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    Incredibly pedantic question:
    Is the sequence 1, 1, 1, 1, ..., 1 an arithmetic sequence, a geometric sequence, or both? Essentially what I'm asking is that are d ≠ 0 and r ≠ 1 conditions for APs and GPs?
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    (Original post by RuairiMorrissey)
    Solve what?
    Dw thanks though
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    (Original post by ShatnersBassoon)
    Incredibly pedantic question:
    Is the sequence 1, 1, 1, 1, ..., 1 an arithmetic sequence, a geometric sequence, or both? Essentially what I'm asking is that are d ≠ 0 and r ≠ 1 conditions for APs and GPs?
    It's both.
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    (Original post by ShatnersBassoon)
    Incredibly pedantic question:
    Is the sequence 1, 1, 1, 1, ..., 1 an arithmetic sequence, a geometric sequence, or both? Essentially what I'm asking is that are d ≠ 0 and r ≠ 1 conditions for APs and GPs?
    You could argue it's both or neither (just a bunch of ones), but I guess both makes a bit more sense.
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    [QUOTE=Nonamebzja;68315928]
    (Original post by joodaa)

    Not really a method felt like cheating i just saif F(x)=X^2 so f(x) must equal 2t cuz when u integrate that between x and 0 it equals X^2
    And dy/dx of X^2 is 2x which is f(x)-f(0) [subbing values in 2t f(x)]
    Are you sure this is correct?
    Using your method iii could also be correct.

    If you use f(t)= 2t + 4 then I got the answer to be iii. Please check?

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    [QUOTE=Nonamebzja;68315788]
    (Original post by theaverage)
    I feel like this ones very obvious but please could someone explain

    Posted from TSR Mobile[/QUOT
    I got f(x)-f(0) was that answer?
    No, the derivative of \int_a^x f(t)\,dt is f(x). This is the fundamental theorem of calculus.
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    (Original post by theaverage)
    I feel like this ones very obvious but please could someone explain

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    is the answer a?
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    [QUOTE=DFranklin;68319852]
    (Original post by Nonamebzja)
    No, the derivative of \int_a^x f(t)\,dt is f(x). This is the fundamental theorem of calculus.
    so is the answer c?
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    [QUOTE=DFranklin;68319852]
    (Original post by Nonamebzja)
    No, the derivative of \int_a^x f(t)\,dt is f(x). This is the fundamental theorem of calculus.
    Oops 🙈
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    [QUOTE=theaverage;68319810]
    (Original post by Nonamebzja)

    Are you sure this is correct?
    Using your method iii could also be correct.

    If you use f(t)= 2t + 4 then I got the answer to be iii. Please check?

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    Yeh true i was stupid sorry about that amd even using X^2 both i and iii work didnt notice
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    hey, is there anyone applying to maths and philosophy?
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    (Original post by testy99)
    hey, is there anyone applying to maths and philosophy?
    Yes
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    [QUOTE=DFranklin;68319852]
    (Original post by Nonamebzja)
    No, the derivative of \int_a^x f(t)\,dt is f(x). This is the fundamental theorem of calculus.
    Right, thanks

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    (Original post by theaverage)
    I feel like this ones very obvious but please could someone explain

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    Did this come from a past paper or a mock?
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    (Original post by RuairiMorrissey)
    You could argue it's both or neither (just a bunch of ones), but I guess both makes a bit more sense.
    How would you argue it's neither?
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    (Original post by testy99)
    hey, is there anyone applying to maths and philosophy?
    Me too. which a levels did you take? ive taken maths, FM and chem
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    Is this an acceptable answer for 2015 2 part iv or have I made a wrong assumption in line 4
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    Hello have done all papers of MAT from 07-15. Any other papers (1 or 2) I can do ?
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    I'm going to have a day off, watch a movie tonight. No point in doing lots of work today.

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    [QUOTE=Mystery.;[url="tel:68319898"]68319898[/url]]
    (Original post by DFranklin;[url="tel:68319852")
    68319852[/url]]

    so is the answer c?
    Yup. Suppose f integrates to F. Then the integral is equal to F(x)-F(0) where F(0) is a constant. Differentiating with respect to x gives f(x).
 
 
 
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