# AQA PHYA4 ~ 13th June 2013 ~ A2 Physics Watch

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#941

Thought I'd done terribly on this but looking at the answers people have put, I might not have done as bad as I thought

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#942

(Original post by

Why does it say 14 on MS? I hope we are right. Damnnnn

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**cooldudeman**)Why does it say 14 on MS? I hope we are right. Damnnnn

Posted from TSR Mobile

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#943

http://www.universetoday.com/19732/radius-of-the-moon/

it states:

it states:

Need a comparison? The average radius of the Earth is 6,371.0 km. In other words, the Earth is about 4 times larger than the Moon.

Does this mean the answer was 3.7!??! or did i misread the question lol

Does this mean the answer was 3.7!??! or did i misread the question lol

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#944

(Original post by

17)

**saba146**)17)

**momentum question when the 2 trolleys collided?anyone remeber the answer??**

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#945

1)t root2,

2)460 and current its greater that 0.26,

3)path of electron was A the arrow pointing upwards,

4)potential at mars was -13,

5)maximum value of tension was 24

6) K.E: P>Q, G.P.E: Q<P

7) capacitance graph question was D,

8) fe>fm>fs

9） ratio of y/d=1/3 – I got 2/3 :/

10) R earth/Rmoon=14 ----- >As I remember the question:

Mass of the earth is 81 x mass of the moon

Gravitational field strength on the earth = 9.8

Gravitational field strength on the moon = 1.8

g = GM/r^2.

9.8 = 81GM/re^2

1.8 = GM/rm^2

Re-arrange and you get re^2/rm^2 = ~14.88

11)which one is incorrect: when spring is compressed &suspended,it has minimum PE

12) which one is incorrect: change of momentum=zero

13)moving horizontally,Blv …

14)rotating coil was A q14 from http://papers.xtremepapers.com/AQA/P...W-QP-JAN03.pdf

15) Capacitance value of 0.02F for one question forgot which was, answer choice was B IIRC

16) units of impulse = kgms-1

17) momentum question when the 2 trolleys collided: 12000Ns

8 MORE MULTIPLE CHOICE QUESTIONS THEN DONE!

SECTION B IS COMPLETE

1a)define shm:

acceleration is proportinal to displacement, and acceleration acts toward equilibrium (2)

acceleration was 0.4

frequency of pendulum = 0.503 3s.f (3)

1500 revs per minute (2)

time for oscilations to be in phase again = 38 (3) -- if you think about it,

after 1 oscilation - difference on 0.1s

after 2 oscillations - difference of 0.2s....

after 19 oscillations difference of 1.9 seconds

so on the 19th osciation of the 1.9s pendulum, the 2s pendulum will arrive 1.9s after it, so on the 20th oscillation of the 1.9s pendulum they are in phase. again, on the 19th oscillation of the 2s pendulum they will be in phase.

19 x 2 = 38s

20 x 1.9 = 38s

TOTAL = 12

2) voltage = 30,000 (1)

b) (3) i think this was the capacity was increase from X to Y. find the energy stored? wasnt this the time taken for the spark to be produced?

yes, i think it was similar:

b) i think this was the capacity was increase from X to Y.time taken for the spark to be produced after the last discharge?

then Q=CV, then Q/Current = time was ~ 3.46s

you had to work out the charge stored and then use the current they gave you to find the time??

c) time taken for discharge will increase because time constant increases (2)

d) flash is brighter because more energy stored (2)

TOTAL = 7

3) 6 marker on fields

1. gravity always attractive

2. electric attractive/repulsive

3. both follow inverse square for Force

4. both follow inverse for potential

5. gravity uses mass

6. electric uses charge

7. only electric fields can be shielded

8. only electric fields depend on medium between charges

9. gradient of potential vs distance graph gives field strength

10. potential definition for both revolves around bringing a mass/charge from infinity to a certain point in a field and is zero at infinity

TOTAL = 6

4) 2 conditions when no force is exerted on the partcle (2)

field is parallel to velocity

particle is stationary

b) out of the plane of the paper

b) prove momentum is proportional to radius= mv^2/r = BQv , mv = BQr --> mv = kr

the speed of particle=8.7x107

c)time taken for partile to go through 1 dee = ~6.8x10^-8

d)show the time taken is independent of radius = 2pim/bq (3)

kinetic energy im MEV = 2.44 (3)

TOTAL = 15

5)

angle for max emf = 60 degrees -- this is at 90 degrees to the plane as emf = BANw sin(wt) therefore max emf is when sin(wt) =1, there for wt (which is the angle) = 90, 90-30 = 60 degrees

angle for max flux linkage = 5pi/6 = 2.62 radians -- this is at 0 degrees = 180 degrees, and N(PHI) = BAN cos(THETA), so max is when cos(THETA) = 1 so theta = 180, 180-39 = 150 degrees = 5pi/6

gradient of graph = emf (1)

drawing a graph (2) Positive Sine graph

peak voltage (3) I got 0.55 for peak to peak voltage then divided by 2 to get 27.5V but there is no set agreement on what the value is for this answer yet.. (MSI_10)

calculate flux density = 0.26 (2)( got 0.25 here

TOTAL= 10

Okay i'm going now... this is the best mark scheme ive done so far, ive tried to incorporate the others! please feel free to edit it!

2)460 and current its greater that 0.26,

3)path of electron was A the arrow pointing upwards,

4)potential at mars was -13,

5)maximum value of tension was 24

6) K.E: P>Q, G.P.E: Q<P

7) capacitance graph question was D,

8) fe>fm>fs

9） ratio of y/d=1/3 – I got 2/3 :/

10) R earth/Rmoon=14 ----- >As I remember the question:

Mass of the earth is 81 x mass of the moon

Gravitational field strength on the earth = 9.8

Gravitational field strength on the moon = 1.8

g = GM/r^2.

