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Edexcel S2 - 27th June 2016 AM Watch

  • View Poll Results: How did you find the Edexcel S2 exam?
    Very hard
    145
    14.71%
    Hard
    331
    33.57%
    Normal
    293
    29.72%
    Easy
    152
    15.42%
    Very easy
    65
    6.59%

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    20
    (Original post by Student403)
    5) 225 (i got 342.25 too but put 225 as my final answer. Not sure of the correct reason)
    I completely screwed up this question lol

    But the other answers I recognise
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    (Original post by redraccoon)
    Anyone remember how much the finding k part of the question was worth? I got a as 11 which I think was wrong so I got the wrong answer for k... wondering how much I would've lost
    k = 1/9
    a = -13 I think
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    (Original post by imran_)
    What would 56 marks be in UMS?


    Posted from TSR Mobile
    Just find the percentage so in your case 75 UMS
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    (Original post by BinaryJava)
    k = 1/9
    a = -13 I think
    i think a was -12
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    (Original post by Mathemagicien)
    I completely screwed up this question lol

    But the other answers I recognise
    Unlucky bro Well done on the others! How's your offer going?
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    Well, that was a disaster. I couldn't do the normal approximation (got z=1.75 but couldn't rearrange), the c.d.f or the last part of the last question. I'm guessing this is going to be my lowest UMS ever.
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    (Original post by Dannyfire)
    How do you prove b=8?
    Differentiate twice to find the turning point and sub in x=8/3
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    (Original post by jonnypdot)
    what was the awnser for var(x) do you find e(x^2)-(e(x))^2
    I got 0.24- don't understand where they're getting 1.92 from
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    (Original post by Student403)
    Unlucky bro Well done on the others! How's your offer going?
    I think its good - did well on STEP, and can probably afford to mess up this module and D2 since I've done pretty well on all the other modules

    How about you?
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    (Original post by amitbalter)
    i got 0.24- don't understand where they're getting 1.92 from
    omg same
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    (Original post by Mathemagicien)
    I think its good - did well on STEP, and can probably afford to mess up this module and D2 since I've done pretty well on all the other modules

    How about you?
    Nice! I have no offer
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    (Original post by Amitbalter)
    I got 0.24- don't understand where they're getting 1.92 from
    bro i got 0.24 too, plus a small number makes sense instead of a number like 1.92 b/c var(x) is a measure how spread the data is, the interval is 0 to 2 to there will be little spread
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    (Original post by hfd)
    From your revision, can you recommend some of the hardest S2 papers you have tried? Best to prepare for the worst and hope for the best!

    I found June 2003 Q4 particularly challenging is you are looking for one to try.
    Probably not really helpful to do past papers from before 2009. The curriculum for some of the units before then is quite different.
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    (Original post by Vlad Murzakov)
    For q3, wasn't it 49π? E(X)=5+9/2=7E(A)= πr^2= 49π
    thats what i got
    E(r) as 7.
    then E(A) as 49 pi
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    Does anyone remember how many marks each question and parts of questions were worth?
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    My variance for question 7 was 0.24.
    My Ex was 1.2 and Ex^2 was 1.68.
    Variance=1.68-(1.2)^2 which give 0.24
    Please reply if you got this, thanks
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    Here are the real answers I am very confident they are all right
    1.
    a) Mean = 1.41
    Variance = 1.4419
    b) mean approximately equals the variance therefore Poisson is suitable
    c)
    i) 0.2510
    ii)0.7769
    d) 0.1378
    e)0.1516
    2.
    a) 60
    b)
    i) 0.0133
    ii)0.0159
    c) 0.2369>0.01 therefore do not reject H0 his claim is not supported
    3.
    a) f(R)={0.25 , 5<R<9
    {0 , otherwise
    b) P(7<R<10)= (10-7)x0.25= 0.75
    c)E(A)=E(piR^2)=PiE(R^2) = 151pi/3
    4.
    a) show by differentiating to find the pdf then differentiating again and setting it equal to zero to find maximum k cannot be zero the for solving what is in the bracket gives you that b=8.
    b) I think there are a lot of ways to do this question, I solved for a first but k=1/9
    5.
    n=225 ignore the negative value because the standard deviation is always positive and plus you can't get a fraction of a student.
    6.
    a) (4,4)(6,6)(8,8)
    (4,6)(4,8)(6,4)
    (6,8)(8,4)(8,6)
    b) m 4 5 6 7 8
    P(M=m) 1/4 3/10 29/100 3/25 1/25
    c)Y~B(n,1/25)
    P(Y>=1)>0.9
    1-P(Y=0)>0.9
    P(y=0)<0.1
    0.96^n<0.1
    taking logs( don't forget to switch the inequality)
    you get n>56....
    therefore the smallest value for n is 57
    7.
    a) E(x)=1.2
    b)Var(x)=0.24
    c) P(X>1.5)=0.325
    d)£41.88
    e) He should not as 40 <41.88
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    (Original post by Student403)
    Nice! I have no offer
    So your business here is just to drive up our grade boundaries?
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    (Original post by igotohaggerston)
    Here are the real answers I am very confident they are all right
    1.
    a) Mean = 1.41
    Variance = 1.4419
    b) mean approximately equals the variance therefore Poisson is suitable
    c)
    i) 0.2510
    ii)0.7769
    d) 0.1378
    e)0.1516
    2.
    a) 60
    b)
    i) 0.0133
    ii)0.0159
    c) 0.2369>0.01 therefore do not reject H0 his claim is not supported
    3.
    a) f(R)={0.25 , 5<R<9
    {0 , otherwise
    b) P(7<R<10)= (10-7)x0.25= 0.75
    c)E(A)=E(piR^2)=PiE(R^2) = 151pi/3
    4.
    a) show by differentiating to find the pdf then differentiating again and setting it equal to zero to find maximum k cannot be zero the for solving what is in the bracket gives you that b=8.
    b) I think there are a lot of ways to do this question, I solved for a first but k=1/9
    5.
    n=225 ignore the negative value because the standard deviation is always positive and plus you can't get a fraction of a student.
    6.
    a) (4,4)(6,6)(8,8)
    (4,6)(4,8)(6,4)
    (6,8)(8,4)(8,6)
    b) m 4 5 6 7 8
    P(M=m) 1/4 3/10 29/100 3/25 1/25
    c)Y~B(n,1/25)
    P(Y>=1)>0.9
    1-P(Y=0)>0.9
    P(y=0)<0.1
    0.96^n<0.1
    taking logs( don't forget to switch the inequality)
    you get n>56....
    therefore the smallest value for n is 57
    7.
    a) E(x)=1.2
    b)Var(x)=0.24
    c) P(X>1.5)=0.325
    d)£41.88
    e) He should not as 40 <41.88
    Wasn't N 342.5 or something like that?
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    What do you predict grade boundaries will be?
 
 
 
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