Turn on thread page Beta
    Offline

    1
    ReputationRep:
    (Original post by jlroper5)
    The 3 steps for making the chlorobenzylamine thingy?
    What it 1) Nitrobenzene using H2SO4 and HNO3
    2) chloronitrobenzene using Cl2 and ALCL3
    3) Reducing the N03 to NH2 using Sn and conc HCL???

    Anyone else get this?
    Yeah I did your 2) first then nitrated it, same reagents though.
    Offline

    0
    ReputationRep:
    (Original post by 079)
    arrow in last part? :confused:
    From O- part of compound to H+
    (There's mixed opinions about this last arrow haha)
    Offline

    16
    ReputationRep:
    (Original post by rogersnm)
    I did the reverse, but I haven't got a clue which is right. I would've thought that having the extra NH2 there would take an additional proton therefore requiring a lower pH for the zwitterion to form.
    Basically a zwitterion is neutral.

    So you want the R group to not have a charge.

    Therefore you need NH2 in the high PH conditions as it you had NH2 in low pH it would accept another proton making it charged.
    Offline

    1
    ReputationRep:
    (Original post by gibb)
    I didnt calculate the empirical formula for the last question, I just multiplied the mass of 144 by the percentage of the element.

    Do you think this will lose me marks?
    If you put the correct structure down then no, they didn't explicity ask for the molecular formula.
    Offline

    0
    ReputationRep:
    (Original post by lukas1051)
    I had it substituted on all 4 available spots on benzene, but I don't think there's a definite answer, I guess they just want you do get that it substituted onto the benzene ring, whether you had 1, 2, 3, or 4 probably doesn't matter.
    Okay thanks
    Offline

    16
    ReputationRep:
    (Original post by Zoe_mj)
    Im pretty sure it was 5, its why I looked for an extra reason to get a mark...
    haha, oh well I trust you over me lol. I tend not to read the question fully

    Hopefully boundaries will be similar to last years so 54/60 will be full UMS.
    Offline

    0
    ReputationRep:
    (Original post by shooby_doo)
    What would losing 15 marks get me
    Probly 1 mark off an A going by the old grade boundaries
    Offline

    1
    ReputationRep:
    (Original post by fudgesundae)
    Basically a zwitterion is neutral.

    So you want the R group to not have a charge.

    Therefore you need NH2 in the high PH conditions as it you had NH2 in low pH it would accept another proton making it charged.
    Sounds good... there goes another couple of marks
    Offline

    9
    ReputationRep:
    (Original post by jlroper5)
    The 3 steps for making the chlorobenzylamine thingy?
    What it 1) Nitrobenzene using H2SO4 and HNO3
    2) chloronitrobenzene using Cl2 and ALCL3
    3) Reducing the N03 to NH2 using Sn and conc HCL???

    Anyone else get this?
    I put all of that.
    Offline

    16
    ReputationRep:
    (Original post by rogersnm)
    Sounds good... there goes another couple of marks
    I wasn't sure myself (I put NH2 as pH 10), but I checked Lysine (it has an NH2 in its R group) and its isoelectric point is pH 10. But literally no in my school except me got this.
    Offline

    10
    ReputationRep:
    Decent paper - expecting slightly lower than usual grade boundaries. Lost 1 mark on the first question and 2 marks on the synthesis question. How did everyone else find it?

    Ester was (CH3)3CCH2COOCH2CH3
    Offline

    0
    ReputationRep:
    (Original post by jlroper5)
    The 3 steps for making the chlorobenzylamine thingy?
    What it 1) Nitrobenzene using H2SO4 and HNO3
    2) chloronitrobenzene using Cl2 and ALCL3
    3) Reducing the N03 to NH2 using Sn and conc HCL???

    Anyone else get this?
    i did 3 before 2 i think
    Offline

    0
    ReputationRep:
    (Original post by fudgesundae)
    haha, oh well I trust you over me lol. I tend not to read the question fully

    Hopefully boundaries will be similar to last years so 54/60 will be full UMS.
    I mean Im going off memory as well, so could be wrong
    Offline

    0
    ReputationRep:
    why would we need to prove it was carbonyl? The guy said it was either aldeyde or ketone.
    Offline

    2
    ReputationRep:
    I think boundaries will be lower the amino acid stuff and polymerization questions were quite challenging
    Offline

    1
    ReputationRep:
    Arrgghh you can't reduce a carboxylic acid people!!!!! It's even in the book! THERE WAS AN ERROR IN THR EXAM!!! Arghhhhhhh
    Offline

    0
    ReputationRep:
    For the 3 step reactions, did it matter whether you put the chlorine or amine group on first? :s
    Offline

    9
    ReputationRep:
    (Original post by lukas1051)
    I had it substituted on all 4 available spots on benzene, but I don't think there's a definite answer, I guess they just want you do get that it substituted onto the benzene ring, whether you had 1, 2, 3, or 4 probably doesn't matter.
    Uh... yes it does matter? That's the point of phenol and the alternating delta negative and delta positive carbons. It only reacts on the delta positive carbons which are at 2,4 and 6.

    Carbon 4 was already reacted so you had to draw Bromine on carbon 2 and 6.
    Offline

    16
    ReputationRep:
    (Original post by jlroper5)
    The 3 steps for making the chlorobenzylamine thingy?
    What it 1) Nitrobenzene using H2SO4 and HNO3
    2) chloronitrobenzene using Cl2 and ALCL3
    3) Reducing the N03 to NH2 using Sn and conc HCL???

    Anyone else get this?
    I got that (except I did step 2 and step 1 the other way round which I'm sure won't matter). However I said the halogen carrier was FeCl3, instead of AlCl3, think that will be acceptable?
    Offline

    10
    ReputationRep:
    (Original post by Confused94)
    For the 3 step reactions, did it matter whether you put the chlorine or amine group on first? :s
    Doesn't matter
 
 
 

University open days

  • Heriot-Watt University
    School of Textiles and Design Undergraduate
    Fri, 16 Nov '18
  • University of Roehampton
    All departments Undergraduate
    Sat, 17 Nov '18
  • Edge Hill University
    Faculty of Health and Social Care Undergraduate
    Sat, 17 Nov '18
Poll
Have you ever experienced bullying?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.