9.8 = 81GM/re^2

1.8 = GM/rm^2

Re-arrange and you get re^2/rm^2 = ~14.88

11)which one is incorrect: when spring is compressed &suspended,it has minimum PE

12) which one is incorrect: change of momentum=zero

13)moving horizontally,Blv …

14)rotating coil was A q14 from http://papers.xtremepapers.com/AQA/P...W-QP-JAN03.pdf

15) Capacitance value of 0.02F for one question forgot which was, answer choice was B IIRC

16) units of impulse = kgms-1

17) momentum question when the 2 trolleys collided: 12000Ns

8 MORE MULTIPLE CHOICE QUESTIONS THEN DONE!

SECTION B IS COMPLETE

1a)define shm:

acceleration is proportinal to displacement, and acceleration acts toward equilibrium (2)

acceleration was 0.4

frequency of pendulum = 0.503 3s.f (3)

1500 revs per minute (2)

time for oscilations to be in phase again = 38 (3) -- if you think about it,

after 1 oscilation - difference on 0.1s

after 2 oscillations - difference of 0.2s....

after 19 oscillations difference of 1.9 seconds

so on the 19th osciation of the 1.9s pendulum, the 2s pendulum will arrive 1.9s after it, so on the 20th oscillation of the 1.9s pendulum they are in phase. again, on the 19th oscillation of the 2s pendulum they will be in phase.

19 x 2 = 38s

20 x 1.9 = 38s

TOTAL = 12

2) voltage = 30,000 (1)

b) (3) i think this was the capacity was increase from X to Y. find the energy stored? wasnt this the time taken for the spark to be produced?

yes, i think it was similar:

b) i think this was the capacity was increase from X to Y.time taken for the spark to be produced after the last discharge?

then Q=CV, then Q/Current = time was ~ 3.46s

you had to work out the charge stored and then use the current they gave you to find the time??

c) time taken for discharge will increase because time constant increases (2)

d) flash is brighter because more energy stored (2)

TOTAL = 7

3) 6 marker on fields

1. gravity always attractive

2. electric attractive/repulsive

3. both follow inverse square for Force

4. both follow inverse for potential

5. gravity uses mass

6. electric uses charge

7. only electric fields can be shielded

8. only electric fields depend on medium between charges

9. gradient of potential vs distance graph gives field strength

10. potential definition for both revolves around bringing a mass/charge from infinity to a certain point in a field and is zero at infinity

TOTAL = 6

4) 2 conditions when no force is exerted on the partcle (2)

field is parallel to velocity

particle is stationary

b) out of the plane of the paper

b) prove momentum is proportional to radius= mv^2/r = BQv , mv = BQr --> mv = kr

the speed of particle=8.7x107

c)time taken for partile to go through 1 dee = ~6.8x10^-8

d)show the time taken is independent of radius = 2pim/bq (3)

kinetic energy im MEV = 2.44 (3)

TOTAL = 15

5)

angle for max emf = 60 degrees -- this is at 90 degrees to the plane as emf = BANw sin(wt) therefore max emf is when sin(wt) =1, there for wt (which is the angle) = 90, 90-30 = 60 degrees

angle for max flux linkage = 5pi/6 = 2.62 radians -- this is at 0 degrees = 180 degrees, and N(PHI) = BAN cos(THETA), so max is when cos(THETA) = 1 so theta = 180, 180-39 = 150 degrees = 5pi/6

gradient of graph = emf (1)

drawing a graph (2) Positive Sine graph

peak voltage (3) I got 0.55 for peak to peak voltage then divided by 2 to get 27.5V but there is no set agreement on what the value is for this answer yet.. (MSI_10)

calculate flux density = 0.26 (2)( got 0.25 here

TOTAL= 10

Okay i'm going now... this is the best mark scheme ive done so far, ive tried to incorporate the others! please feel free to edit it!

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#946

(Original post by

that's 19 oscilations, if you think about it,

after 1 oscilation - difference on 0.1s

after 2 oscillations - difference of 0.2s....

after 19 oscillations difference of 1.9 seconds

so on the 19th osciation of the 1.9s pendulum, the 2s pendulum will arrive 1.9s after it, so on the 20th oscillation of the 1.9s pendulum they are in phase. again, on the 19th oscillation of the 2s pendulum they will be in phase.

19 x 2 = 38s

20 x 1.9 = 38s

hope I helped!

**MisterE1**)that's 19 oscilations, if you think about it,

after 1 oscilation - difference on 0.1s

after 2 oscillations - difference of 0.2s....

after 19 oscillations difference of 1.9 seconds

so on the 19th osciation of the 1.9s pendulum, the 2s pendulum will arrive 1.9s after it, so on the 20th oscillation of the 1.9s pendulum they are in phase. again, on the 19th oscillation of the 2s pendulum they will be in phase.

19 x 2 = 38s

20 x 1.9 = 38s

hope I helped!

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#947

1)t root2,

2)460 and current its greater that 0.26,

3)path of electron was A the arrow pointing upwards,

4)potential at moon or something was -13,

5)maximum value of tension was 24

6) kinetic energy of p was greater than q but potential energy was less that q

7) capacitance graph question was D,

8) fe>fm>fs(i think that is Fe>Fs>Fm)

9） ratio of y/d=1/3

10) R earth/Rmoon=3.7

11)which one is incorrect: when spring is compressed &suspended,it has minimum PE

12) which one is incorrect: change of momentum=zero

13)moving horizontally,Blv …

14)rotating coil was A

15) Capacitance value of 0.02F for one question forgot which was, answer choice was B IIRC

16) units of impulse = kgms-1

momentum question when the 2 trolleys collided 12000

18)negative ion being moved in an electric field but cant remeber the answer

7 MORE MULTIPLE CHOICE QUESTIONS THEN DONE!

SECTION B IS COMPLETE

1a)define shm:

acceleration is proportinal to displacement, and acceleration acts toward equilibrium (2)

acceleration was 0.4

frequency of pendulum = 0.503 3s.f (3)

1500 revs per minute (2)

time for oscilations to be in phase again = 38 (3)

TOTAL = 12

2) voltage = 30,000 (1)

b) (3) i think this was the capacity was increase from X to Y. find the energy stored? wasnt this the time taken for the spark to be produced?

yes, i think it was similar:

b) i think this was the capacity was increase from X to Y.time taken for the spark to be produced after the last discharge?

then Q=CV, then Q/Current = time was ~ 3.46s

you had to work out the charge stored and then use the current they gave you to find the time??

c) time taken for discharge will increase because time constant increases (2)

d) flash is brighter because more energy stored (2)

TOTAL = 7

3) 6 marker on fields

1. gravity always attractive

2. electric attractive/repulsive

3. both follow inverse square for Force

4. both follow inverse for potential

5. gravity uses mass

6. electric uses charge

7. only electric fields can be shielded

8. only electric fields depend on medium between charges

9. gradient of potential vs distance graph gives field strength

10. potential definition for both revolves around bringing a mass/charge from infinity to a certain point in a field and is zero at infinity

TOTAL = 6

4) 2 conditions when no force is exerted on the partcle (2)

field is parallel to velocity

particle is stationary

b) out of the plane of the paper

b) prove momentum is proportional to radius= mv^2/r = BQv , mv = BQr --> mv = kr

the speed of particle=8.7x107

c)time taken for partile to go through 1 dee = ~6.8x10^-8

d)show the time taken is independent of radius = 2pim/bq (3)

kinetic energy im MEV = 2.44 (3)

TOTAL = 15

angle for max emf = 60 degrees -- this is at 90 degrees to the plane as emf = BANw sin(wt) therefore max emf is when sin(wt) =1, there for wt (which is the angle) = 90, 90-30 = 60 degreed

angle for max flux linkage = 5pi/6 = 2.62 radians -- this is at 0 degrees = 180 degrees, and N(PHI) = BAN cos(THETA), so max is when cos(THETA) = 1 so theta = 180, 180-39 = 150 degrees = 5pi/6

gradient of graph = emf (1)

drawing a graph (2) Positive Sine graph

peak voltage (3)

calculate flux density = 0.26 (2)( got 0.25 here

TOTAL= 10

2)460 and current its greater that 0.26,

3)path of electron was A the arrow pointing upwards,

4)potential at moon or something was -13,

5)maximum value of tension was 24

6) kinetic energy of p was greater than q but potential energy was less that q

7) capacitance graph question was D,

8) fe>fm>fs(i think that is Fe>Fs>Fm)

9） ratio of y/d=1/3

10) R earth/Rmoon=3.7

11)which one is incorrect: when spring is compressed &suspended,it has minimum PE

12) which one is incorrect: change of momentum=zero

13)moving horizontally,Blv …

14)rotating coil was A

15) Capacitance value of 0.02F for one question forgot which was, answer choice was B IIRC

16) units of impulse = kgms-1

momentum question when the 2 trolleys collided 12000

18)negative ion being moved in an electric field but cant remeber the answer

7 MORE MULTIPLE CHOICE QUESTIONS THEN DONE!

SECTION B IS COMPLETE

1a)define shm:

acceleration is proportinal to displacement, and acceleration acts toward equilibrium (2)

acceleration was 0.4

frequency of pendulum = 0.503 3s.f (3)

1500 revs per minute (2)

time for oscilations to be in phase again = 38 (3)

TOTAL = 12

2) voltage = 30,000 (1)

b) (3) i think this was the capacity was increase from X to Y. find the energy stored? wasnt this the time taken for the spark to be produced?

yes, i think it was similar:

b) i think this was the capacity was increase from X to Y.time taken for the spark to be produced after the last discharge?

then Q=CV, then Q/Current = time was ~ 3.46s

you had to work out the charge stored and then use the current they gave you to find the time??

c) time taken for discharge will increase because time constant increases (2)

d) flash is brighter because more energy stored (2)

TOTAL = 7

3) 6 marker on fields

1. gravity always attractive

2. electric attractive/repulsive

3. both follow inverse square for Force

4. both follow inverse for potential

5. gravity uses mass

6. electric uses charge

7. only electric fields can be shielded

8. only electric fields depend on medium between charges

9. gradient of potential vs distance graph gives field strength

10. potential definition for both revolves around bringing a mass/charge from infinity to a certain point in a field and is zero at infinity

TOTAL = 6

4) 2 conditions when no force is exerted on the partcle (2)

field is parallel to velocity

particle is stationary

b) out of the plane of the paper

b) prove momentum is proportional to radius= mv^2/r = BQv , mv = BQr --> mv = kr

the speed of particle=8.7x107

c)time taken for partile to go through 1 dee = ~6.8x10^-8

d)show the time taken is independent of radius = 2pim/bq (3)

kinetic energy im MEV = 2.44 (3)

TOTAL = 15

angle for max emf = 60 degrees -- this is at 90 degrees to the plane as emf = BANw sin(wt) therefore max emf is when sin(wt) =1, there for wt (which is the angle) = 90, 90-30 = 60 degreed

angle for max flux linkage = 5pi/6 = 2.62 radians -- this is at 0 degrees = 180 degrees, and N(PHI) = BAN cos(THETA), so max is when cos(THETA) = 1 so theta = 180, 180-39 = 150 degrees = 5pi/6

gradient of graph = emf (1)

drawing a graph (2) Positive Sine graph

peak voltage (3)

calculate flux density = 0.26 (2)( got 0.25 here

TOTAL= 10

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#948

1)t root2,

2)460 and current its greater that 0.26,

3)path of electron was A the arrow pointing upwards,

4)potential at mars was -13,

5)maximum value of tension was 24

6) K.E: P>Q, G.P.E: Q<P

7) capacitance graph question was D,

8) fe>fm>fs

9） ratio of y/d=1/3 – I got 2/3 :/

10) R earth/Rmoon=14 ----- >As I remember the question:

Mass of the earth is 81 x mass of the moon

Gravitational field strength on the earth = 9.8

Gravitational field strength on the moon = 1.8

g = GM/r^2.

9.8 = 81GM/re^2

1.8 = GM/rm^2

Re-arrange and you get re^2/rm^2 = ~14.88

11)which one is incorrect: when spring is compressed &suspended,it has minimum PE

12) which one is incorrect: change of momentum=zero

13)moving horizontally,Blv …

14)rotating coil was A q14 from http://papers.xtremepapers.com/AQA/P...W-QP-JAN03.pdf

15) Capacitance value of 0.02F for one question forgot which was, answer choice was B IIRC

16) units of impulse = kgms-1

17) momentum question when the 2 trolleys collided: 12000Ns

18) negative ion moving through 2 plates, the lower earthed the upper at + 50V, the ion moved downwards towards the earthed plate

SECTION B IS COMPLETE

1a)define shm:

acceleration is proportinal to displacement, and acceleration acts toward equilibrium (2)

acceleration was 0.4

frequency of pendulum = 0.503 3s.f (3)

1500 revs per minute (2)

time for oscilations to be in phase again = 38 (3) -- if you think about it,

after 1 oscilation - difference on 0.1s

after 2 oscillations - difference of 0.2s....

after 19 oscillations difference of 1.9 seconds

so on the 19th osciation of the 1.9s pendulum, the 2s pendulum will arrive 1.9s after it, so on the 20th oscillation of the 1.9s pendulum they are in phase. again, on the 19th oscillation of the 2s pendulum they will be in phase.

19 x 2 = 38s

20 x 1.9 = 38s

TOTAL = 12

2) voltage = 30,000 (1)

b) (3) i think this was the capacity was increase from X to Y. find the energy stored? wasnt this the time taken for the spark to be produced?

yes, i think it was similar:

b) i think this was the capacity was increase from X to Y.time taken for the spark to be produced after the last discharge?

then Q=CV, then Q/Current = time was ~ 3.46s

you had to work out the charge stored and then use the current they gave you to find the time??

c) time taken for discharge will increase because time constant increases (2)

d) flash is brighter because more energy stored (2)

TOTAL = 7

3) 6 marker on fields

1. gravity always attractive

2. electric attractive/repulsive

3. both follow inverse square for Force

4. both follow inverse for potential

5. gravity uses mass

6. electric uses charge

7. only electric fields can be shielded

8. only electric fields depend on medium between charges

9. gradient of potential vs distance graph gives field strength

10. potential definition for both revolves around bringing a mass/charge from infinity to a certain point in a field and is zero at infinity

TOTAL = 6

4) 2 conditions when no force is exerted on the partcle (2)

field is parallel to velocity

particle is stationary

b) out of the plane of the paper

b) prove momentum is proportional to radius= mv^2/r = BQv , mv = BQr --> mv = kr

the speed of particle=8.7x107

c)time taken for partile to go through 1 dee = ~6.8x10^-8

d)show the time taken is independent of radius = 2pim/bq (3)

kinetic energy im MEV = 2.44 (3)

TOTAL = 15

5)

angle for max emf = 60 degrees -- this is at 90 degrees to the plane as emf = BANw sin(wt) therefore max emf is when sin(wt) =1, there for wt (which is the angle) = 90, 90-30 = 60 degrees

angle for max flux linkage = 5pi/6 = 2.62 radians -- this is at 0 degrees = 180 degrees, and N(PHI) = BAN cos(THETA), so max is when cos(THETA) = 1 so theta = 180, 180-39 = 150 degrees = 5pi/6

gradient of graph = emf (1)

drawing a graph (2) Positive Sine graph

peak voltage (3) I got 0.55 for peak to peak voltage then divided by 2 to get 27.5V but there is no set agreement on what the value is for this answer yet.. (MSI_10)

calculate flux density = 0.26 (2)( got 0.25 here

TOTAL= 10

Okay i'm going now... this is the best mark scheme ive done so far, ive tried to incorporate the others! please feel free to edit it! MOST OF THIS WAS SABA146 not me! but I like to feel I helped

whoops I thought I was editing...

2)460 and current its greater that 0.26,

3)path of electron was A the arrow pointing upwards,

4)potential at mars was -13,

5)maximum value of tension was 24

6) K.E: P>Q, G.P.E: Q<P

7) capacitance graph question was D,

8) fe>fm>fs

9） ratio of y/d=1/3 – I got 2/3 :/

10) R earth/Rmoon=14 ----- >As I remember the question:

Mass of the earth is 81 x mass of the moon

Gravitational field strength on the earth = 9.8

Gravitational field strength on the moon = 1.8

g = GM/r^2.

9.8 = 81GM/re^2

1.8 = GM/rm^2

Re-arrange and you get re^2/rm^2 = ~14.88

11)which one is incorrect: when spring is compressed &suspended,it has minimum PE

12) which one is incorrect: change of momentum=zero

13)moving horizontally,Blv …

14)rotating coil was A q14 from http://papers.xtremepapers.com/AQA/P...W-QP-JAN03.pdf

15) Capacitance value of 0.02F for one question forgot which was, answer choice was B IIRC

16) units of impulse = kgms-1

17) momentum question when the 2 trolleys collided: 12000Ns

18) negative ion moving through 2 plates, the lower earthed the upper at + 50V, the ion moved downwards towards the earthed plate

**7 MORE MULTIPLE CHOICE QUESTIONS THEN DONE!**SECTION B IS COMPLETE

1a)define shm:

acceleration is proportinal to displacement, and acceleration acts toward equilibrium (2)

acceleration was 0.4

frequency of pendulum = 0.503 3s.f (3)

1500 revs per minute (2)

time for oscilations to be in phase again = 38 (3) -- if you think about it,

after 1 oscilation - difference on 0.1s

after 2 oscillations - difference of 0.2s....

after 19 oscillations difference of 1.9 seconds

so on the 19th osciation of the 1.9s pendulum, the 2s pendulum will arrive 1.9s after it, so on the 20th oscillation of the 1.9s pendulum they are in phase. again, on the 19th oscillation of the 2s pendulum they will be in phase.

19 x 2 = 38s

20 x 1.9 = 38s

TOTAL = 12

2) voltage = 30,000 (1)

b) (3) i think this was the capacity was increase from X to Y. find the energy stored? wasnt this the time taken for the spark to be produced?

yes, i think it was similar:

b) i think this was the capacity was increase from X to Y.time taken for the spark to be produced after the last discharge?

then Q=CV, then Q/Current = time was ~ 3.46s

you had to work out the charge stored and then use the current they gave you to find the time??

c) time taken for discharge will increase because time constant increases (2)

d) flash is brighter because more energy stored (2)

TOTAL = 7

3) 6 marker on fields

1. gravity always attractive

2. electric attractive/repulsive

3. both follow inverse square for Force

4. both follow inverse for potential

5. gravity uses mass

6. electric uses charge

7. only electric fields can be shielded

8. only electric fields depend on medium between charges

9. gradient of potential vs distance graph gives field strength

10. potential definition for both revolves around bringing a mass/charge from infinity to a certain point in a field and is zero at infinity

TOTAL = 6

4) 2 conditions when no force is exerted on the partcle (2)

field is parallel to velocity

particle is stationary

b) out of the plane of the paper

b) prove momentum is proportional to radius= mv^2/r = BQv , mv = BQr --> mv = kr

the speed of particle=8.7x107

c)time taken for partile to go through 1 dee = ~6.8x10^-8

d)show the time taken is independent of radius = 2pim/bq (3)

kinetic energy im MEV = 2.44 (3)

TOTAL = 15

5)

angle for max emf = 60 degrees -- this is at 90 degrees to the plane as emf = BANw sin(wt) therefore max emf is when sin(wt) =1, there for wt (which is the angle) = 90, 90-30 = 60 degrees

angle for max flux linkage = 5pi/6 = 2.62 radians -- this is at 0 degrees = 180 degrees, and N(PHI) = BAN cos(THETA), so max is when cos(THETA) = 1 so theta = 180, 180-39 = 150 degrees = 5pi/6

gradient of graph = emf (1)

drawing a graph (2) Positive Sine graph

peak voltage (3) I got 0.55 for peak to peak voltage then divided by 2 to get 27.5V but there is no set agreement on what the value is for this answer yet.. (MSI_10)

calculate flux density = 0.26 (2)( got 0.25 here

TOTAL= 10

Okay i'm going now... this is the best mark scheme ive done so far, ive tried to incorporate the others! please feel free to edit it! MOST OF THIS WAS SABA146 not me! but I like to feel I helped

whoops I thought I was editing...

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reply

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#949

(Original post by

1)t root2,

2)460 and current its greater that 0.26,

3)path of electron was A the arrow pointing upwards,

4)potential at mars was -13,

5)maximum value of tension was 24

6) K.E: P>Q, G.P.E: Q<P

7) capacitance graph question was D,

8) fe>fm>fs

9） ratio of y/d=1/3 – I got 2/3 :/

10) R earth/Rmoon=14 ----- >As I remember the question:

Mass of the earth is 81 x mass of the moon

Gravitational field strength on the earth = 9.8

Gravitational field strength on the moon = 1.8

g = GM/r^2.

9.8 = 81GM/re^2

1.8 = GM/rm^2

Re-arrange and you get re^2/rm^2 = ~14.88

11)which one is incorrect: when spring is compressed &suspended,it has minimum PE

12) which one is incorrect: change of momentum=zero

13)moving horizontally,Blv …

14)rotating coil was A q14 from http://papers.xtremepapers.com/AQA/P...W-QP-JAN03.pdf

15) Capacitance value of 0.02F for one question forgot which was, answer choice was B IIRC

16) units of impulse = kgms-1

17) momentum question when the 2 trolleys collided: 12000Ns

8 MORE MULTIPLE CHOICE QUESTIONS THEN DONE!

SECTION B IS COMPLETE

1a)define shm:

acceleration is proportinal to displacement, and acceleration acts toward equilibrium (2)

acceleration was 0.4

frequency of pendulum = 0.503 3s.f (3)

1500 revs per minute (2)

time for oscilations to be in phase again = 38 (3) -- if you think about it,

after 1 oscilation - difference on 0.1s

after 2 oscillations - difference of 0.2s....

after 19 oscillations difference of 1.9 seconds

so on the 19th osciation of the 1.9s pendulum, the 2s pendulum will arrive 1.9s after it, so on the 20th oscillation of the 1.9s pendulum they are in phase. again, on the 19th oscillation of the 2s pendulum they will be in phase.

19 x 2 = 38s

20 x 1.9 = 38s

TOTAL = 12

2) voltage = 30,000 (1)

b) (3) i think this was the capacity was increase from X to Y. find the energy stored? wasnt this the time taken for the spark to be produced?

yes, i think it was similar:

b) i think this was the capacity was increase from X to Y.time taken for the spark to be produced after the last discharge?

then Q=CV, then Q/Current = time was ~ 3.46s

you had to work out the charge stored and then use the current they gave you to find the time??

c) time taken for discharge will increase because time constant increases (2)

d) flash is brighter because more energy stored (2)

TOTAL = 7

3) 6 marker on fields

1. gravity always attractive

2. electric attractive/repulsive

3. both follow inverse square for Force

4. both follow inverse for potential

5. gravity uses mass

6. electric uses charge

7. only electric fields can be shielded

8. only electric fields depend on medium between charges

9. gradient of potential vs distance graph gives field strength

10. potential definition for both revolves around bringing a mass/charge from infinity to a certain point in a field and is zero at infinity

TOTAL = 6

4) 2 conditions when no force is exerted on the partcle (2)

field is parallel to velocity

particle is stationary

b) out of the plane of the paper

b) prove momentum is proportional to radius= mv^2/r = BQv , mv = BQr --> mv = kr

the speed of particle=8.7x107

c)time taken for partile to go through 1 dee = ~6.8x10^-8

d)show the time taken is independent of radius = 2pim/bq (3)

kinetic energy im MEV = 2.44 (3)

TOTAL = 15

5)

angle for max emf = 60 degrees -- this is at 90 degrees to the plane as emf = BANw sin(wt) therefore max emf is when sin(wt) =1, there for wt (which is the angle) = 90, 90-30 = 60 degrees

angle for max flux linkage = 5pi/6 = 2.62 radians -- this is at 0 degrees = 180 degrees, and N(PHI) = BAN cos(THETA), so max is when cos(THETA) = 1 so theta = 180, 180-39 = 150 degrees = 5pi/6

gradient of graph = emf (1)

drawing a graph (2) Positive Sine graph

peak voltage (3) I got 0.55 for peak to peak voltage then divided by 2 to get 27.5V but there is no set agreement on what the value is for this answer yet.. (MSI_10)

calculate flux density = 0.26 (2)( got 0.25 here

TOTAL= 10

Okay i'm going now... this is the best mark scheme ive done so far, ive tried to incorporate the others! please feel free to edit it!

**MisterE1**)1)t root2,

2)460 and current its greater that 0.26,

3)path of electron was A the arrow pointing upwards,

4)potential at mars was -13,

5)maximum value of tension was 24

6) K.E: P>Q, G.P.E: Q<P

7) capacitance graph question was D,

8) fe>fm>fs

9） ratio of y/d=1/3 – I got 2/3 :/

10) R earth/Rmoon=14 ----- >As I remember the question:

Mass of the earth is 81 x mass of the moon

Gravitational field strength on the earth = 9.8

Gravitational field strength on the moon = 1.8

g = GM/r^2.

9.8 = 81GM/re^2

1.8 = GM/rm^2

Re-arrange and you get re^2/rm^2 = ~14.88

11)which one is incorrect: when spring is compressed &suspended,it has minimum PE

12) which one is incorrect: change of momentum=zero

13)moving horizontally,Blv …

14)rotating coil was A q14 from http://papers.xtremepapers.com/AQA/P...W-QP-JAN03.pdf

15) Capacitance value of 0.02F for one question forgot which was, answer choice was B IIRC

16) units of impulse = kgms-1

17) momentum question when the 2 trolleys collided: 12000Ns

8 MORE MULTIPLE CHOICE QUESTIONS THEN DONE!

SECTION B IS COMPLETE

1a)define shm:

acceleration is proportinal to displacement, and acceleration acts toward equilibrium (2)

acceleration was 0.4

frequency of pendulum = 0.503 3s.f (3)

1500 revs per minute (2)

time for oscilations to be in phase again = 38 (3) -- if you think about it,

after 1 oscilation - difference on 0.1s

after 2 oscillations - difference of 0.2s....

after 19 oscillations difference of 1.9 seconds

so on the 19th osciation of the 1.9s pendulum, the 2s pendulum will arrive 1.9s after it, so on the 20th oscillation of the 1.9s pendulum they are in phase. again, on the 19th oscillation of the 2s pendulum they will be in phase.

19 x 2 = 38s

20 x 1.9 = 38s

TOTAL = 12

2) voltage = 30,000 (1)

b) (3) i think this was the capacity was increase from X to Y. find the energy stored? wasnt this the time taken for the spark to be produced?

yes, i think it was similar:

b) i think this was the capacity was increase from X to Y.time taken for the spark to be produced after the last discharge?

then Q=CV, then Q/Current = time was ~ 3.46s

you had to work out the charge stored and then use the current they gave you to find the time??

c) time taken for discharge will increase because time constant increases (2)

d) flash is brighter because more energy stored (2)

TOTAL = 7

3) 6 marker on fields

1. gravity always attractive

2. electric attractive/repulsive

3. both follow inverse square for Force

4. both follow inverse for potential

5. gravity uses mass

6. electric uses charge

7. only electric fields can be shielded

8. only electric fields depend on medium between charges

9. gradient of potential vs distance graph gives field strength

10. potential definition for both revolves around bringing a mass/charge from infinity to a certain point in a field and is zero at infinity

TOTAL = 6

4) 2 conditions when no force is exerted on the partcle (2)

field is parallel to velocity

particle is stationary

b) out of the plane of the paper

b) prove momentum is proportional to radius= mv^2/r = BQv , mv = BQr --> mv = kr

the speed of particle=8.7x107

c)time taken for partile to go through 1 dee = ~6.8x10^-8

d)show the time taken is independent of radius = 2pim/bq (3)

kinetic energy im MEV = 2.44 (3)

TOTAL = 15

5)

angle for max emf = 60 degrees -- this is at 90 degrees to the plane as emf = BANw sin(wt) therefore max emf is when sin(wt) =1, there for wt (which is the angle) = 90, 90-30 = 60 degrees

angle for max flux linkage = 5pi/6 = 2.62 radians -- this is at 0 degrees = 180 degrees, and N(PHI) = BAN cos(THETA), so max is when cos(THETA) = 1 so theta = 180, 180-39 = 150 degrees = 5pi/6

gradient of graph = emf (1)

drawing a graph (2) Positive Sine graph

peak voltage (3) I got 0.55 for peak to peak voltage then divided by 2 to get 27.5V but there is no set agreement on what the value is for this answer yet.. (MSI_10)

calculate flux density = 0.26 (2)( got 0.25 here

TOTAL= 10

Okay i'm going now... this is the best mark scheme ive done so far, ive tried to incorporate the others! please feel free to edit it!

