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Will the real TeeEm please stand up! watch

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    (Original post by SCAR H)
    TeeEm what Q were you referring to i think i complicated it? A or B
    I was thinking of b

    why does it matter now?
    in 18 days you will get your results!
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    (Original post by TeeEm)
    I was thinking of b

    why does it matter now?
    in 18 days you will get your results!
    I know i respect you (obviously) but i just want to know why i wouldn't get the M1. Your replied was a little vague. Could you expand
    Your work on your website is really helpful
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    (Original post by SCAR H)
    I know i respect you (obviously) but i just want to know why i wouldn't get the M1. Your replied was a little vague. Could you expand
    Your work on your website is really helpful
    this is open to interpretation
    a marker has some flexibility.

    I could not possibly give any marks for something which is conceptually wrong, even if the correct solution is followed. (luckily I do not mark)

    You might get 1 mark.
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    18 days to A level results

    Question for Sunday 26/07/15
    AS Level Maths Upwards


    and for those who want that little bit extra,
    Further Maths level Upwards required
    Attached Images
  1. File Type: pdf Q27, Sunday 26-07-15, solution.pdf (189.0 KB, 73 views)
  2. File Type: pdf Q27, Sunday 26-07-15, EXTRA, solution.pdf (71.8 KB, 53 views)
  3. File Type: pdf Q27, Sunday 26-07-15.pdf (16.4 KB, 77 views)
  4. File Type: pdf Q27, Sunday 26-07-15, EXTRA.pdf (11.2 KB, 68 views)
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    The normal one was interesting! I got a third for my solution is that anywhere near
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    (Original post by Joshthemathmo)
    The normal one was interesting! I got a third for my solution is that anywhere near
    the answer is indeed 1/3
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    (Original post by TeeEm)
    18 days to A level results

    Question for Sunday 26/07/15
    AS Level Maths Upwards


    and for those who want that little bit extra,
    Further Maths level Upwards required
    Just a minor typo in the extra, the sign in front of the π^8 should be a minus
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    (Original post by Gome44)
    Just a minor typo in the extra, the sign in front of the π^8 should be a minus
    thank you I will correct it.

    I am uploading new questions and solutions early tonight
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    17 days to A level results

    Question for Monday 27/07/15
    AS Level Maths Upwards


    and for those who want that little bit extra,
    Further Maths level Upwards required
    Attached Images
  5. File Type: pdf Q28, Monday 27-07-15, solution.pdf (89.8 KB, 53 views)
  6. File Type: pdf Q28, Monday 27-07-15, EXTRA, solution.pdf (78.8 KB, 61 views)
  7. File Type: pdf Q28, Monday 27-07-15.pdf (16.3 KB, 83 views)
  8. File Type: pdf Q28, Monday 27-07-15, EXTRA.pdf (14.9 KB, 68 views)
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    16 days to A level results

    Question for Tuesday 28/07/15
    AS Level Maths Upwards


    and for those who want that little bit extra,
    A level Maths Upwards required
    Attached Images
  9. File Type: pdf Q29,Tuesday 28-07-15.pdf (11.0 KB, 66 views)
  10. File Type: pdf Q29,Tuesday 28-07-15, EXTRA.pdf (13.0 KB, 59 views)
  11. File Type: pdf Q29,Tuesday 28-07-15, solution.pdf (159.1 KB, 37 views)
  12. File Type: pdf Q29,Tuesday 28-07-15, EXTRA, solution.pdf (57.5 KB, 37 views)
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    (Original post by TeeEm)
    16 days to A level results

    Question for Tuesday 28/07/15
    AS Level Maths Upwards


    and for those who want that little bit extra,
    A level Maths Upwards required
    The second one is very very nice if you have to do what i think you have to.
    Spoiler:
    Show

    Does it involve modulus integral....?
    Like where it is below and above etc



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    (Original post by physicsmaths)
    The second one is very very nice if you have to do what i think you have to.
    Spoiler:
    Show

    Does it involve modulus integral....?
    Like where it is below and above etc



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    solutions tomorrow...
    today's problems are both easier than the usual questions

    back to series and products soon
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    (Original post by TeeEm)
    solutions tomorrow...
    today's problems are both easier than the usual questions

    back to series and products soon
    Yh they look easy.


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    (Original post by TeeEm)
    16 days to A level results

    Question for Tuesday 28/07/15
    AS Level Maths Upwards


    and for those who want that little bit extra,
    A level Maths Upwards required
    Note square root of x^2 is mod x. I think you did x.
    Ive done it a few times and i think your answer is wrong. Here is the solution. Name:  ImageUploadedByStudent Room1438060282.737025.jpg
Views: 69
Size:  111.5 KB

    Edit: just checked wolfram and gives me my answer aswell.
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    (Original post by TeeEm)
    solutions tomorrow...
    today's problems are both easier than the usual questions

    back to series and products soon
    What do you reckon?


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    (Original post by physicsmaths)
    What do you reckon?


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    sorry one of my classic typos?...
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    (Original post by TeeEm)
    sorry one of my classic typos...
    It should read pi+4
    I doubt that is right aswell.


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    (Original post by physicsmaths)
    I doubt that is right aswell.


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    I am not in my office at the moment

    why don,t you wait until tonight?
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    (Original post by TeeEm)
    I am not in my office at the moment

    why don,t you wait until tonight?
    Sure No problem.
    Name:  ImageUploadedByStudent Room1438083317.481544.jpg
Views: 48
Size:  79.5 KB
    Wolfram gives me the number of 1.81 or whatever which is equivalent to my answer in my solution above.
    Would be nice if someone could check my answer to be sure its right.


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    \int_0^\pi \sqrt{1-4\sin \frac{x}{2} + 4 \sin^2 \frac{x}{2}} \,dx = \int_0^\pi \sqrt{(1-2\sin \frac{x}{2})^2}\,dx = \int_0^\pi | 1 - 2 \sin \frac{x}{2}| \,dx

    1 - 2 sin (x/2) = 0 when x = pi/3, and is decreasing function (in range 0 < x/2 < pi/2) so > 0 for x < pi/3 and < 0 for x > pi/3.

    So integral becomes

    \int_0^{\pi/3} 1 - 2 \sin \frac{x}{2}\,dx + \int_{\pi/3}^\pi 2 \sin \frac{x}{2} - 1\, dx

     =[x + 4 \cos \frac{x}{2}]_0^{\pi/3} - [4 \cos \frac{x}{2} - x]_{\pi/3}^\pi

     = \frac{\pi}{3} - \frac{2\pi}{3} + 8 \cos \frac{\pi}{6} - 4 = 4 \sqrt{3} - 4 - \frac{\pi}{3}
 
 
 
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