi and got -37.68 and said it is a maximum will i get the marks.
2. (Original post by marklowell96)
I used the value 3.14 instead of pi and got -37.68 and said it is a maximum will i get the marks.
how did you do that calculation in your head in the first place? but yes you will still get the marks and was it definitely 12 pi because I got that answer but my teacher said it was 12r earlier?
3. (Original post by r-star)
What was d2y/dx^2 i got 24-3pir is thiss right?
Dy/Dx was 24-3piR^2 I think then d2y/dx2 was -3Pi I think?
4. (Original post by JackMac123)
how did you do that calculation in your head in the first place? but yes you will still get the marks and was it definitely 12 pi because I got that answer but my teacher said it was 12r earlier?
12*3=36
12*0.14=12*14/100 so I got 168/100=1.68

36+1.68=37.68

because it was negative 2 i placed a negative in front of my answer
5. (Original post by r-star)
so how was max=-12pi?
Because d2y/dx2 was -3pi because that was differentiated from 24-3piR
6. (Original post by marklowell96)
12*3=36
12*0.14=12*14/100 so I got 168/100=1.68

36+1.68=37.68

because it was negative 2 i placed a negative in front of my answer
Fair enough, I just left it as -12pi, I am just worried whether it was -12pi because I got that answer however someone in my class got a different answer
7. (Original post by JackMac123)
Fair enough, I just left it as -12pi, I am just worried whether it was -12pi because I got that answer however someone in my class got a different answer
Pretty sure it was the majority of people in my class got that.
8. (Original post by JackMac123)
Because d2y/dx2 was -3pi because that was differentiated from 24-3piR
Dy over dx was 24pi-3pir^2/2
D2y over dx2 i got as 24-3pir
9. Hey for the question numbers i wrote just -a- and for parts just -ii- not -a-ii- does it matter as long as its clear what question you are answering
10. What was the equation of the curve in this question?
11. What was the equation of the curve in the integration question?
12. (Original post by JackMac123)
Fair enough, I just left it as -12pi, I am just worried whether it was -12pi because I got that answer however someone in my class got a different answer
The second derivative came out to -12pi
13. (Original post by ProNoob)
Worst case senerio 0
Best case senerio 2

Posted from TSR Mobile
Surely I can't get 0 I still got stationary value as 4
14. (Original post by SunDun111)
Surely I can't get 0 I still got stationary value as 4
1 mark for stating dy/dx=0
1 mark for r=4
1 mark for getting g d2y/dx^2 i think was 24-3pir??
1 mark for saying -12pi-maximum
????
or maybe you wont get mark for dy dx =0 butfor subbing in r=4 in d2y/dx^2
15. What did you guys get for the remainder question, where the equation had to be divided by x-4?
16. (Original post by J-To-The-Era-Wig)
What did you guys get for the remainder question, where the equation had to be divided by x-4?
36 if I remember correctly
17. (Original post by r-star)
1 mark for stating dy/dx=0
1 mark for r=4
1 mark for getting g d2y/dx^2 i think was 24-3pir??
1 mark for saying -12pi-maximum
????
or maybe you wont get mark for dy dx =0 butfor subbing in r=4 in d2y/dx^2
I made dy/dx = 0 and got 4 but d2y/dx2 I did wrong, would I get two
18. (Original post by C0balt)
36 if I remember correctly
Ahhh good, I got that but I didn't do long division :/ will I lose a mark or two for that?
19. (Original post by J-To-The-Era-Wig)
Ahhh good, I got that but I didn't do long division :/ will I lose a mark or two for that?
No, it asked you to use remainder theorem i.e. plugging a value into the equation and seeing what comes out. The only time you need to use algebraic division is when it asks you for the quotient and the remainder.
20. (Original post by razzmataz1478)
No, it asked you to use remainder theorem i.e. plugging a value into the equation and seeing what comes out. The only time you need to use algebraic division is when it asks you for the quotient and the remainder.
Sweet. I'm on for 100% now 😀

### Related university courses

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: January 27, 2016
Today on TSR

### Edexcel C4 Maths Unofficial Markscheme

Find out how you've done here

### 990

students online now

Exam discussions

### Find your exam discussion here

Poll
Useful resources

Can you help? Study help unanswered threadsStudy Help rules and posting guidelinesLaTex guide for writing equations on TSR

## Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE