AQA PHYA4 ~ 13th June 2013 ~ A2 PhysicsWatch

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6 years ago
#941
Thought I'd done terribly on this but looking at the answers people have put, I might not have done as bad as I thought 0
6 years ago
#942
(Original post by cooldudeman)
Why does it say 14 on MS? I hope we are right. Damnnnn

Posted from TSR Mobile
It's an unofficial mark scheme, you can't always trust them
0
6 years ago
#943

it states:
Need a comparison? The average radius of the Earth is 6,371.0 km. In other words, the Earth is about 4 times larger than the Moon.

Does this mean the answer was 3.7!??! or did i misread the question lol
0
6 years ago
#944
(Original post by saba146)
17) momentum question when the 2 trolleys collided?anyone remeber the answer??
12000 Ns (it was 20000 before, and then 8000 afterwards).
0
6 years ago
#945
1)t root2,
2)460 and current its greater that 0.26,
3)path of electron was A the arrow pointing upwards,
4)potential at mars was -13,
5)maximum value of tension was 24
6) K.E: P>Q, G.P.E: Q<P
7) capacitance graph question was D,
8) fe>fm>fs
9） ratio of y/d=1/3 – I got 2/3 :/
10) R earth/Rmoon=14 ----- >As I remember the question:

Mass of the earth is 81 x mass of the moon
Gravitational field strength on the earth = 9.8
Gravitational field strength on the moon = 1.8

g = GM/r^2.

9.8 = 81GM/re^2

1.8 = GM/rm^2

Re-arrange and you get re^2/rm^2 = ~14.88
11)which one is incorrect: when spring is compressed &suspended,it has minimum PE
12) which one is incorrect: change of momentum=zero
13)moving horizontally,Blv …
14)rotating coil was A q14 from http://papers.xtremepapers.com/AQA/P...W-QP-JAN03.pdf
15) Capacitance value of 0.02F for one question forgot which was, answer choice was B IIRC
16) units of impulse = kgms-1
17) momentum question when the 2 trolleys collided: 12000Ns

8 MORE MULTIPLE CHOICE QUESTIONS THEN DONE!

SECTION B IS COMPLETE
1a)define shm:
acceleration is proportinal to displacement, and acceleration acts toward equilibrium (2)
acceleration was 0.4
frequency of pendulum = 0.503 3s.f (3)
1500 revs per minute (2)
time for oscilations to be in phase again = 38 (3) -- if you think about it,
after 1 oscilation - difference on 0.1s
after 2 oscillations - difference of 0.2s....
after 19 oscillations difference of 1.9 seconds
so on the 19th osciation of the 1.9s pendulum, the 2s pendulum will arrive 1.9s after it, so on the 20th oscillation of the 1.9s pendulum they are in phase. again, on the 19th oscillation of the 2s pendulum they will be in phase.
19 x 2 = 38s
20 x 1.9 = 38s
TOTAL = 12

2) voltage = 30,000 (1)
b) (3) i think this was the capacity was increase from X to Y. find the energy stored? wasnt this the time taken for the spark to be produced?
yes, i think it was similar:

b) i think this was the capacity was increase from X to Y.time taken for the spark to be produced after the last discharge?
then Q=CV, then Q/Current = time was ~ 3.46s

you had to work out the charge stored and then use the current they gave you to find the time??
c) time taken for discharge will increase because time constant increases (2)
d) flash is brighter because more energy stored (2)
TOTAL = 7

3) 6 marker on fields
1. gravity always attractive
2. electric attractive/repulsive
3. both follow inverse square for Force
4. both follow inverse for potential
5. gravity uses mass
6. electric uses charge
7. only electric fields can be shielded
8. only electric fields depend on medium between charges
9. gradient of potential vs distance graph gives field strength
10. potential definition for both revolves around bringing a mass/charge from infinity to a certain point in a field and is zero at infinity
TOTAL = 6

4) 2 conditions when no force is exerted on the partcle (2)
field is parallel to velocity
particle is stationary
b) out of the plane of the paper
b) prove momentum is proportional to radius= mv^2/r = BQv , mv = BQr --> mv = kr
the speed of particle=8.7x107
c)time taken for partile to go through 1 dee = ~6.8x10^-8
d)show the time taken is independent of radius = 2pim/bq (3)
kinetic energy im MEV = 2.44 (3)
TOTAL = 15