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#951

Can anyone remind me of the multiple choice question with the answer as 't root2' ?? I have no memory of it! And thanks to those who put together the unofficial ms (:

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#952

1)t root2, <--- ZAMI it was something to do with the time period of a mass on two springs (if I remember right..)

2)460 and current its greater that 0.26,

3)path of electron was A the arrow pointing upwards,

4)potential at mars was -13,

5)maximum value of tension was 24

6) K.E: P>Q, G.P.E: Q<P

7) capacitance graph question was D,

8) fe>fm>fs

9） ratio of y/d=1/3 – I got 2/3 :/

10) R earth/Rmoon=14 ----- >As I remember the question:

Mass of the earth is 81 x mass of the moon

Gravitational field strength on the earth = 9.8

Gravitational field strength on the moon = 1.8

g = GM/r^2.

9.8 = 81GM/re^2

1.8 = GM/rm^2

Re-arrange and you get re^2/rm^2 = ~14.88

11)which one is incorrect: when spring is compressed &suspended,it has minimum PE

12) which one is incorrect: change of momentum=zero

13)moving horizontally,Blv …

14)rotating coil was A q14 from http://papers.xtremepapers.com/AQA/P...W-QP-JAN03.pdf

15) Capacitance value of 0.02F for one question forgot which was, answer choice was B IIRC

16) units of impulse = kgms-1

17) momentum question when the 2 trolleys collided: 12000Ns

18) negative ion moving through 2 plates, the lower earthed the upper at + 50V, the ion moved downwards towards the earthed plate (answer B)

SECTION B IS COMPLETE

1a)define shm:

acceleration is proportinal to displacement, and acceleration acts toward equilibrium (2)

acceleration was -0.4

frequency of pendulum = 0.503 3s.f (3)

1500 revs per minute (2)

time for oscilations to be in phase again = 38 (3) -- if you think about it,

after 1 oscilation - difference on 0.1s

after 2 oscillations - difference of 0.2s....

after 19 oscillations difference of 1.9 seconds

so on the 19th osciation of the 1.9s pendulum, the 2s pendulum will arrive 1.9s after it, so on the 20th oscillation of the 1.9s pendulum they are in phase. again, on the 19th oscillation of the 2s pendulum they will be in phase.

19 x 2 = 38s

20 x 1.9 = 38s

TOTAL = 12

2) voltage = 30,000 (1)

b) (3) i think this was the capacity was increase from X to Y. find the energy stored? wasnt this the time taken for the spark to be produced?

yes, i think it was similar:

b) i think this was the capacity was increase from X to Y.time taken for the spark to be produced after the last discharge?

then Q=CV, then Q/Current = time was ~ 3.46s

you had to work out the charge stored and then use the current they gave you to find the time??

c) time taken for discharge will increase because time constant increases (2)

d) flash is brighter because more energy stored (2)

TOTAL = 7

3) 6 marker on fields

1. gravity always attractive

2. electric attractive/repulsive

3. both follow inverse square for Force

4. both follow inverse for potential

5. gravity uses mass

6. electric uses charge

7. only electric fields can be shielded

8. only electric fields depend on medium between charges

9. gradient of potential vs distance graph gives field strength

10. potential definition for both revolves around bringing a mass/charge from infinity to a certain point in a field and is zero at infinity

TOTAL = 6

4) 2 conditions when no force is exerted on the partcle (2)

field is parallel to velocity

particle is stationary

b) out of the plane of the paper

b) prove momentum is proportional to radius= mv^2/r = BQv , mv = BQr --> mv = kr

the speed of particle=8.7x107

c)time taken for partile to go through 1 dee = ~6.8x10^-8

d)show the time taken is independent of radius = 2pim/bq (3)

kinetic energy im MEV = 2.44 (3)

TOTAL = 15

5)

angle for max emf = 60 degrees -- this is at 90 degrees to the plane as emf = BANw sin(wt) therefore max emf is when sin(wt) =1, there for wt (which is the angle) = 90, 90-30 = 60 degrees

angle for max flux linkage = 5pi/6 = 2.62 radians -- this is at 0 degrees = 180 degrees, and N(PHI) = BAN cos(THETA), so max is when cos(THETA) = 1 so theta = 180, 180-39 = 150 degrees = 5pi/6

gradient of graph = emf (1)

drawing a graph (2) Positive Sine graph

peak voltage (3) I got 0.55 for peak to peak voltage then divided by 2 to get 27.5V but there is no set agreement on what the value is for this answer yet.. (MSI_10)

calculate flux density = 0.26 (2)( got 0.25 here

TOTAL= 10

Okay i'm (MisterE1) going now... this is the best mark scheme ive done so far, ive tried to incorporate the others! please feel free to edit it! MOST OF THIS WAS SABA146 not me! but I like to feel I helped

2)460 and current its greater that 0.26,

3)path of electron was A the arrow pointing upwards,

4)potential at mars was -13,

5)maximum value of tension was 24

6) K.E: P>Q, G.P.E: Q<P

7) capacitance graph question was D,

8) fe>fm>fs

9） ratio of y/d=1/3 – I got 2/3 :/

10) R earth/Rmoon=14 ----- >As I remember the question:

Mass of the earth is 81 x mass of the moon

Gravitational field strength on the earth = 9.8

Gravitational field strength on the moon = 1.8

g = GM/r^2.

