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    (Original post by Rob194656)
    I think most people have said d2y dx2 was -12pi, which is the simplified version of what I wrote.
    I used the value 3.14 instead of pi and got -37.68 and said it is a maximum will i get the marks.
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    (Original post by marklowell96)
    I used the value 3.14 instead of pi and got -37.68 and said it is a maximum will i get the marks.
    how did you do that calculation in your head in the first place? but yes you will still get the marks and was it definitely 12 pi because I got that answer but my teacher said it was 12r earlier?
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    (Original post by r-star)
    What was d2y/dx^2 i got 24-3pir is thiss right?
    Dy/Dx was 24-3piR^2 I think then d2y/dx2 was -3Pi I think?
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    (Original post by JackMac123)
    how did you do that calculation in your head in the first place? but yes you will still get the marks and was it definitely 12 pi because I got that answer but my teacher said it was 12r earlier?
    12*3=36
    12*0.14=12*14/100 so I got 168/100=1.68

    36+1.68=37.68

    because it was negative 2 i placed a negative in front of my answer
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    (Original post by r-star)
    so how was max=-12pi?
    Because d2y/dx2 was -3pi because that was differentiated from 24-3piR
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    (Original post by marklowell96)
    12*3=36
    12*0.14=12*14/100 so I got 168/100=1.68

    36+1.68=37.68

    because it was negative 2 i placed a negative in front of my answer
    Fair enough, I just left it as -12pi, I am just worried whether it was -12pi because I got that answer however someone in my class got a different answer
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    (Original post by JackMac123)
    Fair enough, I just left it as -12pi, I am just worried whether it was -12pi because I got that answer however someone in my class got a different answer
    Pretty sure it was the majority of people in my class got that.
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    (Original post by JackMac123)
    Because d2y/dx2 was -3pi because that was differentiated from 24-3piR
    Dy over dx was 24pi-3pir^2/2
    D2y over dx2 i got as 24-3pir
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    Hey for the question numbers i wrote just -a- and for parts just -ii- not -a-ii- does it matter as long as its clear what question you are answering
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    What was the equation of the curve in this question?
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    What was the equation of the curve in the integration question?
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    (Original post by JackMac123)
    Fair enough, I just left it as -12pi, I am just worried whether it was -12pi because I got that answer however someone in my class got a different answer
    The second derivative came out to -12pi
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    (Original post by ProNoob)
    Worst case senerio 0
    Best case senerio 2

    Posted from TSR Mobile
    Surely I can't get 0 I still got stationary value as 4
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    (Original post by SunDun111)
    Surely I can't get 0 I still got stationary value as 4
    1 mark for stating dy/dx=0
    1 mark for r=4
    1 mark for getting g d2y/dx^2 i think was 24-3pir??
    1 mark for saying -12pi-maximum
    ????
    or maybe you wont get mark for dy dx =0 butfor subbing in r=4 in d2y/dx^2
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    What did you guys get for the remainder question, where the equation had to be divided by x-4?
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    (Original post by J-To-The-Era-Wig)
    What did you guys get for the remainder question, where the equation had to be divided by x-4?
    36 if I remember correctly
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    (Original post by r-star)
    1 mark for stating dy/dx=0
    1 mark for r=4
    1 mark for getting g d2y/dx^2 i think was 24-3pir??
    1 mark for saying -12pi-maximum
    ????
    or maybe you wont get mark for dy dx =0 butfor subbing in r=4 in d2y/dx^2
    I made dy/dx = 0 and got 4 but d2y/dx2 I did wrong, would I get two
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    (Original post by C0balt)
    36 if I remember correctly
    Ahhh good, I got that but I didn't do long division :/ will I lose a mark or two for that?
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    (Original post by J-To-The-Era-Wig)
    Ahhh good, I got that but I didn't do long division :/ will I lose a mark or two for that?
    No, it asked you to use remainder theorem i.e. plugging a value into the equation and seeing what comes out. The only time you need to use algebraic division is when it asks you for the quotient and the remainder.
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    (Original post by razzmataz1478)
    No, it asked you to use remainder theorem i.e. plugging a value into the equation and seeing what comes out. The only time you need to use algebraic division is when it asks you for the quotient and the remainder.
    Sweet. I'm on for 100% now 😀
 
 
 
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