5)
angle for max emf = 60 degrees -- this is at 90 degrees to the plane as emf = BANw sin(wt) therefore max emf is when sin(wt) =1, there for wt (which is the angle) = 90, 90-30 = 60 degrees
angle for max flux linkage = 5pi/6 = 2.62 radians -- this is at 0 degrees = 180 degrees, and N(PHI) = BAN cos(THETA), so max is when cos(THETA) = 1 so theta = 180, 180-39 = 150 degrees = 5pi/6
gradient of graph = emf (1)

drawing a graph (2) Positive Sine graph
peak voltage (3) I got 0.55 for peak to peak voltage then divided by 2 to get 27.5V but there is no set agreement on what the value is for this answer yet.. (MSI_10)

calculate flux density = 0.26 (2)( got 0.25 here
TOTAL= 10

Okay i'm going now... this is the best mark scheme ive done so far, ive tried to incorporate the others! please feel free to edit it! 1
6 years ago
#946
(Original post by MisterE1)
that's 19 oscilations, if you think about it,
after 1 oscilation - difference on 0.1s
after 2 oscillations - difference of 0.2s....
after 19 oscillations difference of 1.9 seconds

so on the 19th osciation of the 1.9s pendulum, the 2s pendulum will arrive 1.9s after it, so on the 20th oscillation of the 1.9s pendulum they are in phase. again, on the 19th oscillation of the 2s pendulum they will be in phase.

19 x 2 = 38s
20 x 1.9 = 38s

hope I helped!
It's just the lowest common multiple really, I guess you could think of it like that.
0
6 years ago
#947
1)t root2,
2)460 and current its greater that 0.26,
3)path of electron was A the arrow pointing upwards,
4)potential at moon or something was -13,
5)maximum value of tension was 24
6) kinetic energy of p was greater than q but potential energy was less that q
7) capacitance graph question was D,
8) fe>fm>fs(i think that is Fe>Fs>Fm)
9） ratio of y/d=1/3
10) R earth/Rmoon=3.7
11)which one is incorrect: when spring is compressed &suspended,it has minimum PE
12) which one is incorrect: change of momentum=zero
13)moving horizontally,Blv …
14)rotating coil was A
15) Capacitance value of 0.02F for one question forgot which was, answer choice was B IIRC
16) units of impulse = kgms-1
momentum question when the 2 trolleys collided 12000
18)negative ion being moved in an electric field but cant remeber the answer

7 MORE MULTIPLE CHOICE QUESTIONS THEN DONE!

SECTION B IS COMPLETE
1a)define shm:
acceleration is proportinal to displacement, and acceleration acts toward equilibrium (2)
acceleration was 0.4
frequency of pendulum = 0.503 3s.f (3)
1500 revs per minute (2)
time for oscilations to be in phase again = 38 (3)
TOTAL = 12

2) voltage = 30,000 (1)
b) (3) i think this was the capacity was increase from X to Y. find the energy stored? wasnt this the time taken for the spark to be produced?
yes, i think it was similar:

b) i think this was the capacity was increase from X to Y.time taken for the spark to be produced after the last discharge?
then Q=CV, then Q/Current = time was ~ 3.46s

you had to work out the charge stored and then use the current they gave you to find the time??
c) time taken for discharge will increase because time constant increases (2)
d) flash is brighter because more energy stored (2)
TOTAL = 7

3) 6 marker on fields
1. gravity always attractive
2. electric attractive/repulsive
3. both follow inverse square for Force
4. both follow inverse for potential
5. gravity uses mass
6. electric uses charge
7. only electric fields can be shielded
8. only electric fields depend on medium between charges
9. gradient of potential vs distance graph gives field strength
10. potential definition for both revolves around bringing a mass/charge from infinity to a certain point in a field and is zero at infinity
TOTAL = 6