9.8 = 81GM/re^2

1.8 = GM/rm^2

Re-arrange and you get re^2/rm^2 = ~14.88

11)which one is incorrect: when spring is compressed &suspended,it has minimum PE

12) which one is incorrect: change of momentum=zero

13)moving horizontally,Blv …

14)rotating coil was A q14 from http://papers.xtremepapers.com/AQA/P...W-QP-JAN03.pdf

15) Capacitance value of 0.02F for one question forgot which was, answer choice was B IIRC

16) units of impulse = kgms-1

17) momentum question when the 2 trolleys collided: 12000Ns

18) negative ion moving through 2 plates, the lower earthed the upper at + 50V, the ion moved downwards towards the earthed plate (answer B)

**7 MORE MULTIPLE CHOICE QUESTIONS THEN DONE!**SECTION B IS COMPLETE

1a)define shm:

acceleration is proportinal to displacement, and acceleration acts toward equilibrium (2)

acceleration was -0.4

frequency of pendulum = 0.503 3s.f (3)

1500 revs per minute (2)

time for oscilations to be in phase again = 38 (3) -- if you think about it,

after 1 oscilation - difference on 0.1s

after 2 oscillations - difference of 0.2s....

after 19 oscillations difference of 1.9 seconds

so on the 19th osciation of the 1.9s pendulum, the 2s pendulum will arrive 1.9s after it, so on the 20th oscillation of the 1.9s pendulum they are in phase. again, on the 19th oscillation of the 2s pendulum they will be in phase.

19 x 2 = 38s

20 x 1.9 = 38s

TOTAL = 12

2) voltage = 30,000 (1)

b) (3) i think this was the capacity was increase from X to Y. find the energy stored? wasnt this the time taken for the spark to be produced?

yes, i think it was similar:

b) i think this was the capacity was increase from X to Y.time taken for the spark to be produced after the last discharge?

then Q=CV, then Q/Current = time was ~ 3.46s

you had to work out the charge stored and then use the current they gave you to find the time??

c) time taken for discharge will increase because time constant increases (2)

d) flash is brighter because more energy stored (2)

TOTAL = 7

3) 6 marker on fields

1. gravity always attractive

2. electric attractive/repulsive

3. both follow inverse square for Force

4. both follow inverse for potential

5. gravity uses mass

6. electric uses charge

7. only electric fields can be shielded

8. only electric fields depend on medium between charges

9. gradient of potential vs distance graph gives field strength

10. potential definition for both revolves around bringing a mass/charge from infinity to a certain point in a field and is zero at infinity

TOTAL = 6

4) 2 conditions when no force is exerted on the partcle (2)

field is parallel to velocity

particle is stationary

b) out of the plane of the paper

b) prove momentum is proportional to radius= mv^2/r = BQv , mv = BQr --> mv = kr

the speed of particle=8.7x107

c)time taken for partile to go through 1 dee = ~6.8x10^-8

d)show the time taken is independent of radius = 2pim/bq (3)

kinetic energy im MEV = 2.44 (3)

TOTAL = 15

5)

angle for max emf = 60 degrees -- this is at 90 degrees to the plane as emf = BANw sin(wt) therefore max emf is when sin(wt) =1, there for wt (which is the angle) = 90, 90-30 = 60 degrees

angle for max flux linkage = 5pi/6 = 2.62 radians -- this is at 0 degrees = 180 degrees, and N(PHI) = BAN cos(THETA), so max is when cos(THETA) = 1 so theta = 180, 180-39 = 150 degrees = 5pi/6

gradient of graph = emf (1)

drawing a graph (2) Positive Sine graph

peak voltage (3) I got 0.55 for peak to peak voltage then divided by 2 to get 27.5V but there is no set agreement on what the value is for this answer yet.. (MSI_10)

calculate flux density = 0.26 (2)( got 0.25 here

TOTAL= 10

Okay i'm (MisterE1) going now... this is the best mark scheme ive done so far, ive tried to incorporate the others! please feel free to edit it! MOST OF THIS WAS SABA146 not me! but I like to feel I helped

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#953

(Original post by

Can anyone remind me of the multiple choice question with the answer as 't root2' ?? I have no memory of it! And thanks to those who put together the unofficial ms (:

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**zmai**)Can anyone remind me of the multiple choice question with the answer as 't root2' ?? I have no memory of it! And thanks to those who put together the unofficial ms (:

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#954

**zmai**)

Can anyone remind me of the multiple choice question with the answer as 't root2' ?? I have no memory of it! And thanks to those who put together the unofficial ms (:

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#955

(Original post by

18) negative ion moving through 2 plates, the lower earthed the upper at + 50V, the ion moved downwards towards the earthed plate

**MisterE1**)18) negative ion moving through 2 plates, the lower earthed the upper at + 50V, the ion moved downwards towards the earthed plate

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#957

(Original post by

You wouldn't HAVE to find the gradient surely as you know Vmax is BANw, unless they explicitly said to that (I can't remember)

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**oli_G**)You wouldn't HAVE to find the gradient surely as you know Vmax is BANw, unless they explicitly said to that (I can't remember)

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#958

That was the worst exam i have ever done in my life!!!!!!!!!

The exam invigilator kept beeping behind me. I freaked out again as I always do in physics exams and stop thinking

The exam invigilator kept beeping behind me. I freaked out again as I always do in physics exams and stop thinking

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#959

(Original post by

The answer to this was B. The direction was downwards, and that eliminated A and C, and so left you with B and D. However, it was B because it was 25V and not 50V for the other column.

**Tullia**)The answer to this was B. The direction was downwards, and that eliminated A and C, and so left you with B and D. However, it was B because it was 25V and not 50V for the other column.

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