Hey there! Sign in to join this conversationNew here? Join for free
    Offline

    0
    ReputationRep:
    will we get penalised if we dont give answers to a certain no. of significant figures?
    Offline

    14
    ReputationRep:
    Hmm, I found the June '02 paper, but the edexcel website says that the mathematics thing was introduced in 2004... does this mean these '02 papers are legacy and I should stay clear of them?
    Offline

    0
    ReputationRep:
    (Original post by Arsey)
    I haven't taught it for 6/7 years or so. I am thinking of giving myself an A2 FM group next year as I am getting rusty.

    If your M1 knowledge is sound, M2 really isn't that much more difficult.

    On the CoM questions, check carefully it isn't a shape made from rods rather than a solid. Also practise the toppling/hanging parts, they always seem to cause the most problems (is toppling on M2?)
    Toppling is still in M2 - but it is lightly covered.
    There's a Solomon paper with a toppling question - that's the nearest I've seen
    Offline

    14
    ReputationRep:
    According to the spec we need to be able to do centres of mass questions where the lamina may be free to rotate about a horizontal axis.... any past paper questions or help with this?
    • Offline

      2
      (Original post by AndersonsBentFoot)
      will we get penalised if we dont give answers to a certain no. of significant figures?
      never go beyond 3sf if the answer involves g
      Offline

      2
      ReputationRep:
      omg jan 04 7 d !!

      can someone explain this to me

      how are they taking moments like this??

      isn't it force x perpendicular distance, argh

      is there an easier method

      centre of mass question btw
      Attached Images
    • File Type: pdfM2 2004-01.pdf (151.7 KB, 191 views)
    • File Type: pdfM2 2004-01 MS.pdf (95.0 KB, 387 views)
      Offline

      0
      ReputationRep:
      They have taken moments about O and it is force x perpendicular distance.

      The weight of the lamina (10mg) acts at point G (centre of mass) which is at a distance 2.25a from AD. As O is at a distance 2.5a from AD, the perpendicular distance is a/4

      So 10mg(a/4) = P(2a)
      (force P acts horizontally, in line with CD, so the perpendicular distance is 2a)

      therefore P= 10mga/8a
      = 5/4(mg) as required

      as for an easier way, drawing new diagrams helps, and read the questions for which direction the force acts etc. GL everyone for tomorrow!
      Offline

      1
      ReputationRep:
      Good Luck Everyone!!!! Only 3 and a half hours left!!!!
      Offline

      0
      ReputationRep:
      are there anybody doimg M2 today?
      Offline

      0
      ReputationRep:
      (Original post by 6761)
      are there anybody doimg M2 today?
      Done and dusted!
      Offline

      0
      ReputationRep:
      Are there anybody have the mark scheme for this paper?
      Offline

      0
      ReputationRep:
      (Original post by Ajka)
      ...
      I would delete your post, your not supposed to discuss the exam till 12pm.
      Offline

      0
      ReputationRep:
      People no discussion before 12 am.
      Offline

      0
      ReputationRep:
      Good luck on the result - and remember, no discussion for a while (message at the top of the thread...)
      Offline

      0
      ReputationRep:
      when can we discuss?
      Offline

      0
      ReputationRep:
      (Original post by 6761)
      when can we discuss?
      According to this, you have to wait until "12:00 AM - Midnight (GMT)" for a morning exam.
      Offline

      0
      ReputationRep:
      Does anyone have the solutions?
      Offline

      2
      ReputationRep:
      Okay here are my answers to M2, I'm not entirely sure on these answers so don't take my word for it.

      1. a) v = 12
      b) a = 4/45 = 0.0889

      2. a) 29 J

      3. a) t^4 - 6t^2 + 8
      b)1/5 t^5 - 2t3 + 8t
      c) t = 2, t = 1.41 = root 2

      4 a) couldn't do it
      b) 10.24

      5 a) 11, 11
      b) 24

      Not sure about question 6, could someone confirm if this is right?
      6 a) .. prove
      b) 2.03
      c) v = 3i + (5-9.8)t
      d) 0.204
      e) 3root2

      7. mew = 0.514

      8 a) prove m = 4
      b) v = 2/9 therefore moving towards the wall.
      Offline

      0
      ReputationRep:
      OK here's from what I can remember:

      Centre of mass Q : 12.3 and 12.9 and the angle was 28
      Last Q: the velocity you got was 2/9 which was in the positive direction and hence it hit the wall again.
      For the vlocity question where the particle was 10 m above the cliff I was 2.03s and 0.2 seconds for the time Q's and got 3root2 as the value of v (Obviously wrote that as decimals which was 4. something)
      For the other projectile Q I got t as root4 and root2 (Again wrote these as decimal)
      For the Q where the box was dragged from A to B I remember putting down 8400 or something like that and the speed as 10 ms-1 (Rounded to 2 sf) when it passed b.
      I think I got the KE energy one wrong though as I got 3 J but I worked out KE lost which you weren't meant to :facepalm:
      For the moments one and the lowest value of u I got 0.51.
      Offline

      0
      ReputationRep:
      (Original post by Arsey)
      never go beyond 3sf if the answer involves g
      Arsey to the rescue with the solutions?
     
     
     
  1. See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  2. Poll
    Did TEF Bronze Award affect your UCAS choices?
  3. See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  4. The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.