4) 2 conditions when no force is exerted on the partcle (2)
field is parallel to velocity
particle is stationary
b) out of the plane of the paper
b) prove momentum is proportional to radius= mv^2/r = BQv , mv = BQr --> mv = kr
the speed of particle=8.7x107
c)time taken for partile to go through 1 dee = ~6.8x10^-8
d)show the time taken is independent of radius = 2pim/bq (3)
kinetic energy im MEV = 2.44 (3)
TOTAL = 15

angle for max emf = 60 degrees -- this is at 90 degrees to the plane as emf = BANw sin(wt) therefore max emf is when sin(wt) =1, there for wt (which is the angle) = 90, 90-30 = 60 degreed
angle for max flux linkage = 5pi/6 = 2.62 radians -- this is at 0 degrees = 180 degrees, and N(PHI) = BAN cos(THETA), so max is when cos(THETA) = 1 so theta = 180, 180-39 = 150 degrees = 5pi/6
gradient of graph = emf (1)

drawing a graph (2) Positive Sine graph
peak voltage (3)
calculate flux density = 0.26 (2)( got 0.25 here
TOTAL= 10
0
6 years ago
#948
1)t root2,
2)460 and current its greater that 0.26,
3)path of electron was A the arrow pointing upwards,
4)potential at mars was -13,
5)maximum value of tension was 24
6) K.E: P>Q, G.P.E: Q<P
7) capacitance graph question was D,
8) fe>fm>fs
9） ratio of y/d=1/3 – I got 2/3 :/
10) R earth/Rmoon=14 ----- >As I remember the question:

Mass of the earth is 81 x mass of the moon
Gravitational field strength on the earth = 9.8
Gravitational field strength on the moon = 1.8

g = GM/r^2.

9.8 = 81GM/re^2

1.8 = GM/rm^2

Re-arrange and you get re^2/rm^2 = ~14.88
11)which one is incorrect: when spring is compressed &suspended,it has minimum PE
12) which one is incorrect: change of momentum=zero
13)moving horizontally,Blv …
14)rotating coil was A q14 from http://papers.xtremepapers.com/AQA/P...W-QP-JAN03.pdf
15) Capacitance value of 0.02F for one question forgot which was, answer choice was B IIRC
16) units of impulse = kgms-1
17) momentum question when the 2 trolleys collided: 12000Ns
18) negative ion moving through 2 plates, the lower earthed the upper at + 50V, the ion moved downwards towards the earthed plate

7 MORE MULTIPLE CHOICE QUESTIONS THEN DONE!
SECTION B IS COMPLETE
1a)define shm:
acceleration is proportinal to displacement, and acceleration acts toward equilibrium (2)
acceleration was 0.4
frequency of pendulum = 0.503 3s.f (3)
1500 revs per minute (2)
time for oscilations to be in phase again = 38 (3) -- if you think about it,
after 1 oscilation - difference on 0.1s
after 2 oscillations - difference of 0.2s....
after 19 oscillations difference of 1.9 seconds
so on the 19th osciation of the 1.9s pendulum, the 2s pendulum will arrive 1.9s after it, so on the 20th oscillation of the 1.9s pendulum they are in phase. again, on the 19th oscillation of the 2s pendulum they will be in phase.
19 x 2 = 38s
20 x 1.9 = 38s
TOTAL = 12

2) voltage = 30,000 (1)
b) (3) i think this was the capacity was increase from X to Y. find the energy stored? wasnt this the time taken for the spark to be produced?
yes, i think it was similar:

b) i think this was the capacity was increase from X to Y.time taken for the spark to be produced after the last discharge?
then Q=CV, then Q/Current = time was ~ 3.46s

you had to work out the charge stored and then use the current they gave you to find the time??
c) time taken for discharge will increase because time constant increases (2)
d) flash is brighter because more energy stored (2)
TOTAL = 7

3) 6 marker on fields
1. gravity always attractive
2. electric attractive/repulsive
3. both follow inverse square for Force
4. both follow inverse for potential
5. gravity uses mass
6. electric uses charge
7. only electric fields can be shielded
8. only electric fields depend on medium between charges
9. gradient of potential vs distance graph gives field strength
10. potential definition for both revolves around bringing a mass/charge from infinity to a certain point in a field and is zero at infinity
TOTAL = 6

4) 2 conditions when no force is exerted on the partcle (2)
field is parallel to velocity
particle is stationary
b) out of the plane of the paper
b) prove momentum is proportional to radius= mv^2/r = BQv , mv = BQr --> mv = kr
the speed of particle=8.7x107
c)time taken for partile to go through 1 dee = ~6.8x10^-8
d)show the time taken is independent of radius = 2pim/bq (3)
kinetic energy im MEV = 2.44 (3)
TOTAL = 15

