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# C1 January 10th 2011 Exam (Edexcel) Watch

1. Good luck to those sitting the exam tomorrow.
2. Specimen Paper and Mark Scheme for anyone who wants to do some last minute revision:

(Mark Scheme's at the end of the document)
3. Hoping to get an A. I've done so much revision I had to catch up from last year aswell as I barely knew anything at the end of GCSE's. But each past paper I do the results one time will be 74/75 and next time will only be 60. I randomly make silly mistakes like 2 x 4 = 6 or something which can sometimes ruin a 6 mark question.
4. yeah im hoping for an A as well, i have one more question.

f(x) = x^3 - 3x +2

for this, i have the show f(x) = (x-1)^2(x+2)

how exactly would i show this??

thanks
5. (Original post by James A)
yeah im hoping for an A as well, i have one more question.

f(x) = x^3 - 3x +2

for this, i have the show f(x) = (x-1)^2(x+2)

how exactly would i show this??

thanks
f(1) = 1 - 3 + 2 = 0 therefore (x-1) is a factor
f(x) = (x-1)(x^2 + kx - 2)
-k - 2 = -3 -> k = 1
f(x) = (x-1)(x^2 + x - 2)
f(x) = (x-1)(x+2)(x-1)
therefore f(x) = (x-1)^2(x+2)
... or equivalent working i.e. using the factor theorem to prove that any of the given factors are correct and working on that basis to show that the final factorisation is correct. Not too sure if there is another way to do it using only C1 knowledge..
6. (Original post by Darthdevidem)
Anyone have a list of formulae we need to learn for this paper and the C2?
This should remind you both of those you have to learn and those you have to be able to use:
Edexcel_C1andC2_Revision_sheet.pdf
7. does any one have a copy of last years Core 1 exam?
8. (Original post by 135790)
does any one have a copy of last years Core 1 exam?
And also Core2 May paper?
thanks
9. Where do I get the specimen paper?
10. am i the only one who gets a bit worried when you finish a question and theres like 3 pages of space left? they give you wayyy to much space in the exam booklets and it always leaves me paranoid that i didnt do enough

it seems like everytime i learn one thing and get it right in a past paper, i lose something else, i never get above 70 marks, and normally i get around 85%. its like someone doesnt want me to get higher that 85% :O
11. C1 June 2010 QP and MS here, for last minute test

Plus C2, if needed.
Attached Images
12. C1 June 2010 QP.pdf (284.6 KB, 165 views)
13. C1 June 2010 MS.pdf (237.0 KB, 155 views)
14. C2 June 2010 QP.pdf (248.0 KB, 98 views)
15. C2 June 2010 MS.pdf (217.6 KB, 93 views)
16. im so not looking forward to tomorrow, i have c1 then c2 :'(
does anyone else find c2 easier than c1? i always make some silly mistake on c1 or get confused by the question, i dont with c2 and i prefer the questions.
17. I found something called SetA: practise paper 1-5 ( numbered from 1 to 5)
they contian some large numbers
is that included ?
18. Don't forget to revise prove of sum of the first n terms in arithmetic series (just in case )

1/2n [2a+(n-1)d]
19. (Original post by Drewno)
Don't forget to revise prove of sum of the first n terms in arithmetic series (just in case )

1/2n [2a+(n-1)d]
do we have to know how to prove 1/2n [a+L] where L is the last term?
20. (Original post by cylon)
do we have to know how to prove 1/2n [a+L] where L is the last term?
No, I fail to see how you would use this any way.
you need to know 1/n(2a+(n-1)d)
and 1/2(a+(n-1)d)
21. what is the C1 proof that i have to learn???
22. (Original post by chaosdestro0)
No, I fail to see how you would use this any way.
you need to know 1/n(2a+(n-1)d)
and 1/2(a+(n-1)d)
Oh thanks ,
and its easy by the way if you have the first and last term you can easliy use it, and even its way eaiser.
23. (Original post by cylon)
Oh thanks ,
and its easy by the way if you have the first and last term you can easliy use it, and even its way eaiser.
Very small chance you will need to know the proof of sum of series.
I am just trying to find it right now.
Edit:
Arithmetic proof

Sn = a + (a + d) + (a + 2d) + (a + 3d) + ..... (a + (n-2)d) + (a + (n-1)d)
Reversed Sn = (a + (n-1)d) + (a + (n-2)d) .... (a+ 3d) + (a+2d) + (a + d) + a

2Sn = 2a + (n - 1)d + 2a + (n-1)d + 2a(n-1)d

2sn = n[2a + (n-1)d]
Sn = n/2[2a + (n-1)d]
24. (Original post by cylon)
do we have to know how to prove 1/2n [a+L] where L is the last term?
The last term of the series is always a+(n-1)d
So,

Sn=n/2(2a+(n-1)d), can also be written as Sn=n/2(a+a+(n-1)d)
=n/2(a+L)

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