5)
angle for max emf = 60 degrees -- this is at 90 degrees to the plane as emf = BANw sin(wt) therefore max emf is when sin(wt) =1, there for wt (which is the angle) = 90, 90-30 = 60 degrees
angle for max flux linkage = 5pi/6 = 2.62 radians -- this is at 0 degrees = 180 degrees, and N(PHI) = BAN cos(THETA), so max is when cos(THETA) = 1 so theta = 180, 180-39 = 150 degrees = 5pi/6
gradient of graph = emf (1)

drawing a graph (2) Positive Sine graph
peak voltage (3) I got 0.55 for peak to peak voltage then divided by 2 to get 27.5V but there is no set agreement on what the value is for this answer yet.. (MSI_10)

calculate flux density = 0.26 (2)( got 0.25 here
TOTAL= 10

Okay i'm going now... this is the best mark scheme ive done so far, ive tried to incorporate the others! please feel free to edit it! MOST OF THIS WAS SABA146 not me! but I like to feel I helped whoops I thought I was editing...
0
6 years ago
#949
(Original post by MisterE1)
1)t root2,
2)460 and current its greater that 0.26,
3)path of electron was A the arrow pointing upwards,
4)potential at mars was -13,
5)maximum value of tension was 24
6) K.E: P>Q, G.P.E: Q<P
7) capacitance graph question was D,
8) fe>fm>fs
9） ratio of y/d=1/3 – I got 2/3 :/
10) R earth/Rmoon=14 ----- >As I remember the question:

Mass of the earth is 81 x mass of the moon
Gravitational field strength on the earth = 9.8
Gravitational field strength on the moon = 1.8

g = GM/r^2.

9.8 = 81GM/re^2

1.8 = GM/rm^2

Re-arrange and you get re^2/rm^2 = ~14.88
11)which one is incorrect: when spring is compressed &suspended,it has minimum PE
12) which one is incorrect: change of momentum=zero
13)moving horizontally,Blv …
14)rotating coil was A q14 from http://papers.xtremepapers.com/AQA/P...W-QP-JAN03.pdf
15) Capacitance value of 0.02F for one question forgot which was, answer choice was B IIRC
16) units of impulse = kgms-1
17) momentum question when the 2 trolleys collided: 12000Ns

8 MORE MULTIPLE CHOICE QUESTIONS THEN DONE!

SECTION B IS COMPLETE
1a)define shm:
acceleration is proportinal to displacement, and acceleration acts toward equilibrium (2)
acceleration was 0.4
frequency of pendulum = 0.503 3s.f (3)
1500 revs per minute (2)
time for oscilations to be in phase again = 38 (3) -- if you think about it,
after 1 oscilation - difference on 0.1s
after 2 oscillations - difference of 0.2s....
after 19 oscillations difference of 1.9 seconds
so on the 19th osciation of the 1.9s pendulum, the 2s pendulum will arrive 1.9s after it, so on the 20th oscillation of the 1.9s pendulum they are in phase. again, on the 19th oscillation of the 2s pendulum they will be in phase.
19 x 2 = 38s
20 x 1.9 = 38s
TOTAL = 12

2) voltage = 30,000 (1)
b) (3) i think this was the capacity was increase from X to Y. find the energy stored? wasnt this the time taken for the spark to be produced?
yes, i think it was similar:

b) i think this was the capacity was increase from X to Y.time taken for the spark to be produced after the last discharge?
then Q=CV, then Q/Current = time was ~ 3.46s

you had to work out the charge stored and then use the current they gave you to find the time??
c) time taken for discharge will increase because time constant increases (2)
d) flash is brighter because more energy stored (2)
TOTAL = 7

3) 6 marker on fields
1. gravity always attractive
2. electric attractive/repulsive
3. both follow inverse square for Force
4. both follow inverse for potential
5. gravity uses mass
6. electric uses charge
7. only electric fields can be shielded
8. only electric fields depend on medium between charges
9. gradient of potential vs distance graph gives field strength
10. potential definition for both revolves around bringing a mass/charge from infinity to a certain point in a field and is zero at infinity
TOTAL = 6

4) 2 conditions when no force is exerted on the partcle (2)
field is parallel to velocity
particle is stationary
b) out of the plane of the paper
b) prove momentum is proportional to radius= mv^2/r = BQv , mv = BQr --> mv = kr
the speed of particle=8.7x107
c)time taken for partile to go through 1 dee = ~6.8x10^-8
d)show the time taken is independent of radius = 2pim/bq (3)
kinetic energy im MEV = 2.44 (3)
TOTAL = 15

5)
angle for max emf = 60 degrees -- this is at 90 degrees to the plane as emf = BANw sin(wt) therefore max emf is when sin(wt) =1, there for wt (which is the angle) = 90, 90-30 = 60 degrees
angle for max flux linkage = 5pi/6 = 2.62 radians -- this is at 0 degrees = 180 degrees, and N(PHI) = BAN cos(THETA), so max is when cos(THETA) = 1 so theta = 180, 180-39 = 150 degrees = 5pi/6
gradient of graph = emf (1)

drawing a graph (2) Positive Sine graph
peak voltage (3) I got 0.55 for peak to peak voltage then divided by 2 to get 27.5V but there is no set agreement on what the value is for this answer yet.. (MSI_10)

calculate flux density = 0.26 (2)( got 0.25 here
TOTAL= 10

Okay i'm going now... this is the best mark scheme ive done so far, ive tried to incorporate the others! please feel free to edit it! For q17 on section a I think 3 of the options was 8000,12000 and 20000, I'm pretty sure I went with 20000 not 100% sure though.
0
6 years ago
#950
Damn I never put negative sign for the acceleration in q1. Sooo stupid

Posted from TSR Mobile
0
6 years ago
#951
Can anyone remind me of the multiple choice question with the answer as 't root2' ?? I have no memory of it! And thanks to those who put together the unofficial ms (:

Posted from TSR Mobile
0
6 years ago
#952
1)t root2, <--- ZAMI it was something to do with the time period of a mass on two springs (if I remember right..)
2)460 and current its greater that 0.26,
3)path of electron was A the arrow pointing upwards,
4)potential at mars was -13,
5)maximum value of tension was 24
6) K.E: P>Q, G.P.E: Q<P
7) capacitance graph question was D,
8) fe>fm>fs
9） ratio of y/d=1/3 – I got 2/3 :/
10) R earth/Rmoon=14 ----- >As I remember the question:

Mass of the earth is 81 x mass of the moon
Gravitational field strength on the earth = 9.8
Gravitational field strength on the moon = 1.8

g = GM/r^2.

9.8 = 81GM/re^2

1.8 = GM/rm^2

Re-arrange and you get re^2/rm^2 = ~14.88
11)which one is incorrect: when spring is compressed &suspended,it has minimum PE
12) which one is incorrect: change of momentum=zero
13)moving horizontally,Blv …
14)rotating coil was A q14 from http://papers.xtremepapers.com/AQA/P...W-QP-JAN03.pdf
15) Capacitance value of 0.02F for one question forgot which was, answer choice was B IIRC
16) units of impulse = kgms-1
17) momentum question when the 2 trolleys collided: 12000Ns
18) negative ion moving through 2 plates, the lower earthed the upper at + 50V, the ion moved downwards towards the earthed plate (answer B)

7 MORE MULTIPLE CHOICE QUESTIONS THEN DONE!
SECTION B IS COMPLETE
1a)define shm:
acceleration is proportinal to displacement, and acceleration acts toward equilibrium (2)
acceleration was -0.4
frequency of pendulum = 0.503 3s.f (3)
1500 revs per minute (2)
time for oscilations to be in phase again = 38 (3) -- if you think about it,
after 1 oscilation - difference on 0.1s
after 2 oscillations - difference of 0.2s....
after 19 oscillations difference of 1.9 seconds
so on the 19th osciation of the 1.9s pendulum, the 2s pendulum will arrive 1.9s after it, so on the 20th oscillation of the 1.9s pendulum they are in phase. again, on the 19th oscillation of the 2s pendulum they will be in phase.
19 x 2 = 38s
20 x 1.9 = 38s
TOTAL = 12

2) voltage = 30,000 (1)
b) (3) i think this was the capacity was increase from X to Y. find the energy stored? wasnt this the time taken for the spark to be produced?
yes, i think it was similar:

b) i think this was the capacity was increase from X to Y.time taken for the spark to be produced after the last discharge?
then Q=CV, then Q/Current = time was ~ 3.46s

you had to work out the charge stored and then use the current they gave you to find the time??
c) time taken for discharge will increase because time constant increases (2)
d) flash is brighter because more energy stored (2)
TOTAL = 7

3) 6 marker on fields
1. gravity always attractive
2. electric attractive/repulsive
3. both follow inverse square for Force
4. both follow inverse for potential
5. gravity uses mass
6. electric uses charge
7. only electric fields can be shielded
8. only electric fields depend on medium between charges
9. gradient of potential vs distance graph gives field strength
10. potential definition for both revolves around bringing a mass/charge from infinity to a certain point in a field and is zero at infinity
TOTAL = 6

4) 2 conditions when no force is exerted on the partcle (2)
field is parallel to velocity
particle is stationary
b) out of the plane of the paper
b) prove momentum is proportional to radius= mv^2/r = BQv , mv = BQr --> mv = kr
the speed of particle=8.7x107
c)time taken for partile to go through 1 dee = ~6.8x10^-8
d)show the time taken is independent of radius = 2pim/bq (3)
kinetic energy im MEV = 2.44 (3)
TOTAL = 15

5)
angle for max emf = 60 degrees -- this is at 90 degrees to the plane as emf = BANw sin(wt) therefore max emf is when sin(wt) =1, there for wt (which is the angle) = 90, 90-30 = 60 degrees
angle for max flux linkage = 5pi/6 = 2.62 radians -- this is at 0 degrees = 180 degrees, and N(PHI) = BAN cos(THETA), so max is when cos(THETA) = 1 so theta = 180, 180-39 = 150 degrees = 5pi/6
gradient of graph = emf (1)

drawing a graph (2) Positive Sine graph
peak voltage (3) I got 0.55 for peak to peak voltage then divided by 2 to get 27.5V but there is no set agreement on what the value is for this answer yet.. (MSI_10)

calculate flux density = 0.26 (2)( got 0.25 here
TOTAL= 10

Okay i'm (MisterE1) going now... this is the best mark scheme ive done so far, ive tried to incorporate the others! please feel free to edit it! MOST OF THIS WAS SABA146 not me! but I like to feel I helped 0
6 years ago
#953
(Original post by zmai)
Can anyone remind me of the multiple choice question with the answer as 't root2' ?? I have no memory of it! And thanks to those who put together the unofficial ms (:

Posted from TSR Mobile
I think it was the time period of 2 springs in series
0
6 years ago
#954
(Original post by zmai)
Can anyone remind me of the multiple choice question with the answer as 't root2' ?? I have no memory of it! And thanks to those who put together the unofficial ms (:

Posted from TSR Mobile
it wasa mass on a spring, one was just a single spring and other was 2 strings joined together in series we had to find the time period
0
6 years ago
#955
(Original post by MisterE1)
18) negative ion moving through 2 plates, the lower earthed the upper at + 50V, the ion moved downwards towards the earthed plate
The answer to this was B. The direction was downwards, and that eliminated A and C, and so left you with B and D. However, it was B because it was 25V and not 50V for the other column.
0
6 years ago
#956
Thankyou!

Posted from TSR Mobile
0
6 years ago
#957
(Original post by oli_G)
You wouldn't HAVE to find the gradient surely as you know Vmax is BANw, unless they explicitly said to that (I can't remember)

Posted from TSR Mobile
Don't think they did just thought that's must be how they wanted you to do it as I must have missed some information for that part!
0
6 years ago
#958
That was the worst exam i have ever done in my life!!!!!!!!!

The exam invigilator kept beeping behind me. I freaked out again as I always do in physics exams and stop thinking 0
6 years ago
#959
(Original post by Tullia)
The answer to this was B. The direction was downwards, and that eliminated A and C, and so left you with B and D. However, it was B because it was 25V and not 50V for the other column.
Agreed

Posted from TSR Mobile
0
6 years ago
#960
Ty, I've added it in, I'll be back in the morning, night all!
0
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